Chapter 24, Problem 24.33P

Interpretation Introduction

Interpretation:

Specific activity (in $\text{Ci/g}$) of $1.65\text{ mg}$ isotope that emits $1.56\times {10}^6\alpha \text{ particles per second}$ has to be determined using the given information.

Concept Introduction:

Mass of a substance can be determined from molar mass as given,

  $Mass\text{ = No}\text{. of moles}\times \text{Molar mass}$

Unit conversion:

$Specific\text{ activity }\left(in\text{ Ci/g}\right)\text{= }No.\text{of disintegrations per second}\times \frac{1\text{ Ci}}{3.70\times {10}^{10}\text{ d/s}}\times \frac{1}{Mass}$