Number of G r a y (Dose) received by 70 kg person has to be determined using the given data. Concept Introduction: Radiation Dose is the dose quantity that explains the effects of ionizing radiation. It describes the quantity of radiation energy that is absorbed by a matter. D o s e = E n e r g y ( J o u l e s ) W e i g h t ( k g ) The units commonly used to measure dose are gray ( G y ) and rad . 1 Gy = 1 J/kg 1 rad = 0 .01 J/kg = 0 .01 Gy

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Answer 1

Question

Chapter 24, Problem 24.62P

(a)

Interpretation Introduction

Interpretation:

Number of Gray (Dose) received by 70 kg person has to be determined using the given data.

Concept Introduction:

Radiation Dose is the dose quantity that explains the effects of ionizing radiation. It describes the quantity of radiation energy that is absorbed by a matter.

Dose = Energy(Joules)Weight(kg)

The units commonly used to measure dose are gray (Gy) and rad.

1 Gy = 1 J/kg1 rad = 0.01 J/kg = 0.01 Gy

(a)

Expert Solution

Explanation of Solution

Given information is shown below,

No. of β− particle = 6.0×105Mass of person = 70 kgEnergy of each β− particle = 8.74×10−14 J

Energy absorbed is determined as follows,

Energy(J) = (6.0×105 β−)(8.74×10−14 J/β−)= 5.244×10−8 J

Dose (Gray) received by 95 kg human is calculated as given,

Dose = (5.244×10−8 J70 kg)(1 rad0.01 J/kg)(0.01 Gy1 rad)= 7.49×10−10 Gy

Dose (Gray) received by 70 kg human is 7.49×10-10 Gy.

(b)

Interpretation Introduction

Interpretation:

Number of mrem received by 70 kg person has to be determined using the given data.

Concept Introduction:

Radiation Dose is the dose quantity that explains the effects of ionizing radiation. It describes the quantity of radiation energy that is absorbed by a matter.

The units commonly used to measure dose are gray (Gy) and rad.

1 Gy = 1 J/kg1 rad = 0.01 J/kg = 0.01 Gy

The tissue damage caused by the radiation depends on the exposure time, strength of the radiation and tissue type. Tissue damage can be determined by multiplying dose that is absorbed with RBE (Relative Biological Effectiveness).

The two units used to measure amount of damaged tissue in a person is rem(Roentgen Equivalent for Man) and sievert(Sv.)

No. of rem = no. of rads×RBE1 Sv = 100 rem

(b)

Expert Solution

Explanation of Solution

Given information is shown below,

No. of β− particle = 6.0×105Mass of person = 70 kgEnergy of each β− particle = 8.74×10−14 JRBE = 1.0

Energy absorbed is determined as follows,

Energy(J) = (6.0×105 β−)(8.74×10−14 J/β−)= 5.244×10−8 J

Dose (rad) received is calculated as given,

Dose = (5.244×10−8 J70 kg)(1 rad0.01 J/kg)= 7.49×10−8 rad

Dose (rad) received by 70 kg human is 7.49×10−8 rad.

Number of mrem received by 70 kg person is determined as shown below,

No. of rem = no. of rads×RBE= (7.49×10−8 rad)(1.0)(1 mrem10−3 rem)= 7.49×10−5 mrem

Number of mrem received by 70 kg person is 7.49×10−5 mrem.

(c)

Interpretation Introduction

Interpretation:

Number of sieverts (Sv) received by 70 kg person has to be determined using the given data.

Concept Introduction:

Radiation Dose is the dose quantity that explains the effects of ionizing radiation. It describes the quantity of radiation energy that is absorbed by a matter.

The units commonly used to measure dose are gray (Gy) and rad.

1 Gy = 1 J/kg1 rad = 0.01 J/kg = 0.01 Gy

The tissue damage caused by the radiation depends on the exposure time, strength of the radiation and tissue type. Tissue damage can be determined by multiplying dose that is absorbed with RBE (Relative Biological Effectiveness).

The two units used to measure amount of damaged tissue in a person is rem(Roentgen Equivalent for Man) and sievert(Sv.)

No. of rem = no. of rads×RBE1 Sv = 100 rem

(c)

Expert Solution

Explanation of Solution

Given information is shown below,

No. of β− particle = 6.0×105Mass of person = 70 kgEnergy of each β− particle = 8.74×10−14 JRBE = 1.0

Energy absorbed is determined as follows,

Energy(J) = (6.0×105 β−)(8.74×10−14 J/β−)= 5.244×10−8 J

Dose (rad) received is calculated as given,

Dose = (5.244×10−8 J70 kg)(1 rad0.01 J/kg)= 7.49×10−8 rad

Dose (rad) received is 7.49×10−8 rad.

Number of Sv received by 70 kg person is determined as shown below,

No. of rem = no. of rads×RBE= (7.49×10−8 rad)(1.0)= 7.49×10−8 remNo. of Sv = 7.49×10−8 rem(0.01 Sv1 rem)= 7.49×10−10 Sv

Number of Sv received by 70 kg person is 7.49×10−10 Sv.

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Answer 2

Question

Chapter 24, Problem 24.62P

(a)

Interpretation Introduction

Interpretation:

Number of Gray (Dose) received by 70 kg person has to be determined using the given data.

Concept Introduction:

Radiation Dose is the dose quantity that explains the effects of ionizing radiation. It describes the quantity of radiation energy that is absorbed by a matter.

Dose = Energy(Joules)Weight(kg)

The units commonly used to measure dose are gray (Gy) and rad.

1 Gy = 1 J/kg1 rad = 0.01 J/kg = 0.01 Gy

(a)

Expert Solution

Explanation of Solution

Given information is shown below,

No. of β− particle = 6.0×105Mass of person = 70 kgEnergy of each β− particle = 8.74×10−14 J

Energy absorbed is determined as follows,

Energy(J) = (6.0×105 β−)(8.74×10−14 J/β−)= 5.244×10−8 J

Dose (Gray) received by 95 kg human is calculated as given,

Dose = (5.244×10−8 J70 kg)(1 rad0.01 J/kg)(0.01 Gy1 rad)= 7.49×10−10 Gy

Dose (Gray) received by 70 kg human is 7.49×10-10 Gy.

(b)

Interpretation Introduction

Interpretation:

Number of mrem received by 70 kg person has to be determined using the given data.

Concept Introduction:

Radiation Dose is the dose quantity that explains the effects of ionizing radiation. It describes the quantity of radiation energy that is absorbed by a matter.

The units commonly used to measure dose are gray (Gy) and rad.

1 Gy = 1 J/kg1 rad = 0.01 J/kg = 0.01 Gy

The tissue damage caused by the radiation depends on the exposure time, strength of the radiation and tissue type. Tissue damage can be determined by multiplying dose that is absorbed with RBE (Relative Biological Effectiveness).

The two units used to measure amount of damaged tissue in a person is rem(Roentgen Equivalent for Man) and sievert(Sv.)

No. of rem = no. of rads×RBE1 Sv = 100 rem

(b)

Expert Solution

Explanation of Solution

Given information is shown below,

No. of β− particle = 6.0×105Mass of person = 70 kgEnergy of each β− particle = 8.74×10−14 JRBE = 1.0

Energy absorbed is determined as follows,

Energy(J) = (6.0×105 β−)(8.74×10−14 J/β−)= 5.244×10−8 J

Dose (rad) received is calculated as given,

Dose = (5.244×10−8 J70 kg)(1 rad0.01 J/kg)= 7.49×10−8 rad

Dose (rad) received by 70 kg human is 7.49×10−8 rad.

Number of mrem received by 70 kg person is determined as shown below,

No. of rem = no. of rads×RBE= (7.49×10−8 rad)(1.0)(1 mrem10−3 rem)= 7.49×10−5 mrem

Number of mrem received by 70 kg person is 7.49×10−5 mrem.

(c)

Interpretation Introduction

Interpretation:

Number of sieverts (Sv) received by 70 kg person has to be determined using the given data.

Concept Introduction:

Radiation Dose is the dose quantity that explains the effects of ionizing radiation. It describes the quantity of radiation energy that is absorbed by a matter.

The units commonly used to measure dose are gray (Gy) and rad.

1 Gy = 1 J/kg1 rad = 0.01 J/kg = 0.01 Gy

The tissue damage caused by the radiation depends on the exposure time, strength of the radiation and tissue type. Tissue damage can be determined by multiplying dose that is absorbed with RBE (Relative Biological Effectiveness).

The two units used to measure amount of damaged tissue in a person is rem(Roentgen Equivalent for Man) and sievert(Sv.)

No. of rem = no. of rads×RBE1 Sv = 100 rem

(c)

Expert Solution

Explanation of Solution

Given information is shown below,

No. of β− particle = 6.0×105Mass of person = 70 kgEnergy of each β− particle = 8.74×10−14 JRBE = 1.0

Energy absorbed is determined as follows,

Energy(J) = (6.0×105 β−)(8.74×10−14 J/β−)= 5.244×10−8 J

Dose (rad) received is calculated as given,

Dose = (5.244×10−8 J70 kg)(1 rad0.01 J/kg)= 7.49×10−8 rad

Dose (rad) received is 7.49×10−8 rad.

Number of Sv received by 70 kg person is determined as shown below,

No. of rem = no. of rads×RBE= (7.49×10−8 rad)(1.0)= 7.49×10−8 remNo. of Sv = 7.49×10−8 rem(0.01 Sv1 rem)= 7.49×10−10 Sv

Number of Sv received by 70 kg person is 7.49×10−10 Sv.

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Answer 3

Question

Chapter 24, Problem 24.62P

(a)

Interpretation Introduction

Interpretation:

Number of Gray (Dose) received by 70 kg person has to be determined using the given data.

Concept Introduction:

Radiation Dose is the dose quantity that explains the effects of ionizing radiation. It describes the quantity of radiation energy that is absorbed by a matter.

Dose = Energy(Joules)Weight(kg)

The units commonly used to measure dose are gray (Gy) and rad.

1 Gy = 1 J/kg1 rad = 0.01 J/kg = 0.01 Gy

(a)

Expert Solution

Explanation of Solution

Given information is shown below,

No. of β− particle = 6.0×105Mass of person = 70 kgEnergy of each β− particle = 8.74×10−14 J

Energy absorbed is determined as follows,

Energy(J) = (6.0×105 β−)(8.74×10−14 J/β−)= 5.244×10−8 J

Dose (Gray) received by 95 kg human is calculated as given,

Dose = (5.244×10−8 J70 kg)(1 rad0.01 J/kg)(0.01 Gy1 rad)= 7.49×10−10 Gy

Dose (Gray) received by 70 kg human is 7.49×10-10 Gy.

(b)

Interpretation Introduction

Interpretation:

Number of mrem received by 70 kg person has to be determined using the given data.

Concept Introduction:

Radiation Dose is the dose quantity that explains the effects of ionizing radiation. It describes the quantity of radiation energy that is absorbed by a matter.

The units commonly used to measure dose are gray (Gy) and rad.

1 Gy = 1 J/kg1 rad = 0.01 J/kg = 0.01 Gy

The tissue damage caused by the radiation depends on the exposure time, strength of the radiation and tissue type. Tissue damage can be determined by multiplying dose that is absorbed with RBE (Relative Biological Effectiveness).

The two units used to measure amount of damaged tissue in a person is rem(Roentgen Equivalent for Man) and sievert(Sv.)

No. of rem = no. of rads×RBE1 Sv = 100 rem

(b)

Expert Solution

Explanation of Solution

Given information is shown below,

No. of β− particle = 6.0×105Mass of person = 70 kgEnergy of each β− particle = 8.74×10−14 JRBE = 1.0

Energy absorbed is determined as follows,

Energy(J) = (6.0×105 β−)(8.74×10−14 J/β−)= 5.244×10−8 J

Dose (rad) received is calculated as given,

Dose = (5.244×10−8 J70 kg)(1 rad0.01 J/kg)= 7.49×10−8 rad

Dose (rad) received by 70 kg human is 7.49×10−8 rad.

Number of mrem received by 70 kg person is determined as shown below,

No. of rem = no. of rads×RBE= (7.49×10−8 rad)(1.0)(1 mrem10−3 rem)= 7.49×10−5 mrem

Number of mrem received by 70 kg person is 7.49×10−5 mrem.

(c)

Interpretation Introduction

Interpretation:

Number of sieverts (Sv) received by 70 kg person has to be determined using the given data.

Concept Introduction:

Radiation Dose is the dose quantity that explains the effects of ionizing radiation. It describes the quantity of radiation energy that is absorbed by a matter.

The units commonly used to measure dose are gray (Gy) and rad.

1 Gy = 1 J/kg1 rad = 0.01 J/kg = 0.01 Gy

The tissue damage caused by the radiation depends on the exposure time, strength of the radiation and tissue type. Tissue damage can be determined by multiplying dose that is absorbed with RBE (Relative Biological Effectiveness).

The two units used to measure amount of damaged tissue in a person is rem(Roentgen Equivalent for Man) and sievert(Sv.)

No. of rem = no. of rads×RBE1 Sv = 100 rem

(c)

Expert Solution

Explanation of Solution

Given information is shown below,

No. of β− particle = 6.0×105Mass of person = 70 kgEnergy of each β− particle = 8.74×10−14 JRBE = 1.0

Energy absorbed is determined as follows,

Energy(J) = (6.0×105 β−)(8.74×10−14 J/β−)= 5.244×10−8 J

Dose (rad) received is calculated as given,

Dose = (5.244×10−8 J70 kg)(1 rad0.01 J/kg)= 7.49×10−8 rad

Dose (rad) received is 7.49×10−8 rad.

Number of Sv received by 70 kg person is determined as shown below,

No. of rem = no. of rads×RBE= (7.49×10−8 rad)(1.0)= 7.49×10−8 remNo. of Sv = 7.49×10−8 rem(0.01 Sv1 rem)= 7.49×10−10 Sv

Number of Sv received by 70 kg person is 7.49×10−10 Sv.

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Answer 4

Question

Chapter 24, Problem 24.62P

(a)

Interpretation Introduction

Interpretation:

Number of Gray (Dose) received by 70 kg person has to be determined using the given data.

Concept Introduction:

Radiation Dose is the dose quantity that explains the effects of ionizing radiation. It describes the quantity of radiation energy that is absorbed by a matter.

Dose = Energy(Joules)Weight(kg)

The units commonly used to measure dose are gray (Gy) and rad.

1 Gy = 1 J/kg1 rad = 0.01 J/kg = 0.01 Gy

(a)

Expert Solution

Explanation of Solution

Given information is shown below,

No. of β− particle = 6.0×105Mass of person = 70 kgEnergy of each β− particle = 8.74×10−14 J

Energy absorbed is determined as follows,

Energy(J) = (6.0×105 β−)(8.74×10−14 J/β−)= 5.244×10−8 J

Dose (Gray) received by 95 kg human is calculated as given,

Dose = (5.244×10−8 J70 kg)(1 rad0.01 J/kg)(0.01 Gy1 rad)= 7.49×10−10 Gy

Dose (Gray) received by 70 kg human is 7.49×10-10 Gy.

(b)

Interpretation Introduction

Interpretation:

Number of mrem received by 70 kg person has to be determined using the given data.

Concept Introduction:

Radiation Dose is the dose quantity that explains the effects of ionizing radiation. It describes the quantity of radiation energy that is absorbed by a matter.

The units commonly used to measure dose are gray (Gy) and rad.

1 Gy = 1 J/kg1 rad = 0.01 J/kg = 0.01 Gy

The tissue damage caused by the radiation depends on the exposure time, strength of the radiation and tissue type. Tissue damage can be determined by multiplying dose that is absorbed with RBE (Relative Biological Effectiveness).

The two units used to measure amount of damaged tissue in a person is rem(Roentgen Equivalent for Man) and sievert(Sv.)

No. of rem = no. of rads×RBE1 Sv = 100 rem

(b)

Expert Solution

Explanation of Solution

Given information is shown below,

No. of β− particle = 6.0×105Mass of person = 70 kgEnergy of each β− particle = 8.74×10−14 JRBE = 1.0

Energy absorbed is determined as follows,

Energy(J) = (6.0×105 β−)(8.74×10−14 J/β−)= 5.244×10−8 J

Dose (rad) received is calculated as given,

Dose = (5.244×10−8 J70 kg)(1 rad0.01 J/kg)= 7.49×10−8 rad

Dose (rad) received by 70 kg human is 7.49×10−8 rad.

Number of mrem received by 70 kg person is determined as shown below,

No. of rem = no. of rads×RBE= (7.49×10−8 rad)(1.0)(1 mrem10−3 rem)= 7.49×10−5 mrem

Number of mrem received by 70 kg person is 7.49×10−5 mrem.

(c)

Interpretation Introduction

Interpretation:

Number of sieverts (Sv) received by 70 kg person has to be determined using the given data.

Concept Introduction:

Radiation Dose is the dose quantity that explains the effects of ionizing radiation. It describes the quantity of radiation energy that is absorbed by a matter.

The units commonly used to measure dose are gray (Gy) and rad.

1 Gy = 1 J/kg1 rad = 0.01 J/kg = 0.01 Gy

The tissue damage caused by the radiation depends on the exposure time, strength of the radiation and tissue type. Tissue damage can be determined by multiplying dose that is absorbed with RBE (Relative Biological Effectiveness).

The two units used to measure amount of damaged tissue in a person is rem(Roentgen Equivalent for Man) and sievert(Sv.)

No. of rem = no. of rads×RBE1 Sv = 100 rem

(c)

Expert Solution

Explanation of Solution

Given information is shown below,

No. of β− particle = 6.0×105Mass of person = 70 kgEnergy of each β− particle = 8.74×10−14 JRBE = 1.0

Energy absorbed is determined as follows,

Energy(J) = (6.0×105 β−)(8.74×10−14 J/β−)= 5.244×10−8 J

Dose (rad) received is calculated as given,

Dose = (5.244×10−8 J70 kg)(1 rad0.01 J/kg)= 7.49×10−8 rad

Dose (rad) received is 7.49×10−8 rad.

Number of Sv received by 70 kg person is determined as shown below,

No. of rem = no. of rads×RBE= (7.49×10−8 rad)(1.0)= 7.49×10−8 remNo. of Sv = 7.49×10−8 rem(0.01 Sv1 rem)= 7.49×10−10 Sv

Number of Sv received by 70 kg person is 7.49×10−10 Sv.

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Answer 5

Chapter 24, Problem 24.62P

(a)

Interpretation Introduction

Interpretation:

Number of Gray (Dose) received by 70 kg person has to be determined using the given data.

Concept Introduction:

Radiation Dose is the dose quantity that explains the effects of ionizing radiation. It describes the quantity of radiation energy that is absorbed by a matter.

Dose = Energy(Joules)Weight(kg)

The units commonly used to measure dose are gray (Gy) and rad.

1 Gy = 1 J/kg1 rad = 0.01 J/kg = 0.01 Gy

(a)

Expert Solution

Explanation of Solution

Given information is shown below,

No. of β− particle = 6.0×105Mass of person = 70 kgEnergy of each β− particle = 8.74×10−14 J

Energy absorbed is determined as follows,

Energy(J) = (6.0×105 β−)(8.74×10−14 J/β−)= 5.244×10−8 J

Dose (Gray) received by 95 kg human is calculated as given,

Dose = (5.244×10−8 J70 kg)(1 rad0.01 J/kg)(0.01 Gy1 rad)= 7.49×10−10 Gy

Dose (Gray) received by 70 kg human is 7.49×10-10 Gy.

(b)

Interpretation Introduction

Interpretation:

Number of mrem received by 70 kg person has to be determined using the given data.

Concept Introduction:

Radiation Dose is the dose quantity that explains the effects of ionizing radiation. It describes the quantity of radiation energy that is absorbed by a matter.

The units commonly used to measure dose are gray (Gy) and rad.

1 Gy = 1 J/kg1 rad = 0.01 J/kg = 0.01 Gy

The tissue damage caused by the radiation depends on the exposure time, strength of the radiation and tissue type. Tissue damage can be determined by multiplying dose that is absorbed with RBE (Relative Biological Effectiveness).

The two units used to measure amount of damaged tissue in a person is rem(Roentgen Equivalent for Man) and sievert(Sv.)

No. of rem = no. of rads×RBE1 Sv = 100 rem

(b)

Expert Solution

Explanation of Solution

Given information is shown below,

No. of β− particle = 6.0×105Mass of person = 70 kgEnergy of each β− particle = 8.74×10−14 JRBE = 1.0

Energy absorbed is determined as follows,

Energy(J) = (6.0×105 β−)(8.74×10−14 J/β−)= 5.244×10−8 J

Dose (rad) received is calculated as given,

Dose = (5.244×10−8 J70 kg)(1 rad0.01 J/kg)= 7.49×10−8 rad

Dose (rad) received by 70 kg human is 7.49×10−8 rad.

Number of mrem received by 70 kg person is determined as shown below,

No. of rem = no. of rads×RBE= (7.49×10−8 rad)(1.0)(1 mrem10−3 rem)= 7.49×10−5 mrem

Number of mrem received by 70 kg person is 7.49×10−5 mrem.

(c)

Interpretation Introduction

Interpretation:

Number of sieverts (Sv) received by 70 kg person has to be determined using the given data.

Concept Introduction:

Radiation Dose is the dose quantity that explains the effects of ionizing radiation. It describes the quantity of radiation energy that is absorbed by a matter.

The units commonly used to measure dose are gray (Gy) and rad.

1 Gy = 1 J/kg1 rad = 0.01 J/kg = 0.01 Gy

The tissue damage caused by the radiation depends on the exposure time, strength of the radiation and tissue type. Tissue damage can be determined by multiplying dose that is absorbed with RBE (Relative Biological Effectiveness).

The two units used to measure amount of damaged tissue in a person is rem(Roentgen Equivalent for Man) and sievert(Sv.)

No. of rem = no. of rads×RBE1 Sv = 100 rem

(c)

Expert Solution

Explanation of Solution

Given information is shown below,

No. of β− particle = 6.0×105Mass of person = 70 kgEnergy of each β− particle = 8.74×10−14 JRBE = 1.0

Energy absorbed is determined as follows,

Energy(J) = (6.0×105 β−)(8.74×10−14 J/β−)= 5.244×10−8 J

Dose (rad) received is calculated as given,

Dose = (5.244×10−8 J70 kg)(1 rad0.01 J/kg)= 7.49×10−8 rad

Dose (rad) received is 7.49×10−8 rad.

Number of Sv received by 70 kg person is determined as shown below,

No. of rem = no. of rads×RBE= (7.49×10−8 rad)(1.0)= 7.49×10−8 remNo. of Sv = 7.49×10−8 rem(0.01 Sv1 rem)= 7.49×10−10 Sv

Number of Sv received by 70 kg person is 7.49×10−10 Sv.

Answer 6

Chapter 24, Problem 24.62P

(a)

Interpretation Introduction

Interpretation:

Number of Gray (Dose) received by 70 kg person has to be determined using the given data.

Concept Introduction:

Radiation Dose is the dose quantity that explains the effects of ionizing radiation. It describes the quantity of radiation energy that is absorbed by a matter.

Dose = Energy(Joules)Weight(kg)

The units commonly used to measure dose are gray (Gy) and rad.

1 Gy = 1 J/kg1 rad = 0.01 J/kg = 0.01 Gy

(a)

Expert Solution

Explanation of Solution

Given information is shown below,

No. of β− particle = 6.0×105Mass of person = 70 kgEnergy of each β− particle = 8.74×10−14 J

Energy absorbed is determined as follows,

Energy(J) = (6.0×105 β−)(8.74×10−14 J/β−)= 5.244×10−8 J

Dose (Gray) received by 95 kg human is calculated as given,

Dose = (5.244×10−8 J70 kg)(1 rad0.01 J/kg)(0.01 Gy1 rad)= 7.49×10−10 Gy

Dose (Gray) received by 70 kg human is 7.49×10-10 Gy.

Answer 7

Chapter 24, Problem 24.62P

(a)

Interpretation Introduction

Interpretation:

Number of Gray (Dose) received by 70 kg person has to be determined using the given data.

Concept Introduction:

Radiation Dose is the dose quantity that explains the effects of ionizing radiation. It describes the quantity of radiation energy that is absorbed by a matter.

Dose = Energy(Joules)Weight(kg)

The units commonly used to measure dose are gray (Gy) and rad.

1 Gy = 1 J/kg1 rad = 0.01 J/kg = 0.01 Gy

Answer 8

(a)

Expert Solution

Explanation of Solution

Given information is shown below,

No. of β− particle = 6.0×105Mass of person = 70 kgEnergy of each β− particle = 8.74×10−14 J

Energy absorbed is determined as follows,

Energy(J) = (6.0×105 β−)(8.74×10−14 J/β−)= 5.244×10−8 J

Dose (Gray) received by 95 kg human is calculated as given,

Dose = (5.244×10−8 J70 kg)(1 rad0.01 J/kg)(0.01 Gy1 rad)= 7.49×10−10 Gy

Dose (Gray) received by 70 kg human is 7.49×10-10 Gy.

Answer 9

(a)

Expert Solution

Answer 10

(a)

Expert Solution

Answer 11

Expert Solution

Answer 12

(b)

Interpretation Introduction

Interpretation:

Number of mrem received by 70 kg person has to be determined using the given data.

Concept Introduction:

Radiation Dose is the dose quantity that explains the effects of ionizing radiation. It describes the quantity of radiation energy that is absorbed by a matter.

The units commonly used to measure dose are gray (Gy) and rad.

1 Gy = 1 J/kg1 rad = 0.01 J/kg = 0.01 Gy

The tissue damage caused by the radiation depends on the exposure time, strength of the radiation and tissue type. Tissue damage can be determined by multiplying dose that is absorbed with RBE (Relative Biological Effectiveness).

The two units used to measure amount of damaged tissue in a person is rem(Roentgen Equivalent for Man) and sievert(Sv.)

No. of rem = no. of rads×RBE1 Sv = 100 rem

(b)

Expert Solution

Explanation of Solution

Given information is shown below,

No. of β− particle = 6.0×105Mass of person = 70 kgEnergy of each β− particle = 8.74×10−14 JRBE = 1.0

Energy absorbed is determined as follows,

Energy(J) = (6.0×105 β−)(8.74×10−14 J/β−)= 5.244×10−8 J

Dose (rad) received is calculated as given,

Dose = (5.244×10−8 J70 kg)(1 rad0.01 J/kg)= 7.49×10−8 rad

Dose (rad) received by 70 kg human is 7.49×10−8 rad.

Number of mrem received by 70 kg person is determined as shown below,

No. of rem = no. of rads×RBE= (7.49×10−8 rad)(1.0)(1 mrem10−3 rem)= 7.49×10−5 mrem

Number of mrem received by 70 kg person is 7.49×10−5 mrem.

Answer 13

(b)

Interpretation Introduction

Interpretation:

Number of mrem received by 70 kg person has to be determined using the given data.

Concept Introduction:

Radiation Dose is the dose quantity that explains the effects of ionizing radiation. It describes the quantity of radiation energy that is absorbed by a matter.

The units commonly used to measure dose are gray (Gy) and rad.

1 Gy = 1 J/kg1 rad = 0.01 J/kg = 0.01 Gy

The tissue damage caused by the radiation depends on the exposure time, strength of the radiation and tissue type. Tissue damage can be determined by multiplying dose that is absorbed with RBE (Relative Biological Effectiveness).

The two units used to measure amount of damaged tissue in a person is rem(Roentgen Equivalent for Man) and sievert(Sv.)

No. of rem = no. of rads×RBE1 Sv = 100 rem

Answer 14

(b)

Expert Solution

Explanation of Solution

Given information is shown below,

No. of β− particle = 6.0×105Mass of person = 70 kgEnergy of each β− particle = 8.74×10−14 JRBE = 1.0

Energy absorbed is determined as follows,

Energy(J) = (6.0×105 β−)(8.74×10−14 J/β−)= 5.244×10−8 J

Dose (rad) received is calculated as given,

Dose = (5.244×10−8 J70 kg)(1 rad0.01 J/kg)= 7.49×10−8 rad

Dose (rad) received by 70 kg human is 7.49×10−8 rad.

Number of mrem received by 70 kg person is determined as shown below,

No. of rem = no. of rads×RBE= (7.49×10−8 rad)(1.0)(1 mrem10−3 rem)= 7.49×10−5 mrem

Number of mrem received by 70 kg person is 7.49×10−5 mrem.

Answer 15

(b)

Expert Solution

Answer 16

(b)

Expert Solution

Answer 17

Expert Solution

Answer 18

(c)

Interpretation Introduction

Interpretation:

Number of sieverts (Sv) received by 70 kg person has to be determined using the given data.

Concept Introduction:

Radiation Dose is the dose quantity that explains the effects of ionizing radiation. It describes the quantity of radiation energy that is absorbed by a matter.

The units commonly used to measure dose are gray (Gy) and rad.

1 Gy = 1 J/kg1 rad = 0.01 J/kg = 0.01 Gy

The tissue damage caused by the radiation depends on the exposure time, strength of the radiation and tissue type. Tissue damage can be determined by multiplying dose that is absorbed with RBE (Relative Biological Effectiveness).

The two units used to measure amount of damaged tissue in a person is rem(Roentgen Equivalent for Man) and sievert(Sv.)

No. of rem = no. of rads×RBE1 Sv = 100 rem

(c)

Expert Solution

Explanation of Solution

Given information is shown below,

No. of β− particle = 6.0×105Mass of person = 70 kgEnergy of each β− particle = 8.74×10−14 JRBE = 1.0

Energy absorbed is determined as follows,

Energy(J) = (6.0×105 β−)(8.74×10−14 J/β−)= 5.244×10−8 J

Dose (rad) received is calculated as given,

Dose = (5.244×10−8 J70 kg)(1 rad0.01 J/kg)= 7.49×10−8 rad

Dose (rad) received is 7.49×10−8 rad.

Number of Sv received by 70 kg person is determined as shown below,

No. of rem = no. of rads×RBE= (7.49×10−8 rad)(1.0)= 7.49×10−8 remNo. of Sv = 7.49×10−8 rem(0.01 Sv1 rem)= 7.49×10−10 Sv

Number of Sv received by 70 kg person is 7.49×10−10 Sv.

Answer 19

(c)

Interpretation Introduction

Interpretation:

Number of sieverts (Sv) received by 70 kg person has to be determined using the given data.

Concept Introduction:

Radiation Dose is the dose quantity that explains the effects of ionizing radiation. It describes the quantity of radiation energy that is absorbed by a matter.

The units commonly used to measure dose are gray (Gy) and rad.

1 Gy = 1 J/kg1 rad = 0.01 J/kg = 0.01 Gy

The tissue damage caused by the radiation depends on the exposure time, strength of the radiation and tissue type. Tissue damage can be determined by multiplying dose that is absorbed with RBE (Relative Biological Effectiveness).

The two units used to measure amount of damaged tissue in a person is rem(Roentgen Equivalent for Man) and sievert(Sv.)

No. of rem = no. of rads×RBE1 Sv = 100 rem

Answer 20

(c)

Expert Solution

Explanation of Solution

Given information is shown below,

No. of β− particle = 6.0×105Mass of person = 70 kgEnergy of each β− particle = 8.74×10−14 JRBE = 1.0

Energy absorbed is determined as follows,

Energy(J) = (6.0×105 β−)(8.74×10−14 J/β−)= 5.244×10−8 J

Dose (rad) received is calculated as given,

Dose = (5.244×10−8 J70 kg)(1 rad0.01 J/kg)= 7.49×10−8 rad

Dose (rad) received is 7.49×10−8 rad.

Number of Sv received by 70 kg person is determined as shown below,

No. of rem = no. of rads×RBE= (7.49×10−8 rad)(1.0)= 7.49×10−8 remNo. of Sv = 7.49×10−8 rem(0.01 Sv1 rem)= 7.49×10−10 Sv

Number of Sv received by 70 kg person is 7.49×10−10 Sv.

Answer 21

(c)

Expert Solution

Answer 22

(c)

Expert Solution

Answer 23

Expert Solution

Answer 24

Ch. 24.1 - Prob. 24.1AFP Ch. 24.1 - Prob. 24.1BFP Ch. 24.1 - Prob. 24.2AFP Ch. 24.1 - Why is stable but unstable? Ch. 24.1 - Prob. 24.3AFP Ch. 24.1 - Prob. 24.3BFP Ch. 24.2 - Prob. 24.4AFP Ch. 24.2 - Prob. 24.4BFP Ch. 24.2 - Prob. 24.5AFP Ch. 24.2 - Prob. 24.5BFP

Explanation of Solution

Explanation of Solution

Explanation of Solution

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