Chapter 24, Problem 24.50P

Interpretation Introduction

(a)

Interpretation:

The given Diels-Alder reaction is reversible or irreversible at room temperature is to be determined.

Concept introduction:

The standard free energy change ($\Delta G^o$) of the reaction decides whether the reaction is reversible or irreversible at the given conditions. If ($\Delta G^o$) is positive, the reaction will be reversible, and if ($\Delta G^o$) is negative, the reaction will irreversible and spontaneous. The relation of ${\text{ΔG}}^{\text{o}}$ with ${\text{ΔH}}^{\text{o}}$ and ${\text{TΔS}}^{\text{o}}$ is ${\text{ΔG}}^{\text{o}}{\text{= ΔH}}^{\text{o}}{\text{- TΔS}}^{\text{o}}$, where T is the temperature of the reaction in K. At equilibrium, $\Delta G^o$ of the reaction is always zero.

Interpretation Introduction

(b)

Interpretation:

The temperature at which the equilibrium constant of the given Diels-Alder reaction becomes $\text{1}$ is to be estimated.

Concept introduction:

The standard free energy change ($\Delta G^o$) of the reaction decides whether the reaction is reversible or irreversible at the given conditions. If ($\Delta G^o$) is positive, the reaction will be reversible, and if ($\Delta G^o$) is negative, the reaction will irreversible and spontaneous. The relation of ${\text{ΔG}}^{\text{o}}$ with ${\text{ΔH}}^{\text{o}}$ and ${\text{TΔS}}^{\text{o}}$ is ${\text{ΔG}}^{\text{o}}{\text{= ΔH}}^{\text{o}}{\text{- TΔS}}^{\text{o}}$, where T is the temperature of the reaction in K. At equilibrium, $\Delta G^o$ of the reaction is always zero.