Masteringchemistry with Pearson Etext -- Standalone Access Card -- For Chemistry
Masteringchemistry with Pearson Etext -- Standalone Access Card -- For Chemistry
3rd Edition
ISBN: 9780321806383
Author: Nivaldo J. Tro
Publisher: PEARSON
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Chapter 24, Problem 28E
Interpretation Introduction

Interpretation: The formula and name of each of the given complex ion is to be written.

Concept Introduction:

• For naming the coordination compounds, the following procedure is to be followed:

1. The cation and anion are to be identified and the simple ion is to be named first.

2. Ligands are to be named and listed in the alphabetical order before the name of the metal cation.

3. A prefix is to be used to indicate the number of ligands (when there is more than one ligand of similar type is present like di for 2, tri for 3, tetra for 4, penta for 5, hexa for 6). If the ligand name already contains a prefix like ethylenediamine, a parentheses around the ligand is to be placed and then, prefix like bis-(2), tris-(4) or tetrakis-(4) is to be used to indicate the number.

4. The metal is to be named:

• If the complex ion is a cation, the name of the metal followed by the oxidation state written in roman numerals should be used like for Co3+ is written as cobalt (III).

• If the complex ion is an anion, the ending of the metal is dropped and ‘-ate’ is added followed by the oxidation state written in Roman numerals. For example: Pt2+ is platinate(II).

• The entire name of the complex ion is written by listing the ligands first followed by the metal.

• While writing the formula for the complex ion, first write the symbol for the metal followed by the neutral molecules and then anions. If more than one anion or neutral molecule acts as a ligand, they should be listed in an alphabetical order based on the chemical symbol.

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Chapter 24 Solutions

Masteringchemistry with Pearson Etext -- Standalone Access Card -- For Chemistry

Ch. 24 - Prob. 1ECh. 24 - Prob. 2ECh. 24 - 3. Why is the +2 oxidation state so common for...Ch. 24 - 4. Explain why atomic radii of elements in the...Ch. 24 - 5. Gold is the most electronegative transition...Ch. 24 - Prob. 6ECh. 24 - Prob. 7ECh. 24 - Prob. 8ECh. 24 - Prob. 9ECh. 24 - Prob. 10ECh. 24 - Prob. 11ECh. 24 - Prob. 12ECh. 24 - Prob. 13ECh. 24 - Prob. 14ECh. 24 - Prob. 15ECh. 24 - Prob. 16ECh. 24 - 17. Write the ground state electron configuration...Ch. 24 - 18. Write the ground state electron configuration...Ch. 24 - Prob. 19ECh. 24 - Prob. 20ECh. 24 - Prob. 21ECh. 24 - Prob. 22ECh. 24 - Prob. 23ECh. 24 - Prob. 24ECh. 24 - Prob. 25ECh. 24 - Prob. 26ECh. 24 - Prob. 27ECh. 24 - Prob. 28ECh. 24 - Prob. 29ECh. 24 - Prob. 30ECh. 24 - Prob. 31ECh. 24 - Prob. 32ECh. 24 - Prob. 33ECh. 24 - Prob. 34ECh. 24 - Prob. 35ECh. 24 - Prob. 36ECh. 24 - Prob. 37ECh. 24 - Prob. 38ECh. 24 - Prob. 39ECh. 24 - Prob. 40ECh. 24 - Prob. 41ECh. 24 - Prob. 42ECh. 24 - Prob. 43ECh. 24 - Prob. 44ECh. 24 - Prob. 45ECh. 24 - Prob. 46ECh. 24 - Prob. 47ECh. 24 - Prob. 48ECh. 24 - Prob. 49ECh. 24 - Prob. 50ECh. 24 - Prob. 51ECh. 24 - Prob. 52ECh. 24 - Prob. 53ECh. 24 - Prob. 54ECh. 24 - Prob. 55ECh. 24 - Prob. 56ECh. 24 - 57. Recall from Chapter 8 that Cr and Cu are...Ch. 24 - 58. Most of the second row transition metals do...Ch. 24 - Prob. 59ECh. 24 - Prob. 60ECh. 24 - Prob. 61ECh. 24 - Prob. 62ECh. 24 - Prob. 63ECh. 24 - Prob. 64ECh. 24 - Prob. 65ECh. 24 - Prob. 66ECh. 24 - Prob. 67ECh. 24 - Prob. 68ECh. 24 - 69. When a solution of PtCl2 reacts with the...Ch. 24 - Prob. 70ECh. 24 - Prob. 71ECh. 24 - Prob. 72ECh. 24 - Prob. 73ECh. 24 - Prob. 74ECh. 24 - Prob. 75ECh. 24 - Prob. 76ECh. 24 - Prob. 77ECh. 24 - Prob. 78ECh. 24 - 79. Which element has the higher ionization...Ch. 24 - Prob. 80E
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