(a)
Interpretation:
Missing species in the given transmutations,
Concept Introduction:
Nuclear reaction can be written in the shorthand notation with the parentheses. Bombarding particle, that is projectile can be represented as first symbol in the parentheses and the emitted can be represented as the second particle in the parentheses.
Parent nucleus and daughter nucleus can be represented in the front part of the parentheses and back part of the parentheses respectively. For example:
Common particles in radioactive decay and nuclear transformations are mentioned below,
Balancing nuclear reaction equation: The balanced nuclear reaction should conserve both mass number and atomic number.
- The sum of the mass numbers of the reactants should be equal to the sum of mass numbers of the products in the reaction.
- The sum of
atomic numbers (or the atomic charge) of the reactants should be equal to the sum of atomic numbers (or the atomic charge) of the products in the reaction.
(a)

Explanation of Solution
For the given reaction, short hand notation is
The given unbalanced nuclear equation is,
According to the law of conservation of
Missing species is determined as follows,
The elemental symbol of the missing species is
(b)
Interpretation:
Missing species in the given transmutations,
Concept Introduction:
Nuclear reaction can be written in the shorthand notation with the parentheses. Bombarding particle, that is projectile can be represented as first symbol in the parentheses and the emitted can be represented as the second particle in the parentheses.
Parent nucleus and daughter nucleus can be represented in the front part of the parentheses and back part of the parentheses respectively. For example:
Common particles in radioactive decay and nuclear transformations are mentioned below,
Balancing nuclear reaction equation: The balanced nuclear reaction should conserve both mass number and atomic number.
- The sum of the mass numbers of the reactants should be equal to the sum of mass numbers of the products in the reaction.
- The sum of atomic numbers (or the atomic charge) of the reactants should be equal to the sum of atomic numbers (or the atomic charge) of the products in the reaction.
(b)

Explanation of Solution
For the given reaction, short hand notation is
The given unbalanced nuclear equation is,
According to the law of conservation of atomic mass and number, the unknown species can be predicted.
Missing species is determined as follows,
By analyzing the X, atomic number of X is 0 and the atomic mass is 1. So the missing species is neutron,
Therefore, the balanced nuclear equation is,
(c)
Interpretation:
Missing species in the given transmutations,
Concept Introduction:
Nuclear reaction can be written in the shorthand notation with the parentheses. Bombarding particle, that is projectile can be represented as first symbol in the parentheses and the emitted can be represented as the second particle in the parentheses.
Parent nucleus and daughter nucleus can be represented in the front part of the parentheses and back part of the parentheses respectively. For example:
Common particles in radioactive decay and nuclear transformations are mentioned below,
Balancing nuclear reaction equation: The balanced nuclear reaction should conserve both mass number and atomic number.
- The sum of the mass numbers of the reactants should be equal to the sum of mass numbers of the products in the reaction.
- The sum of atomic numbers (or the atomic charge) of the reactants should be equal to the sum of atomic numbers (or the atomic charge) of the products in the reaction.
(c)

Explanation of Solution
For the given reaction, short hand notation is
The given unbalanced nuclear equation is,
According to the law of conservation of atomic mass and number, the unknown element can be predicted.
Missing species is determined as follows,
The elemental symbol of the missing species is
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Chapter 24 Solutions
CHEM 212:CHEMISTSRY V 2
- 个 Stuck x ctc xALE X A ALE × A ALE X Lab x (19: x - G www-awu.aleks.com/alekscgi/x/Isl.exe/10_u-lgNslkr7j8P3jH-1Q1g8NUi-mObka ZLx2twjEhK7mVG6PUUIO06 Chapter 12 HW 三 Question 26 of 39 (4 points) 1 Question Attempt: 1 of Unlimited Answer the following questions about the given alkane. Part: 0 / 2 Part 1 of 2 Give the IUPAC name. Skip Part 2 53°F Clear Check × Q Search hp hp 02arrow_forwardCalculate the equilibrium constant at 25.0 oC for the following equation. Cd(s) + Sn+2(aq) ↔Cd+2(aq) + Sn(s) Group of answer choices 3.11x104 1.95x1018 9.66x108 1.40x109arrow_forwardWhat is the pH at the cathode for the following cell written in line notation at 25.0 oC with a Ecell = -0.2749 V? Ni(s)|Ni+2(aq, 1.00 M)||H+1(aq, ?M)|H2(g, 1.00 atm)|Pt(s)arrow_forward
- Calculate Ecell for a hydrogen fuel cell at 95.0 oC using the following half-reactions with PH2 = 25.0 atm and PO2 = 25.0 atm. O2(g) + 4H+1(aq) + 4e-1 → 2H2O(l) Eo = 1.229 V 2H2(g) → 4H+1(aq) + 4e-1 Eo = 0.00 Varrow_forwardCalculate Ecell at 25.0 oC using the following half-reactions with [Ag+1] = 0.0100 M and [Sn+2] = 0.0200 M. Ag+1(aq) + 1e-1 Ag(s) Sn+2(aq) + 2e-1 Sn(s)arrow_forwardDone 18:19 www-awu.aleks.com Chapter 12 HW Question 27 of 39 (5 points) | Question Attempt: 1 of Unlimited .. LTE סוי 9 ✓ 20 ✓ 21 × 22 23 24 25 26 27 28 29 30 Answer the following questions about the given alkane. Part: 0 / 2 Part 1 of 2 Classify each carbon atom as a 1º, 2º, 3º, or 4°. Highlight in red any 1° carbons, highlight in blue any 2° carbons. highlight in green any 3° carbons, and leave any 4° carbons unhighlighted. Skip Part Check Save For Later © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use Privacy Center | Accessibility ☑ คarrow_forward
- < Done 19:22 www-awu.aleks.com Chapter 12 HW Question 4 of 39 (2 points) | Question Attempt: 5 of Unlimited : .. LTE סוי 1 ✓ 2 ✓ 3 = 4 ✓ 5 ✓ 6 ✓ 7 ✓ 8 ✓ 9 = 10 11 ✓ 12 Consider the molecule (CH3)2CHCH2CHCн for the following questions. Part 1 of 2 Which of the following molecules is/are constitutional isomer(s) to (CH3)2CHCH2CH2CH3? Check all that apply. Part 2 of 2 (CH3),C(CH2)2CH3 CH3 H,C-CH-CH-CH, CH 3 None of the above. ☑ Which of the following molecules is/are identical molecules to (CH3)2CHCH2CH2CH₁₂? Check all that apply. CH3 H,C-CH-CH₂-CH2-CH, CH3(CH2)2CH(CH3)2 CH2-CH2-CH3 HỌC-CH=CH, 乂 ☑ а None of the above Check Save For Later Submit Assignment © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center Accessibilityarrow_forward18:11 LTE ا... US$50 off hotels is waiting for you Book now, hotels in Nashville are going fast QUTSLIVII 25 61 69 points) | QuestIVIT ALLēm... now Give the IUPAC name for each compound. Part 1 of 3 Part 2 of 3 X ☑ Х Check Save For Later Submit © 2025 McGraw Hill LLC. All Rights Reserved. TOMS CT US ...vacy Center | Accessibilityarrow_forwardDone 19:17 www-awu.aleks.com Chapter 12 HW Question 29 of 39 (6 points) | Question Attempt: 1 of Unlimited .III LTE סוי 27 28 = 29 30 31 32 = 33 34 35 Consider this structure. CH3CH2CH2 Part 1 of 3 3 CH2 CH2CH3 - C-CH2CH 3 H CH₂ Give the IUPAC name of this structure. 3-ethyl-3,4-dimethylheptane Part: 1/3 Part 2 of 3 Draw the skeletal structure. Skip Part < Check Click and drag to start drawing a structure. Save For Later Submit © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibility Хarrow_forward
- 18:57 .III LTE www-awu.aleks.com Chapter 12 HW Question 31 of 39 (8 points) | Question Attem... Give the IUPAC name of each compound. Part 1 of 4 Part 2 of 4 Х Х Check Save For Later Submit © 2025 McGraw Hill LLC. All Rights Reserved. TOMS OF US vacy Center | Accessibilityarrow_forwardWhat is the missing reactant in this organic reaction? CH3-C-CH2-NH2 + R - CH3 O: 0 CH3-N-CH2-C-NH-CH2-C-CH3 + H2O Specifically, in the drawing area below draw the condensed structure of R. If there is more than one reasonable answer, you can draw any one of them. If there is no reasonable answer, check the No answer box under the drawing area. Note for advanced students: you may assume no products other than those shown above are formed. Explanation Check Click anywhere to draw the first atom of your structure. C © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center Accesarrow_forwardDone 18:17 • www-awu.aleks.com Chapter 12 HW Question 24 of 39 (4 points) | Question Attempt: 1 of Unlimited ▼ 20 ✓ 21 × 22 23 24 25 26 raw the structure corresponding to each IUPAC name. Part 1 of 2 .III LTE 22 27 28 סוי 29 29 3 A skeletal structure corresponding to the IUPAC name 3-ethyl-4-methylhexane. Part 2 of 2 Click and drag to start drawing a structure. A condensed structure corresponding to the IUPAC name 2,2,4- trimethylpentane. Click anywhere to draw the first atom of your structure. Check Save For Later Submit < Х ப: G © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibility : Garrow_forward
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