(a) Explanation Formula used: The value of increment is calculated as Δ y = f ( x + Δ x ) − f ( x ) . Calculation: Substitute, x = 3 in f ( x ) = 3 x 2 − x . f ( x ) = 3 x 2 − x f ( 3 ) = 3 ( 3 ) 2 − ( 3 ) = 27 − 3 = 24 Then increment in function f ( x + Δ x ) = 3 ( x + Δ x ) 2 − ( x + Δ x ) . Substitute, x = 3 and Δ x = 0.1 in f ( x + Δ x ) = 3 ( x + Δ x ) 2 − ( x + Δ x ) (b) To determine The differential. If the function is y = 3 x 2 − x , for x = 3 , and Δ x = 0.1 . (c) To determine The difference of increment and differential. If the function is y = 3 x 2 − x , for x = 3 , and Δ x = 0.1 .

Pearson eText for Basic Technical Mathematics with Calculus -- Instant Access (Pearson+)

11th Edition

ISBN: 9780137554843

Author: Allyn Washington, Richard Evans

Publisher: PEARSON+

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Chapter 24, Problem 2PT

(a)

To determine

The increment. If the function is y=3x2−x, for x=3, and Δx=0.1.

(b)

To determine

The differential. If the function is y=3x2−x, for x=3, and Δx=0.1.

(c)

To determine

The difference of increment and differential. If the function is y=3x2−x, for x=3, and Δx=0.1.

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Chapter 24, Problem 1PT

Chapter 24, Problem 3PT

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Chapter 24 Solutions

Pearson eText for Basic Technical Mathematics with Calculus -- Instant Access (Pearson+)

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The increment. If the function is y = 3 x 2 − x , for x = 3 , and Δ x = 0.1 .

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The increment. If the function is y=3x2−x, for x=3, and Δx=0.1.

The differential. If the function is y=3x2−x, for x=3, and Δx=0.1.

The difference of increment and differential. If the function is y=3x2−x, for x=3, and Δx=0.1.

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Chapter 24 Solutions