Stable nuclide has to be identified among the given nuclides and explained. Concept Introduction: Nuclear stability means that the nucleus is stable meaning that it does not spontaneously emit any kind of radioactivity. Nuclear stability can be explained based on neutron to proton ratio (N/Z) in the nucleus. For a stable atoms having low atomic number , n/p ratio is close to 1. When atomic number increases N/Z becomes greater than 1. For a stable nucleus N/Z ratio is one and which lies in the belt of stability of graph of number of protons to number neutrons. When an isotope is above the belt of stability, N/Z ratio is high and there exists a beta emission to decrease the stability. General rules for predicting the nuclear stability is given below, If the nucleus contains 2, 8,20,50,82 or 126 protons or neutrons, then they are generally considered as stable than the nuclei that do not possess these numbers. If the nuclei has even number of both protons and neutrons, then they are considered as stable as those with odd number of these particles. All isotopes of elements with atomic number higher than 83 are radioactive.

Question

Want to see the full answer?

Answer 1

Question

Chapter 24, Problem 24.16P

Interpretation Introduction

Interpretation:

Stable nuclide has to be identified among the given nuclides and explained.

Concept Introduction:

Nuclear stability means that the nucleus is stable meaning that it does not spontaneously emit any kind of radioactivity.

Nuclear stability can be explained based on neutron to proton ratio (N/Z) in the nucleus.

For a stable atoms having low atomic number, n/p ratio is close to 1. When atomic number increases N/Z becomes greater than 1.

For a stable nucleus N/Z ratio is one and which lies in the belt of stability of graph of number of protons to number neutrons.

When an isotope is above the belt of stability, N/Z ratio is high and there exists a beta emission to decrease the stability.

General rules for predicting the nuclear stability is given below,

If the nucleus contains 2, 8,20,50,82 or 126 protons or neutrons, then they are generally considered as stable than the nuclei that do not possess these numbers.

If the nuclei has even number of both protons and neutrons, then they are considered as stable as those with odd number of these particles.

All isotopes of elements with atomic number higher than 83 are radioactive.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

1) Suppose 0.1 kg ice at 0°C (273K) is in 0.5kg water at 20°C (293K). What is the change in entropy of the ice as it melts at 0°? To produce the original "water gas" mixture, carbon (in a combustible form known as coke) is reacted with steam: 131.4 kJ + H20(g) + C(s) → CO(g) + H2(g) From this information and the equations in the previous problem, calculate the enthalpy for the combustion or carbon to form carbon dioxide. kindly show me how to solve both parts of the same long problem. Thanks

we were assigned to dilute 900ppm in to 18ppm by using only 250ml vol flask. firstly we did calc and convert 900ppm to 0.9 ppm to dilute in 1 liter. to begin the experiment we took 0,225g of kmno4 and dissolved in to 250 vol flask. then further we took 10 ml sample sol and dissolved in to 100 ml vol flask and put it in to a spectrometer and got value of 0.145A . upon further calc we got v2 as 50ml . need to find DF, % error (expval and accptVal), molarity, molality. please write the whole report. thank you The format, tables, introduction, procedure and observation, result, calculations, discussion and conclusion

Q5. Predict the organic product(s) for the following transformations. If no reaction will take place (or the reaction is not synthetically useful), write "N.R.". Determine what type of transition state is present for each reaction (think Hammond Postulate). I Br₂ CH3 F2, light CH3 Heat CH3 F₂ Heat Br2, light 12, light CH3 Cl2, light No