Bundle: Chemistry & Chemical Reactivity, Loose-Leaf Version, 9th + OWLv2, 4 terms (24 Months) Printed Access Card
9th Edition
ISBN: 9781305367425
Author: John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher: Cengage Learning
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Chapter 24, Problem 37SCQ
Interpretation Introduction
Interpretation:
The achiral amino acid from the
Concept introduction: A molecule is achiral if it is superimposible on its mirror image.
An achiral carbon atom is substituted by two same groups.
Chiral carbon forms four different bonds. A molecule is known as chiral if it is not superimposible on its mirror image. Some chiral molecule are known by their lack of plane of symmetry and centre of symmetry.
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Learning Goal:
This question reviews the format for writing an element's written symbol. Recall that written symbols have a particular format. Written symbols use a form like this:
35 Cl
17
In this form the mass number, 35, is a stacked superscript. The atomic number, 17, is a stacked subscript. "CI" is the chemical symbol for the element chlorine. A general way to show this form is:
It is also correct to write symbols by leaving off the atomic number, as in the following form:
atomic number
mass number Symbol
35 Cl or
mass number Symbol
This is because if you write the element symbol, such as Cl, you know the atomic number is 17 from that symbol. Remember that the atomic number, or number of protons in the nucleus, is what defines the element. Thus, if 17 protons
are in the nucleus, the element can only be chlorine. Sometimes you will only see 35 C1, where the atomic number is not written.
Watch this video to review the format for written symbols.
In the following table each column…
need help please and thanks dont understand only need help with C-F
Learning Goal:
As discussed during the lecture, the enzyme HIV-1 reverse transcriptae (HIV-RT) plays a significant role for the HIV virus and is an important drug target. Assume a concentration [E] of 2.00 µM (i.e. 2.00 x 10-6 mol/l) for HIV-RT. Two potential drug molecules, D1 and D2, were identified, which form stable complexes with the HIV-RT.
The dissociation constant of the complex ED1 formed by HIV-RT and the drug D1 is 1.00 nM (i.e. 1.00 x 10-9). The dissociation constant of the complex ED2 formed by HIV-RT and the drug D2 is 100 nM (i.e. 1.00 x 10-7).
Part A - Difference in binding free eenergies
Compute the difference in binding free energy (at a physiological temperature T=310 K) for the complexes. Provide the difference as a positive numerical expression with three significant figures in kJ/mol.
The margin of error is 2%.
Part B - Compare difference in free energy to the thermal…
need help please and thanks dont understand only need help with C-F
Learning Goal:
As discussed during the lecture, the enzyme HIV-1 reverse transcriptae (HIV-RT) plays a significant role for the HIV virus and is an important drug target. Assume a concentration [E] of 2.00 µM (i.e. 2.00 x 10-6 mol/l) for HIV-RT. Two potential drug molecules, D1 and D2, were identified, which form stable complexes with the HIV-RT.
The dissociation constant of the complex ED1 formed by HIV-RT and the drug D1 is 1.00 nM (i.e. 1.00 x 10-9). The dissociation constant of the complex ED2 formed by HIV-RT and the drug D2 is 100 nM (i.e. 1.00 x 10-7).
Part A - Difference in binding free eenergies
Compute the difference in binding free energy (at a physiological temperature T=310 K) for the complexes. Provide the difference as a positive numerical expression with three significant figures in kJ/mol.
The margin of error is 2%.
Part B - Compare difference in free energy to the thermal…
Chapter 24 Solutions
Bundle: Chemistry & Chemical Reactivity, Loose-Leaf Version, 9th + OWLv2, 4 terms (24 Months) Printed Access Card
Ch. 24.1 - Draw the Lewis structure for the tripeptide...Ch. 24.1 - Prob. 1RCCh. 24.1 - Prob. 2RCCh. 24.1 - Prob. 3RCCh. 24.2 - Prob. 1RCCh. 24.2 - Prob. 2RCCh. 24.2 - Prob. 3RCCh. 24.3 - What is the sequence of the strand of DNA...Ch. 24.3 - Prob. 2CYUCh. 24.3 - 1. Which breaks down more quickly in an aqueous...
Ch. 24.3 - Prob. 2RCCh. 24.3 - 3. Which amino acid is selected by the mRNA codon...Ch. 24.3 - Kynamro has the hydrogen bonding sequence:...Ch. 24.3 - The formula of Kynamro is...Ch. 24.3 - Prob. 3QCh. 24.4 - 1. Which of the following is not an example of a...Ch. 24.4 - Prob. 2RCCh. 24.5 - Prob. 1RCCh. 24.5 - Prob. 2RCCh. 24.5 - Prob. 1QCh. 24.5 - Prob. 2QCh. 24.5 - Prob. 3QCh. 24 - (a) Draw the Lewis structure for the amino acid...Ch. 24 - (a) Draw the Lewis structure for the amino acid...Ch. 24 - Prob. 3PSCh. 24 - Prob. 4PSCh. 24 - Draw Lewis structures for the two dipeptides that...Ch. 24 - Do the amino acid sequences: valine-asparagine and...Ch. 24 - Draw the Lewis structure for the tripeptide...Ch. 24 - Prob. 8PSCh. 24 - Prob. 9PSCh. 24 - Prob. 10PSCh. 24 - Prob. 11PSCh. 24 - Prob. 12PSCh. 24 - (a) Draw the structural formula for the sugar...Ch. 24 - (a) Draw the structural formula for the sugar -D-2...Ch. 24 - Prob. 15PSCh. 24 - Prob. 16PSCh. 24 - Given the following nucleotide sequence in DNA:...Ch. 24 - Given the following nucleotide sequence in DNA: 5'...Ch. 24 - Prob. 19PSCh. 24 - If a drop of oleic acid is added to a dish of...Ch. 24 - What structure do all steroids have in common?Ch. 24 - Prob. 22PSCh. 24 - Prob. 23PSCh. 24 - The chemical equation for the fermentation of...Ch. 24 - Prob. 25PSCh. 24 - Prob. 26PSCh. 24 - Prob. 27GQCh. 24 - Prob. 28GQCh. 24 - Prob. 29GQCh. 24 - Prob. 30GQCh. 24 - Prob. 31GQCh. 24 - There are 41 = 4 mononucleotides of DNA, there are...Ch. 24 - Prob. 33GQCh. 24 - The first step of the metabolic process known as...Ch. 24 - Prob. 35ILCh. 24 - Insulin is a protein important in the metabolism...Ch. 24 - Prob. 37SCQCh. 24 - Prob. 38SCQCh. 24 - Do the DNA sequences ATGC and CGTA represent the...Ch. 24 - Prob. 41SCQCh. 24 - Which of the following statements is/are true? (a)...
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