Chemical Principles in the Laboratory
Chemical Principles in the Laboratory
11th Edition
ISBN: 9781305264434
Author: Emil Slowinski, Wayne C. Wolsey, Robert Rossi
Publisher: Brooks Cole
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Chapter 24, Problem 2ASA

In an acid-base titration, 21.16 mL of an NaOH solution are needed to neutralize 20.04 mL of a 0.0997 M HCl solution. To find the molarity of the NaOH solution, we can use the following procedure:

  1. First note the value of MH+ in the HCl solution. ____________M
  2. Find MOH- in the NaOH solution. (Use Eq.3.) ____________M
  3. Obtain MNaOH from MOH. ____________M

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Please help in solving e-f of question. Thanks
can someone explain what I did wrong. the correct answer is circled for number one, but I got 2.19 as the poh, not the pH
A 16.8 mL solution of 0.100 mol L-1 CH3COOH is titrated using 0.150 mol L-1 NaOH. What is the pH of the solution after 5.66 mL of the NaOH solution is added? Express your answer to 2 decimal places. Remember you can find KA and/or KB values in your textbook in chapter 15. They are also posted on eClass. Answer:
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Acid-Base Titration | Acids, Bases & Alkalis | Chemistry | FuseSchool; Author: FuseSchool - Global Education;https://www.youtube.com/watch?v=yFqx6_Y6c2M;License: Standard YouTube License, CC-BY