Mathematics For Machine Technology
Mathematics For Machine Technology
8th Edition
ISBN: 9781337798310
Author: Peterson, John.
Publisher: Cengage Learning,
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Chapter 24, Problem 25A
To determine

(a)

The percent increase in temperature.

Expert Solution
Check Mark

Answer to Problem 25A

Percentage increase in temperature is 13%.

Explanation of Solution

Given information:

Initial temperature of heated steel is 13000 F and color is dark red. Color changes to dull cherry-red at approximately 14700.

Calculation:

As per the given information initial temperature is 13000 F and color is dark red. Color changes to dull cherry-red at approximately 14700.

So, change in temperature =(1470013000)=1700F.

Need to find the percentage change in the temperature.

As we know the proportion to find percentage is given as

  PB=R100   where, P=percentage, B= base and R=rate

Here, initial temperature will be base B=13000F, percentage will be P=1700F.

Putting these value in standard proportion,

  PB=R1001701300=R100                           {Put B=1300 and P=170}Applying cross multiplication,1300R=170×100R=170×1001300R=13.07692R=13                                   {Rounding off to nearest whole number}

Hence, percentage increase in temperature is 13%.

To determine

(b)

The percent increase in temperature.

Expert Solution
Check Mark

Answer to Problem 25A

Percentage increase in temperature is 69%.

Explanation of Solution

Given information:

Initial temperature of heated steel is 13000 F and color is dark red. Color changes to orange yellow at approximately 22000.

Calculation:

As per the given information initial temperature is 13000 F and color is dark red. Color changes to orange yellow at approximately 22000.

So, change in temperature =(2200013000)=9000F.

Need to find the percentage change in the temperature.

As we know the proportion to find percentage is given as

  PB=R100   where, P=percentage, B= base and R=rate

Here, initial temperature will be base B=13000F, percentage will be P=9000F.

Putting these value in standard proportion,

  PB=R1009001300=R100                           {Put B=1300 and P=900}Applying cross multiplication,1300R=900×100R=900×1001300R=69.23076R=69                                   {Rounding off to nearest whole number}

Hence, percentage increase in temperature is 69%.

To determine

(c)

The percent increase in temperature.

Expert Solution
Check Mark

Answer to Problem 25A

Percentage increase in temperature is 110%.

Explanation of Solution

Given information:

Initial temperature of heated steel is 13000 F and color is dark red. Color changes to brilliant white at approximately 27300.

Calculation:

As per the given information initial temperature is 13000 F and color is dark red. Color changes to brilliant white at approximately 27300.

So, change in temperature =(2730013000)=14300F.

Need to find the percentage change in the temperature.

As we know the proportion to find percentage is given as

  PB=R100   where, P=percentage, B= base and R=rate

Here, initial temperature will be base B=13000F, percentage will be P=14300F.

Putting these value in standard proportion,

  PB=R10014301300=R100                           {Put B=1300 and P=1430}Applying cross multiplication,1300R=1430×100R=1430×1001300R=110R=110                                   {Rounding off to nearest whole number}

Hence, percentage increase in temperature is 110%.

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Chapter 24 Solutions

Mathematics For Machine Technology

Ch. 24 - Finding Percentage, Percent, and Base in Practical...Ch. 24 - Finding Percentage, Percent, and Base in Practical...Ch. 24 - Finding Percentage, Percent, and Base in Practical...Ch. 24 - Finding Percentage, Percent, and Base in Practical...Ch. 24 - Finding Percentage, Percent, and Base in Practical...Ch. 24 - Finding Percentage, Percent, and Base in Practical...Ch. 24 - Prob. 17ACh. 24 - Finding Percentage, Percent, and Base in Practical...Ch. 24 - Finding Percentage, Percent, and Base in Practical...Ch. 24 - Finding Percentage, Percent, and Base in Practical...Ch. 24 - Prob. 21ACh. 24 - Prob. 22ACh. 24 - Finding Percentage, Percent, and Base in Practical...Ch. 24 - Finding Percentage, Percent, and Base in Practical...Ch. 24 - Prob. 25ACh. 24 - Prob. 26ACh. 24 - Finding Percentage, Percent, and Base in Practical...Ch. 24 - Finding Percentage, Percent, and Base in Practical...Ch. 24 - Finding Percentage, Percent, and Base in Practical...Ch. 24 - Finding Percentage, Percent, and Base in Practical...Ch. 24 - Prob. 31ACh. 24 - A manufacturer estimates that 15,500 pieces per...Ch. 24 - The average percent defective product of a...Ch. 24 - Prob. 34ACh. 24 - Prob. 35ACh. 24 - The cost of one dozen cutters is listed as $525. A...Ch. 24 - A manufacturer's production this week is 3620...Ch. 24 - Two machines are used to produce the same product....Ch. 24 - Allowing for scrap, a firm produced 1890 pieces....Ch. 24 - A manufacturing company receives $122,000 upon the...Ch. 24 - Prob. 41A
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