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(a)
Interpretation:
Structural formula for given compounds has to be written.
Concept Introduction:
Any organic molecule can be named by using certain rules given by IUPAC (International Union for Pure and applied chemistry). IUPAC name consists of three parts in major namely Prefix suffix and root word.
Prefix represents the substituent present in the molecule and its position in the root name.
Suffix denotes the presence of
Root word represents the longest continuous carbon skeleton of the organic molecule.
The structure of a molecule can be drawn by analyzing the presence of prefix, suffix and root word in the given IUPAC name.
Structural formula is representation of the organic compound. In this the lengthy carbon chain is shown only with the carbon atoms (along with the hydrogen) without any bonds. The additional branches are shown with explicit bonds.
To Give: The structural formula for given compounds.
(b)
Interpretation:
Structural formula for given compounds has to be written.
Concept Introduction:
Any organic molecule can be named by using certain rules given by IUPAC (International Union for Pure and applied chemistry). IUPAC name consists of three parts in major namely Prefix suffix and root word.
Prefix represents the substituent present in the molecule and its position in the root name.
Suffix denotes the presence of functional group if any in the molecule. It can be an alkene, alkyne, alcohol, carboxylic acid, alcohol etc.
Root word represents the longest continuous carbon skeleton of the organic molecule.
The structure of a molecule can be drawn by analyzing the presence of prefix, suffix and root word in the given IUPAC name.
Structural formula is representation of the organic compound. In this the lengthy carbon chain is shown only with the carbon atoms (along with the hydrogen) without any bonds. The additional branches are shown with explicit bonds.
To Give: The structural formula for given compounds.
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Chapter 23 Solutions
OWLv2 for Ebbing/Gammon's General Chemistry, 11th Edition, [Instant Access], 1 term (6 months)
- Don't used Ai solutionarrow_forward5. A solution of sucrose is fermented in a vessel until the evolution of CO2 ceases. Then, the product solution is analyzed and found to contain, 45% ethanol; 5% acetic acid; and 15% glycerin by weight. If the original charge is 500 kg, evaluate; e. The ratio of sucrose to water in the original charge (wt/wt). f. Moles of CO2 evolved. g. Maximum possible amount of ethanol that could be formed. h. Conversion efficiency. i. Per cent excess of excess reactant. Reactions: Inversion reaction: C12H22O11 + H2O →2C6H12O6 Fermentation reaction: C6H12O6 →→2C2H5OH + 2CO2 Formation of acetic acid and glycerin: C6H12O6 + C2H5OH + H₂O→ CH3COOH + 2C3H8O3arrow_forwardShow work. don't give Ai generated solution. How many carbons and hydrogens are in the structure?arrow_forward
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