Answer y ( x ) = − 16 x 2 + 6 x + 22. Water-skier 5 feet above the water 16 x 2 − 6 x − 17 = 0. Skier in the air x = 1.235 s Explanation Given information: The table shows the heights y of a competitive water-skier x seconds after jumping off a ramp Calculation : y ( 0 ) y ( 0.25 ) y ( 0.75 ) y ( 1 ) y ( 1.1 ) 22 22.5 17.5 12 9.24 0.5 -1.5 -3.5 -5.5 -2 -2 -2 Because second differences are constant so we can modal the data with a quadratic function . y ( x ) = a x 2 + b x + c . .......(1) y ( 0 ) = a × ( 0 ) 2 + b × 0 + c . 22 = 0 + 0 + c . c = 22. y ( 1 ) = a × ( 1 ) 2 + b × 1 + c . 12 = a + b + 22. a + b = − 10......... ( 2 ) y ( 0.25 ) = a × ( 0.25 ) 2 + b × ( 0.25 ) + c . 22.5 = ( 1 / 16 ) a + ( 1 / 4 ) b + 22. ( 1 / 16 ) a + ( 1 / 4 ) b = 0.5....... ( 3 ) solving (2) and (3) . a = − 16 , b = 6 , c = 22. Putting a = − 16 , b = 6 , c = 22 in equation ( 1 ) y ( x ) = − 16 x 2 + 6 x + 22. Water-skier 5 feet above the water, 5 = − 16 x 2 + 6 x + 22 . 16 x 2 − 6 x − 17 = 0. x = 1.235 s .

Big Ideas Math A Bridge To Success Algebra 2: Student Edition 2015

1st Edition

ISBN: 9781680331165

Author: HOUGHTON MIFFLIN HARCOURT

Publisher: Houghton Mifflin Harcourt

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Question

Chapter 2.4, Problem 35E

To determine

Write a function that models the height of the water-skier over time. When is the water-skier 5 feet above the water? How long is the skier in the air.

Expert Solution & Answer

Answer to Problem 35E

y(x)=−16x2+6x+22.

Water-skier 5 feet above the water 16x2−6x−17=0.

Skier in the air x=1.235s

Explanation of Solution

Given information: The table shows the heights y of a competitive water-skier x seconds after jumping off a ramp

Big Ideas Math A Bridge To Success Algebra 2: Student Edition 2015, Chapter 2.4, Problem 35E

Calculation :

y(0)		y(0.25)		y(0.75)		y(1)		y(1.1)
22		22.5		17.5		12		9.24
	0.5		-1.5		-3.5		-5.5
		-2		-2		-2

Because second differences are constant so we can modal the data with a quadratic function .

y(x)=ax2+bx+c........(1)

y(0)=a× (0) 2 +b×0+c.22=0+0+c.c=22. y(1)=a× (1) 2 +b×1+c.12=a+b+22.a+b=−10.........(2) y(0.25)=a× (0.25) 2 +b×(0.25)+c.22.5=(1/16)a+(1/4)b+22.(1/16)a+(1/4)b=0.5.......(3)solving (2) and (3) .a=−16,b=6,c=22.Putting a=−16,b=6,c=22in equation (1)y(x)=−16x2+6x+22.

Water-skier 5 feet above the water,

5=−16x2+6x+22 .16x2−6x−17=0.x=1.235s.

Chapter 2.4, Problem 34E

Chapter 2.4, Problem 36E

Chapter 2 Solutions

Big Ideas Math A Bridge To Success Algebra 2: Student Edition 2015

Ch. 2.1 - Prob. 1E Ch. 2.1 - Prob. 2E Ch. 2.1 - Prob. 3E Ch. 2.1 - Prob. 4E Ch. 2.1 - Prob. 5E Ch. 2.1 - Prob. 6E Ch. 2.1 - Prob. 7E Ch. 2.1 - Prob. 8E Ch. 2.1 - Prob. 9E Ch. 2.1 - Prob. 10E

Ch. 2.1 - Prob. 11E Ch. 2.1 - Prob. 12E Ch. 2.1 - Prob. 13E Ch. 2.1 - Prob. 14E Ch. 2.1 - Prob. 15E Ch. 2.1 - Prob. 16E Ch. 2.1 - Prob. 17E Ch. 2.1 - Prob. 18E Ch. 2.1 - Prob. 19E Ch. 2.1 - Prob. 20E Ch. 2.1 - Prob. 21E Ch. 2.1 - Prob. 22E Ch. 2.1 - Prob. 23E Ch. 2.1 - Prob. 24E Ch. 2.1 - Prob. 25E Ch. 2.1 - Prob. 26E Ch. 2.1 - Prob. 27E Ch. 2.1 - Prob. 28E Ch. 2.1 - Prob. 29E Ch. 2.1 - Prob. 30E Ch. 2.1 - Prob. 31E Ch. 2.1 - Prob. 32E Ch. 2.1 - Prob. 33E Ch. 2.1 - Prob. 34E Ch. 2.1 - Prob. 35E Ch. 2.1 - Prob. 36E Ch. 2.1 - Prob. 37E Ch. 2.1 - Prob. 38E Ch. 2.1 - Prob. 39E Ch. 2.1 - Prob. 40E Ch. 2.1 - Prob. 41E Ch. 2.1 - Prob. 42E Ch. 2.1 - Prob. 43E Ch. 2.1 - Prob. 44E Ch. 2.1 - Prob. 45E Ch. 2.1 - Prob. 46E Ch. 2.1 - Prob. 47E Ch. 2.1 - Prob. 48E Ch. 2.1 - Prob. 49E Ch. 2.1 - Prob. 50E Ch. 2.1 - Prob. 51E Ch. 2.1 - Prob. 52E Ch. 2.2 - Prob. 1E Ch. 2.2 - Prob. 2E Ch. 2.2 - Prob. 3E Ch. 2.2 - Prob. 4E Ch. 2.2 - Prob. 5E Ch. 2.2 - Prob. 6E Ch. 2.2 - Prob. 7E Ch. 2.2 - Prob. 8E Ch. 2.2 - 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