EBK PHYSICS FOR SCIENTISTS AND ENGINEER
6th Edition
ISBN: 9781319321710
Author: Mosca
Publisher: VST
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Chapter 23, Problem 82P
(a)
To determine
The graph between
(b)
To determine
The point of highest electric field strength.
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Problem:
A disk with radius R has uniform surface charge density O. By regarding the disk as a series of thin concentric rings, calculate the electric potential V
at a point on the disk's axis a distance x from the center of the disk. Assume that the potential is zero at infinity.
Answer:
( sqrt(
9) (a) Use Gauss's law to find the electric field inside and outside a long straight wire of radius R with
uniform charge density p
(b) Integrate E to find the potential inside and outside the wire with the boundary condition (R) = 0
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HI Q Q ↓
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5. The figure shows a charged dielectric sphere centered at the origin and touches an infinite line of
charges at x=4 m. The charged line extends along the z-axes as shown. Find the magnitude of the
electric field (in N/C) at x=3 m.
z (m)
y (m)
Q= 10 nC
X=4 m
X (m).
Infinite line charge with A= 4 nC/m
A) 3.22
B) 50.1
C) 72
D) 67.8
E) 4.2
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Chapter 23 Solutions
EBK PHYSICS FOR SCIENTISTS AND ENGINEER
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- From Gauss's law, the electric field set up by a uniform line of charge is E=(20r)r where r is a unit vector pointing radially away from the line and is the linear charge density along the line. Derive an expression for the potential difference between r = r1, and r = r2.arrow_forwardA particle with charge q on the negative x axis and a second particle with charge 2q on the positive x axis are each a distance d from the origin. Where should a third particle with charge 3q be placed so that the magnitude of the electric field at the origin is zero?arrow_forward(a) A uniformly charged cylindrical shell with no end caps has total charge Q, radius R, and length h. Determine the electric potential at a point a distance d from the right end of the cylinder as shown in Figure P24.51. Suggestion: Use the result of Example 24.5 by treating the cylinder as a collection of ring charges. (b) What If? Use the result of Example 24.6 to solve the same problem for a solid cylinder. Figure P24.51arrow_forward
- The electric potential inside a charged spherical conductor of radius R is given by V = keQ/R, and the potential outside is given by V = keQ/R, Using Er = dV/dr, derive the electric field (a) inside and (b) outside this charge distribution.arrow_forwardplease helparrow_forward4) (a)Using the Gauss law find the electric field of an infinite conductor plane with charge density o. (b)Using the result in part (a) calculate the capacitance of a capacitor made of two conducting plane of 2 m² area and with charge density o = these conducting planes are separated with a distance 0.1 mm and there is Aluminium oxide as the dielectric between two plates. 9.6 C/m² andarrow_forward
- Consider a uniformly charged disc of radius 'a' and surface charge density o . Consider a point P on the axis of the disc at a distance z from the disc. The potential at P is given by o 1 (a) Eo z' Va? +z? 26 (b) la². (c) - z² - Va? (d). [H.C.U.-2015]arrow_forwardA thin circular disc of radius a has a total charge Q uniformly distributed over it. It lies in the x - y plane, centered on the origin. The charge density on the disc is p(F) = e ng² 8(2') for x2 + y2 ≤a² and 0 elsewhere. Calculate (a) the electrostatic potential and (b) the electric field at a general point z on the positive z axis.arrow_forwardRa1 +9 -9 Rea Consider two concentric spherical conductors, separated by an isolating material with (absolute) permittivity e. The two conductors have radius R1 and R2, they are put on a potential V and V2, which leads to a charge +q and –q sitting on them, respectively. By the problem's spherical symmetry, we see that the charge on each conductor is distributed uniformly, and that, in spherical coordinates, the electric field between the two conductors is of the form E(r) = -E(r) er. Determine the capacity C using the following steps: 1. Use Gauss's Law in integral form, with N a ball of radius r (R2 < r < R1), to find an expression for E(r) in terms of q. 2. Calculate AV = Vị – V2 using the formula - E•dr Δν and with C the black line segment indicated on the drawing (parallel with e,). 3. The capacity now follows from C = q/AV.arrow_forward
- (Gauss’s Law, Electric Field, Electric Potential and Electric Potential Energy ) with solutionarrow_forwardAn infinitely large plane carries uniform surface charge density o. Find the maximum of the magnitude of the electric potential difference over a distance L. OL/(280) OL/EO OL²/(280) zero Oσd/(20) 00/(280)arrow_forward= 5) A plastic disk of radius R= 80.0 cm is charged on one side with a uniform surface charge density o 9.06 fC/m², and then three quadrants of the disk are removed. The remaining quadrant is shown in Fig. With V=0 at infinity, a) what is the potential due to the remaining quadrant at point P, which is on the central axis of the original disk at distance D=27.8 cm from the original center? b) What is the potential under D>> limit Rarrow_forward
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