BIG JAVA: LATE OBJECTS
2nd Edition
ISBN: 9781119626220
Author: Horstmann
Publisher: WILEY
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Expert Solution & Answer
Chapter 24, Problem 11RE
Explanation of Solution
XPath:
The easiest way to inspect the XML document is by using the XPath syntax.
- In the DOM standard, a node is a common superclass for all the components that is present in the XML document.
- To be precise, nodes are elements and text sequences.
- XPath describes a node or set of nodes, the syntax of XPath is similar to that of directory paths.
Example:
/items/item[1]/quantity
The above XPath selects the quantity of the first item.
Result of evaluating the following XPath expressions:
a. Expression to get the value of the first coin
The XPath expression that is used to get the value of the first coin is “/purse/coin[1]/value”
B Number of coins:
The XPath expression that is used to get the number of coins is “count(/purse/coin)”...
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Challenge: Assume that the assigned network addresses are correct. Can you deduce (guess) what the network subnet masks are? Explain while providing subnet mask bits for each subnet mask.
[Hint: Look at the addresses in binary and consider the host ids]
To assume that the network addresses are correct, we take a look at the network ID and IP addresses. Take 20.0.0.0/8, we have an /8 prefix which is Class A, that provide us with 255.0.0.0. This means that there are 24 host bits while the network bits are 8. When compared to the IP address 20.255.0.7, we can perform an additional operation with the subnet mask giving us 20.0.0.0. The same happened with 20.0.0.89, which we also got 20.0.0.0. Therefore, these two IP addresses fall within the respective /8 subnet. For 200.100.10.0/30, the /30 is Class C with a subnet mask of 255.255.255.252, meaning 30 network bits and only two host bits. When applying the subnet mask and the IP addresses…
It is possible to sort an array of n values using pipeline of n filter processes.The first process inputs all the values one at a time, keep the minimum, and passes the others on to the next process. Each filter does the same thing; it receives a stream of values from the previous process, keep the smallest, and passes the others to the next process. Assume each process has local storage for only two values--- the next input value and the minimum it has seen so far.
(a) Developcode for filter processes. Declare the channels and use asynchronous message passing.
Hint:Define an array of channels value[n] (int), and a set of filter processes Filter[i = 0 ton-1]. Each process Filter[i] (where 0 <= i <= n-2) receives a stream of integers through channelvalue[i], keeps the smallest, and sends all other integers to channel value[i+1]. The last processFilter[n-1] receives only one integer through channel value[n-1] and does not need to send anyinteger further.
It is possible to sort an array of n values using pipeline of n filter processes.The first process inputs all the values one at a time, keep the minimum, and passes the others on to the next process. Each filter does the same thing; it receives a stream of values from the previous process, keep the smallest, and passes the others to the next process. Assume each process has local storage for only two values--- the next input value and the minimum it has seen so far.
(a) Developcode for filter processes. Declare the channels and use asynchronous message passing.
Hint:Define an array of channels value[n] (int), and a set of filter processes Filter[i = 0 ton-1]. Each process Filter[i] (where 0 <= i <= n-2) receives a stream of integers through channelvalue[i], keeps the smallest, and sends all other integers to channel value[i+1]. The last processFilter[n-1] receives only one integer through channel value[n-1] and does not need to send anyinteger further.
Chapter 24 Solutions
BIG JAVA: LATE OBJECTS
Ch. 24.1 - Prob. 1SCCh. 24.1 - Prob. 2SCCh. 24.1 - Prob. 3SCCh. 24.2 - Prob. 4SCCh. 24.2 - Prob. 5SCCh. 24.3 - Prob. 6SCCh. 24.3 - Prob. 7SCCh. 24.4 - Prob. 8SCCh. 24.4 - Prob. 9SCCh. 24.4 - Prob. 10SC
Ch. 24 - Prob. 1RECh. 24 - Prob. 2RECh. 24 - Prob. 3RECh. 24 - Prob. 4RECh. 24 - Prob. 5RECh. 24 - Prob. 6RECh. 24 - Prob. 7RECh. 24 - Prob. 8RECh. 24 - Prob. 9RECh. 24 - Prob. 10RECh. 24 - Prob. 11RECh. 24 - Prob. 12RECh. 24 - Prob. 13RECh. 24 - Prob. 14RECh. 24 - Prob. 15RECh. 24 - Prob. 16RECh. 24 - Prob. 17RECh. 24 - Prob. 18RECh. 24 - Prob. 1PECh. 24 - Prob. 2PECh. 24 - Prob. 3PECh. 24 - Prob. 4PECh. 24 - Prob. 5PECh. 24 - Prob. 6PECh. 24 - Prob. 1PPCh. 24 - Prob. 2PPCh. 24 - Prob. 3PPCh. 24 - Prob. 4PPCh. 24 - Prob. 5PPCh. 24 - Prob. 6PPCh. 24 - Prob. 7PPCh. 24 - Prob. 8PPCh. 24 - Prob. 9PPCh. 24 - Prob. 10PPCh. 24 - Prob. 11PPCh. 24 - Prob. 12PP
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