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Consider a closed triangular box resting within a horizontal electric field of magnitude E = 8.02  104 N/C as shown in the figure below. A closed right triangular box with its vertical side on the left and downward slope on the right rests within a horizontal electric field vector E that points from left to right. The box has a height of 10.0 cm and a depth of 30.0 cm. The downward slope of the box makes an angle of 60 degrees with the vertical. (a) Calculate the electric flux through the vertical rectangular surface of the box. kN · m2/C(b) Calculate the electric flux through the slanted surface of the box. kN · m2/C(c) Calculate the electric flux through the entire surface of the box. kN · m2/C

Chapter 24 Solutions

Modified Mastering Physics without Pearson eText-- Instant Access -- for Physics for Scientists & Engineers with Modern Physics

Ch. 24 - Suppose three identical capacitors are connected...Ch. 24 - A large copper sheet of thickness is placed...Ch. 24 - The parallel plates of an isolated capacitor carry...Ch. 24 - If the voltage across a capacitor is doubled, the...Ch. 24 - An isolated charged capacitor has horizontal...Ch. 24 - Suppose a battery remains connected to the...Ch. 24 - How does the energy stored in a capacitor change...Ch. 24 - For dielectrics consisting of polar molecules, how...Ch. 24 - A dielectric is pulled out from between the plates...Ch. 24 - We have seen that the capacitance C depends on the...Ch. 24 - What value might we assign to the dielectric...Ch. 24 - Prob. 5MCQCh. 24 - Prob. 6MCQCh. 24 - Prob. 9MCQCh. 24 - Prob. 11MCQCh. 24 - Prob. 12MCQCh. 24 - Prob. 13MCQCh. 24 - Prob. 1PCh. 24 - Prob. 2PCh. 24 - Prob. 3PCh. 24 - Prob. 4PCh. 24 - Prob. 5PCh. 24 - Prob. 6PCh. 24 - Prob. 7PCh. 24 - Prob. 8PCh. 24 - Prob. 9PCh. 24 - Prob. 10PCh. 24 - Prob. 11PCh. 24 - Prob. 12PCh. 24 - Prob. 13PCh. 24 - Prob. 14PCh. 24 - Prob. 15PCh. 24 - Prob. 16PCh. 24 - Prob. 17PCh. 24 - Prob. 18PCh. 24 - Prob. 19PCh. 24 - Prob. 20PCh. 24 - Prob. 21PCh. 24 - Prob. 22PCh. 24 - Prob. 24PCh. 24 - Prob. 25PCh. 24 - Prob. 26PCh. 24 - Prob. 27PCh. 24 - Prob. 28PCh. 24 - Prob. 29PCh. 24 - Prob. 31PCh. 24 - Prob. 32PCh. 24 - Prob. 33PCh. 24 - Prob. 34PCh. 24 - Prob. 35PCh. 24 - Prob. 36PCh. 24 - Prob. 37PCh. 24 - Prob. 38PCh. 24 - Prob. 39PCh. 24 - Prob. 40PCh. 24 - Prob. 41PCh. 24 - Prob. 42PCh. 24 - Prob. 43PCh. 24 - Prob. 44PCh. 24 - Prob. 45PCh. 24 - Prob. 49PCh. 24 - Prob. 53PCh. 24 - Prob. 54PCh. 24 - Prob. 57PCh. 24 - Prob. 58PCh. 24 - (II) Two different dielectrics fill the space...Ch. 24 - (II) Repeat Problem 60 (Fig. 2431) but assume the...Ch. 24 - Prob. 63PCh. 24 - Prob. 76GPCh. 24 - Prob. 84GPCh. 24 - Prob. 87GP
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