
Electrical Wiring: Residental - With Plans (Paperback) Package
18th Edition
ISBN: 9781305416376
Author: MULLIN
Publisher: Cengage
expand_more
expand_more
format_list_bulleted
Textbook Question
Chapter 23.1, Problem 17R
Electric heating cable embedded in plaster, or sandwiched between layers of dry wall, creates heat. Therefore, any nonmetallic-sheathed cable run above these ceilings and buried in insulation must have its current-carrying capacity derated according to the (40°C) (50°C) (60°C) correction factors found in Table 310.15(B)(2)(a) in the NEC. (Circle the correct answer.)
Expert Solution & Answer

Trending nowThis is a popular solution!

Students have asked these similar questions
Design a counter to count-up from 2 to 7 using three of
D Flip Flops
(3) 3-Bit Count up (3 to 5) Using D Flip-Flop:
The State Equation of D Flip-Flop:
Q(t+1)=D(t) => Dn=Qn
Present State
D Flip-Flop
Next State
n
Q2p Q1p Q0p
3
0 1
1
1
Q2n Q1n Q0n D2 D1 D0
0 0 1 0 0
4
1
0
0
1
0
1
1 0
1
5
1 0
1
0
1
1
01
1
D2-Sum(3,4) and don't care X-Sum(0,1,2,6,7)
D1=Sum(5) and don't care X=Sum(0,1,2,6,7)
D0=Sum(4,5) and don't care X=Sum(0,1,2,6,7)
Using K-map to simplify the functions:
D2=Q1+Q0'
D1=Q1'QO
DO=Q1'
XOX
XOX
Q2 10
Q2 01
Q2 1xx
Q0
QO
Qo
D2 Q2
>CK
Q2
D1 Q1
BCD
CK
Q1
DO QF
►CK
Q0
☐ Present State Next State D Flip-Flop
n Q2p Q1p Q0p Q2n Q1n Q0n D2 D1 D0
2 0 1
0
0 1 1 0 1 1
3 0
1
1
1
0
0 1 00
4
1
0
0
1
0
1
1
0
1
5
1
0
1
1
1
0
1 1
0
6
1
1
0
0
1
0
0
1
0
D2
D2=Sum(3,4,5), X=Sum(0,1,7)
D1
Q2
1
Q1
1
0
☑
0
Qo
D2=Q0+Q1'
✗
0
Q1
Consider the following 4×1 multiplexer with inputs:
w0=2, w1=1, w2=x2' and w3=0
And with switches:
S1 x1 and S0=x0
What is the multiplexer output f as a function of x2, x1
and x0?
I need help adding a capacitor and a Zener diode to my circuit. I’m looking for a simple sketch or diagram showing how to connect them. i want diagram with final circuit after adding the zener diad and capacitor. don't do calclution or anything. thanks
Chapter 23 Solutions
Electrical Wiring: Residental - With Plans (Paperback) Package
Ch. 23.1 - a. What is the allowance in watts made for...Ch. 23.1 - What are some of the advantages of electric...Ch. 23.1 - List the different types of electric heating...Ch. 23.1 - There are two basic voltage classifications for...Ch. 23.1 - What device is required when the total connected...Ch. 23.1 - Prob. 6RCh. 23.1 - Prob. 7RCh. 23.1 - A certain type of control connects electric...Ch. 23.1 - What advantages does a 240-volt heating unit have...Ch. 23.1 - The white wire of a cable may be used to connect...
Ch. 23.1 - Receptacle outlets furnished as part of a...Ch. 23.1 - The branch circuit supplying a fixed electric...Ch. 23.1 - Prob. 13RCh. 23.1 - For ballpark calculations, the wattage output of a...Ch. 23.1 - A central electric furnace heating system is...Ch. 23.1 - What section of the Code provides the correct...Ch. 23.1 - Electric heating cable embedded in plaster, or...Ch. 23.2 - Prob. 1RCh. 23.2 - Prob. 2RCh. 23.2 - Prob. 3RCh. 23.2 - a. Must an air conditioner installed in a window...Ch. 23.2 - Prob. 5RCh. 23.2 - What is the Code requirement for receptacles...Ch. 23.2 - Prob. 7RCh. 23.2 - When the nameplate on an air-conditioning unit...Ch. 23.2 - Prob. 9RCh. 23.2 - Match the following terms with the statement that...Ch. 23.2 - The disconnect for an air conditioner or heat pump...
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, electrical-engineering and related others by exploring similar questions and additional content below.Similar questions
- Question 3 AC Motor Drives [15]Calculate the instantaneous currents delivered by the inverter if the direct axiscurrent required at a particular instant is 8.66A and the quadrature current is5A. Derive all equations for the three currents.arrow_forwardA certain signal f(t) has the following PSD (assume 12 load): Sp (w) = new + 8(w) - 1.5) + (w + 1.5)] (a) What is the mean power in the bandwidth w≤2 rad/see? (b) What is the mean power in the bandwidth -1.9 to 0.99 rad/sec? Paress(w) dw 2ㅈ -arrow_forward(75 Marks) JA signal (t) is bond 7)(t)(t) and f(t), are band-limited to 1.2 kHz each. These signals are to be limited to 9.6 kHz, and three other signals transmitted by means of time-division multiplexing. Set up scheme for accomplishing this multiplexing requirement, with each signal sampled at its Nyquist rate. What must be the speed of the commutator (the output but ram-k bit/sec)? the minimum band width? (25 Marks)arrow_forward
- Draw the digital modulation outputs, ASK Amplitude Shift Keying) FSK (Frequency Shift Keying) and PSK (Phase Shift Keying). For baseband and carriet frequency as shown 101 wwwwwwwwwwww 010 BASESAND basband CARRIER Carralarrow_forwardplease show full working. I've included the solutionarrow_forwardcan you please show working and steps. The answer is 8kohms.arrow_forward
- PSD A certain signal f(t) has the following PSD (assume 12 load): | Sƒ(w) = π[e¯\w\ + 8(w − 2) + +8(w + 2)] (a) What is the mean power in the bandwidth w≤ 1 rad/sec? (b) What is the mean power in the bandwidth 0.99 to 1.01 rad/sec? (c) What is the mean power in the bandwidth 1.99 to 2.01 rad/sec? (d) What is the total mean power in (t)? Pav= + 2T SfLw) dw - SALW)arrow_forwardAn AM modulation waveform signal:- p(t)=(8+4 cos 1000πt + 4 cos 2000πt) cos 10000nt (a) Sketch the amplitude spectrum of p(t). (b) Find total power, sideband power and power efficiency. (c) Find the average power containing of each sideband.arrow_forwardCan you rewrite the solution because it is unclear? AM (+) = 8(1+ 0.5 cos 1000kt +0.5 ros 2000ks) = cos 10000 πt. 8 cos wat + 4 cos wit + 4 cos Wat coswet. -Jet jooort J11000 t = 4 e jqooort jgoort +4e + e +e j 12000rt. 12000 kt + e +e jooxt igoo t te (w) = 8ES(W- 100007) + 8IS (W-10000) USBarrow_forward
- Can you rewrite the solution because it is unclear? AM (+) = 8(1+0.5 cos 1000kt +0.5 ros 2000 thts) = cos 10000 πt. 8 cos wat + 4 cos wit + 4 cos Wat coswet. J4000 t j11000rt $14+) = 45 jqooort +4e + e + e j 12000rt. 12000 kt + e +e +e Le jsoort -; goon t te +e Dcw> = 885(W- 100007) + 8 IS (W-10000) - USBarrow_forwardCan you rewrite the solution because it is unclear? Q2 AM ①(+) = 8 (1+0.5 cos 1000πt +0.5 ros 2000kt) $4+) = 45 = *cos 10000 πt. 8 cos wat + 4 cosat + 4 cos Wat coswet. j1000016 +4e -j10000πt j11000Rt j gooort -j 9000 πt + e +e j sooort te +e J11000 t + e te j 12000rt. -J12000 kt + с = 8th S(W- 100007) + 8 IS (W-10000) <&(w) = USB -5-5 -4-5-4 b) Pc 2² = 64 PSB = 42 + 4 2 Pt Pc+ PSB = y = Pe c) Puss = PLSB = = 32 4² = 8 w 32+ 8 = × 100% = 140 (1)³×2×2 31 = 20% x 2 = 3w 302 USB 4.5 5 5.6 6 ms Ac = 4 mi = 0.5 mz Ac = 4 ५ M2 = =0.5arrow_forwardA. Draw the waveform for the following binary sequence using Bipolar RZ, Bipolar NRZ, and Manchester code. Data sequence= (00110100) B. In a binary PCM system, the output signal-to-quantization ratio is to be hold to a minimum of 50 dB. If the message is a single tone with fm-5 kHz. Determine: 1) The number of required levels, and the corresponding output signal-to-quantizing noise ratio. 2) Minimum required system bandwidth.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- EBK ELECTRICAL WIRING RESIDENTIALElectrical EngineeringISBN:9781337516549Author:SimmonsPublisher:CENGAGE LEARNING - CONSIGNMENT

EBK ELECTRICAL WIRING RESIDENTIAL
Electrical Engineering
ISBN:9781337516549
Author:Simmons
Publisher:CENGAGE LEARNING - CONSIGNMENT
Introduction to 8051 Microcontroller | Part 1 | Bharat Acharya Education; Author: Bharat Acharya Education;https://www.youtube.com/watch?v=2-geyR_aM28;License: Standard Youtube License