(a) Answer The current in the wire is zero. Explanation Given: Four resistors are connected. The circuit diagram is Calculation: As the resistors on both of the line AB are identical, the point A and B are at the same potential. As there is no potential difference between the points A, B , so there will be no current in the wire connecting these two points. Hence, the current in the wire is zero. Conclusion: Hence, the current in the wire is zero. (b) To determine the current through each resistor. Answer The current through each resistor doesn’t vary. Explanation Given: Four resistors are connected. The circuit diagram is Calculation: As there is no current through the wire connecting AB, the circuit identical to the one without the wire. Hence, the wire doesn’t make any difference in the circuit. So, the current through resistor doesn’t vary. Conclusion: Hence, the current through each resistor doesn’t vary. (c) To determine the current through the battery. Answer Current drawn from the battery also doesn’t change. Explanation Given: Four resistors are connected. The circuit diagram is Calculation: The current drawn from the battery depends on the voltage of the battery and the effective resistance of the circuit only. The effective resistance of the circuit with the wire is equal to that of the circuit without the wire which is equal to R. As the effective resistance of the circuit doesn’t change, the current drawn from the battery also doesn’t change. Conclusion: Hence, current drawn from the battery also doesn’t change. (d) To determine the potential difference across each resistor. Answer The potential difference across each resistor remains the same. Explanation Given: Four resistors are connected. The circuit diagram is Calculation: The potential difference across each resistor remains the same. Conclusion: Hence, the potential difference across each resistor remains the same.

Glencoe Physics: Principles and Problems, Student Edition

1st Edition

ISBN: 9780078807213

Author: Paul W. Zitzewitz

Publisher: Glencoe/McGraw-Hill

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Question

Chapter 23.1, Problem 24SSC

(a)

To determine

the current through the wire.

(a)

Expert Solution

Answer to Problem 24SSC

The current in the wire is zero.

Explanation of Solution

Given:

Four resistors are connected.

The circuit diagram is

Glencoe Physics: Principles and Problems, Student Edition, Chapter 23.1, Problem 24SSC , additional homework tip 1

Calculation:

As the resistors on both of the line AB are identical, the point A and B are at the same potential. As there is no potential difference between the points A, B , so there will be no current in the wire connecting these two points. Hence, the current in the wire is zero.

Conclusion:

Hence, the current in the wire is zero.

(b)

To determine

the current through each resistor.

(b)

Expert Solution

Answer to Problem 24SSC

The current through each resistor doesn’t vary.

Explanation of Solution

Given:

Four resistors are connected.

The circuit diagram is

Glencoe Physics: Principles and Problems, Student Edition, Chapter 23.1, Problem 24SSC , additional homework tip 2

Calculation:

As there is no current through the wire connecting AB, the circuit identical to the one without the wire. Hence, the wire doesn’t make any difference in the circuit. So, the current through resistor doesn’t vary.

Conclusion:

Hence, the current through each resistor doesn’t vary.

(c)

To determine

the current through the battery.

(c)

Expert Solution

Answer to Problem 24SSC

Current drawn from the battery also doesn’t change.

Explanation of Solution

Given:

Four resistors are connected.

The circuit diagram is

Glencoe Physics: Principles and Problems, Student Edition, Chapter 23.1, Problem 24SSC , additional homework tip 3

Calculation:

The current drawn from the battery depends on the voltage of the battery and the effective resistance of the circuit only. The effective resistance of the circuit with the wire is equal to that of the circuit without the wire which is equal to R. As the effective resistance of the circuit doesn’t change, the current drawn from the battery also doesn’t change.

Conclusion:

Hence, current drawn from the battery also doesn’t change.

(d)

To determine

the potential difference across each resistor.

(d)

Expert Solution

Answer to Problem 24SSC

The potential difference across each resistor remains the same.

Explanation of Solution

Given:

Four resistors are connected.

The circuit diagram is

Glencoe Physics: Principles and Problems, Student Edition, Chapter 23.1, Problem 24SSC , additional homework tip 4

Calculation:

The potential difference across each resistor remains the same.

Conclusion:

Hence, the potential difference across each resistor remains the same.

Chapter 23.1, Problem 23SSC

Chapter 23.2, Problem 25PP

Chapter 23 Solutions

Glencoe Physics: Principles and Problems, Student Edition

Ch. 23.1 - Prob. 1PP Ch. 23.1 - Prob. 2PP Ch. 23.1 - Prob. 3PP Ch. 23.1 - Prob. 4PP Ch. 23.1 - Prob. 5PP Ch. 23.1 - Prob. 6PP Ch. 23.1 - Prob. 7PP Ch. 23.1 - Prob. 8PP Ch. 23.1 - Prob. 9PP Ch. 23.1 - Prob. 10PP

Ch. 23.1 - Prob. 11PP Ch. 23.1 - Prob. 12PP Ch. 23.1 - Prob. 13PP Ch. 23.1 - Prob. 14PP Ch. 23.1 - Prob. 15PP Ch. 23.1 - Prob. 16PP Ch. 23.1 - Prob. 17PP Ch. 23.1 - Prob. 18SSC Ch. 23.1 - Prob. 19SSC Ch. 23.1 - Prob. 20SSC Ch. 23.1 - Prob. 21SSC Ch. 23.1 - Prob. 22SSC Ch. 23.1 - Prob. 23SSC Ch. 23.1 - Prob. 24SSC Ch. 23.2 - Prob. 25PP Ch. 23.2 - Prob. 26PP Ch. 23.2 - Prob. 27PP Ch. 23.2 - Prob. 28SSC Ch. 23.2 - Prob. 29SSC Ch. 23.2 - Prob. 30SSC Ch. 23.2 - Prob. 31SSC Ch. 23.2 - Prob. 32SSC Ch. 23.2 - Prob. 33SSC Ch. 23.2 - Prob. 34SSC Ch. 23.2 - Prob. 35SSC Ch. 23 - Prob. 36A Ch. 23 - Prob. 37A Ch. 23 - Prob. 38A Ch. 23 - Prob. 39A Ch. 23 - Prob. 40A Ch. 23 - Prob. 41A Ch. 23 - Prob. 42A Ch. 23 - Prob. 43A Ch. 23 - Prob. 44A Ch. 23 - Prob. 45A Ch. 23 - Prob. 46A Ch. 23 - Prob. 47A Ch. 23 - Prob. 48A Ch. 23 - Prob. 49A Ch. 23 - Prob. 50A Ch. 23 - Prob. 51A Ch. 23 - Prob. 52A Ch. 23 - Prob. 53A Ch. 23 - Prob. 54A Ch. 23 - Prob. 55A Ch. 23 - Prob. 56A Ch. 23 - Prob. 57A Ch. 23 - Prob. 58A Ch. 23 - Prob. 59A Ch. 23 - Prob. 60A Ch. 23 - Prob. 61A Ch. 23 - Prob. 62A Ch. 23 - Prob. 63A Ch. 23 - Prob. 64A Ch. 23 - Prob. 65A Ch. 23 - Prob. 66A Ch. 23 - Prob. 67A Ch. 23 - Prob. 68A Ch. 23 - Prob. 69A Ch. 23 - Prob. 70A Ch. 23 - Prob. 71A Ch. 23 - Prob. 72A Ch. 23 - Prob. 73A Ch. 23 - Prob. 74A Ch. 23 - Prob. 75A Ch. 23 - Prob. 76A Ch. 23 - Prob. 77A Ch. 23 - Prob. 78A Ch. 23 - Prob. 79A Ch. 23 - Prob. 80A Ch. 23 - Prob. 81A Ch. 23 - Prob. 82A Ch. 23 - Prob. 83A Ch. 23 - Prob. 84A Ch. 23 - Prob. 85A Ch. 23 - Prob. 86A Ch. 23 - Prob. 87A Ch. 23 - Prob. 88A Ch. 23 - Prob. 89A Ch. 23 - Prob. 90A Ch. 23 - Prob. 91A Ch. 23 - Prob. 92A Ch. 23 - Prob. 93A Ch. 23 - Prob. 94A Ch. 23 - Prob. 95A Ch. 23 - Prob. 96A Ch. 23 - Prob. 97A Ch. 23 - Prob. 98A Ch. 23 - Prob. 99A Ch. 23 - Prob. 101A Ch. 23 - Prob. 102A Ch. 23 - Prob. 103A Ch. 23 - Prob. 104A Ch. 23 - Prob. 105A Ch. 23 - Prob. 1STP Ch. 23 - Prob. 2STP Ch. 23 - Prob. 3STP Ch. 23 - Prob. 4STP Ch. 23 - Prob. 5STP Ch. 23 - Prob. 6STP Ch. 23 - Prob. 7STP Ch. 23 - Prob. 8STP Ch. 23 - Prob. 9STP Ch. 23 - Prob. 10STP

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