BIG JAVA: LATE OBJECTS
2nd Edition
ISBN: 9781119626220
Author: Horstmann
Publisher: WILEY
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Expert Solution & Answer
Chapter 23.5, Problem 12SC
Explanation of Solution
Query for displaying the amount due:
In the given program, the amount due can be displayed in two ways:
- Compute using loop for displaying line items.
- Else, issue a query for displaying line items.
The below SQL query is used to compute and display the line items amount due:
/* Display the amount due of line items */
SELECT SUM (Product.Price * LineItem.Quantity)
FROM Product, LineItem
WHERE Product.Product_Code = LineItem.Product_Code
AND LineItem.Invoice_Number = ?
Explanation:
- The above “SELECT” statement calculates and displays the “SUM(Product.Price * LineItem.Quantity)” columns from the “Product and LineItem” tables where “Product.Product_Code” is equal to “LineItem.Product_code” and “LineItem.Product_Code” is equal to “?”.
- “SUM(Product.Price * LineItem.Quantity)” – It finds and displays the total line items amount due related to the invoice number.
- “SUM” – It is a function used to calculate the sum of a field.
- “Product...
- “SUM(Product.Price * LineItem.Quantity)” – It finds and displays the total line items amount due related to the invoice number.
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public class SquareRoot {
public static void main(String[] args) {
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// implement a loop of your choice here
// Method that calculates the square root of integer variables
public static double myRoot(int number) {
double root;
root=number/2;
double root old;
do {
root old root;
root (root_old+number/root_old)/2;
} while (Math.abs(root_old-root)>1.8E-6);
return root;
}
// Method that calculates the square root of double variables
public static double myRoot(double number) {
double root;
root number/2;
double root_old;
do {
root old root;
root (root_old+number/root_old)/2;
while (Math.abs (root_old-root)>1.0E-6);
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Chapter 23 Solutions
BIG JAVA: LATE OBJECTS
Ch. 23.1 - Prob. 1SCCh. 23.1 - Prob. 2SCCh. 23.2 - Prob. 3SCCh. 23.2 - Prob. 4SCCh. 23.3 - Prob. 5SCCh. 23.3 - Prob. 6SCCh. 23.4 - Prob. 7SCCh. 23.4 - Prob. 8SCCh. 23.5 - Prob. 9SCCh. 23.5 - Prob. 10SC
Ch. 23.5 - Prob. 11SCCh. 23.5 - Prob. 12SCCh. 23 - Prob. 1RECh. 23 - Prob. 2RECh. 23 - Prob. 3RECh. 23 - Prob. 4RECh. 23 - Prob. 5RECh. 23 - Prob. 6RECh. 23 - Prob. 7RECh. 23 - Prob. 8RECh. 23 - Prob. 9RECh. 23 - Prob. 10RECh. 23 - Prob. 11RECh. 23 - Prob. 12RECh. 23 - Prob. 13RECh. 23 - Prob. 14RECh. 23 - Prob. 15RECh. 23 - Prob. 16RECh. 23 - Prob. 17RECh. 23 - Prob. 18RECh. 23 - Prob. 19RECh. 23 - Prob. 20RECh. 23 - Prob. 21RECh. 23 - Prob. 22RECh. 23 - Prob. 23RECh. 23 - Prob. 1PECh. 23 - Prob. 2PECh. 23 - Prob. 5PECh. 23 - Prob. 6PE
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