Chapter 24, Problem 43QP

Interpretation Introduction

Interpretation:

The molar mass and molecular formula of white phosphorus are to be determined.

Concept introduction:

The formula for depression in freezing point is given as follows:

$\Delta T_b=T_b-T_b{}^o={\text{K}}_{\text{b}}\times m$

Here, $T_b{}^o$

is the boiling point of pure solvent, $m$ is the molality of the solution, and $T_b$ is the boiling point of solvent.

Molality is the number of moles of solute dissolved in 1kg of solvent.

The molality of the solution is given by the expression as follows: $m=\frac{\text{Given}\text{mass}}{\text{Molar}\text{mass}}\times \frac{1}{\text{Mass}\text{of}\text{solvent}\text{(Kg)}}$