Interpretation:
The incorrect statement about significance of zeros in recorded measurement has to be chosen from the given options.
Concept Introduction:
Whenever a measurement is made, the significant figures in the measured quantity give the actual measurement. For this the significant figures should be recognized first. The significant figures may be non-zero digit and zero digit. But Zero may be or may not be a significant figure. It depends on where the zero appears. Leading zeros in the front of any number are never significant. Zeros between the numbers are significant. Zeros appearing at the last (trailing zeros) are significant if a decimal point is there in the number.
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Chapter 2 Solutions
General, Organic, and Biological Chemistry Seventh Edition
- 5. Use the MS data to answer the questions on the next page. 14.0 1.4 15.0 8.1 100- MS-IW-5644 26.0 2.8 27.0 6.7 28.0 1.8 29.0 80 4.4 38.0 1.0 39.0 1.5 41.0 1.2 42.0 11.2 43.0 100.0 44.0 4.3 79.0 1.9 80.0 2.6 Relative Intensity 40 81.0 1.9 82.0 2.5 93.0 8.7 20- 95.0 8.2 121.0 2.0 123.0 2.0 136.0 11.8 0 138.0 11.5 20 40 8. 60 a. Br - 0 80 100 120 140 160 180 200 220 m/z Identify the m/z of the base peak and molecular ion. 2 b. Draw structures for each of the following fragments (include electrons and charges): 43.0, 93.0, 95.0, 136.0, and 138.0 m/z. C. Draw a reasonable a-fragmentation mechanism for the fragmentation of the molecular ion to fragment 43.0 m/z. Be sure to include all electrons and formal charges. 6. Using the values provided in Appendix E of your lab manual, calculate the monoisotopic mass for the pyridinium ion (CsH6N) and show your work.arrow_forwardNonearrow_forwardStereochemistry: Three possible answers- diastereomers, enantiomers OH CH₂OH I -c=0 21108 1101 41745 HOR CH₂OH IL Но CH₂OH TIL a. Compounds I and III have this relationship with each other: enantiomers b. Compounds II and IV have this relationship with each other: c. Compounds I and II have this relationship with each other: d. *Draw one structure that is a stereoisomer of II, but neither a diastereomer nor an enantiomer. (more than one correct answer)arrow_forward
- Don't used Ai solutionarrow_forwardDon't used Ai solutionarrow_forwardIn mass spectrometry, alpha cleavages are common in molecules with heteroatoms. Draw the two daughter ions that would be observed in the mass spectrum resulting from an alpha cleavage of this molecule. + NH2 Q Draw Fragment with m/z of 72arrow_forward
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