(a) Explanation Given Information: The provided matrices are, Age 0 − 10 10 − 30 over 30 ¯ A = Well Sick Carrier [ 0.70 0.70 0.60 0.10 0.20 0.30 0.20 0.10 0.10 ] and Male Female B = [ 60 , 000 65,000 100 , 000 110,000 200 , 000 230,000 ] 0 − 10 10 − 30 over 30 Age The matrix A represents the proportion of people in the city who are either sick, well, or a carrier due to the hit of epidemic flu in the city and the matrix B represents the population in the city according to age and sex. Formula used: The product of two matrixes of order m × n and p × q is possible only if the internal dimensions, that is, n and p are equal. The order of the resultant matrix will be m × q which means, it is determined by the external dimensions of the two matrices. Calculation: Consider two matrices, Age 0 − 10 10 − 30 over 30 ¯ A = Well Sick Carrier [ 0.70 0.70 0.60 0.10 0.20 0.30 0.20 0.10 0.10 ] And, Male Female B = [ 60 , 000 65,000 100 , 000 110,000 200 , 000 230,000 ] 0 − 10 10 − 30 over 30 Age The product of the matrices of order 3 × 3 and 3 × 2 is possible as the internal dimensions, n and p are equal, that is n = p = 3 (b) To determine The number of males who are sick in the city. Where, Age 0 − 10 10 − 30 over 30 ¯ A = Well Sick Carrier [ 0.70 0.70 0.60 0.10 0.20 0.30 0.20 0.10 0.10 ] Male Female B = [ 60 , 000 65,000 100 , 000 110,000 200 , 000 230,000 ] 0 − 10 10 − 30 over 30 Age (c) To determine The number of female carriers in the city. Where, Age 0 − 10 10 − 30 over 30 ¯ A = Well Sick Carrier [ 0.70 0.70 0.60 0.10 0.20 0.30 0.20 0.10 0.10 ] Male Female B = [ 60 , 000 65,000 100 , 000 110,000 200 , 000 230,000 ] 0 − 10 10 − 30 over 30 Age

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Publisher: YUZU

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Question

Chapter 2.3, Problem 74E

(a)

To determine

To calculate: The product of matrix A and matrix B.

Where,

Age 0−10 10−30over 30¯A=WellSickCarrier[ 0.70 0.70 0.600.10 0.20 0.300.20 0.10 0.10 ]

Male FemaleB=[ 60,000 65,000100,000 110,000200,000 230,000 ]0−1010−30over 30 Age

(b)

To determine

The number of males who are sick in the city.

Where,

Age 0−10 10−30over 30¯A=WellSickCarrier[ 0.70 0.70 0.600.10 0.20 0.300.20 0.10 0.10 ] Male FemaleB=[ 60,000 65,000100,000 110,000200,000 230,000 ]0−1010−30over 30 Age

(c)

To determine

The number of female carriers in the city.

Where,

Age 0−10 10−30over 30¯A=WellSickCarrier[ 0.70 0.70 0.600.10 0.20 0.300.20 0.10 0.10 ] Male FemaleB=[ 60,000 65,000100,000 110,000200,000 230,000 ]0−1010−30over 30 Age

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Chapter 2.3, Problem 73E

Chapter 2.3, Problem 75E

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Chapter 2 Solutions

EBK FINITE MATHEMATICS & ITS APPLICATIO

Ch. 2.1 - 1. Determine whether the following systems of...Ch. 2.1 - Give the meaning of each of the following...Ch. 2.1 - 3. Perform the indicated elementary row...Ch. 2.1 - State the next elementary row operation that...Ch. 2.1 - In Exercises 1–8, perform the indicated elementary...Ch. 2.1 - Prob. 2E Ch. 2.1 - In Exercises 1–8, perform the indicated elementary...Ch. 2.1 - In Exercises 1–8, perform the indicated elementary...Ch. 2.1 - In Exercises 18, perform the indicated elementary...Ch. 2.1 - In Exercises 18, perform the indicated elementary...

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The product of matrix A and matrix B . Where, Age 0 − 10 10 − 30 over 30 ¯ A = Well Sick Carrier [ 0.70 0.70 0.60 0.10 0.20 0.30 0.20 0.10 0.10 ] Male Female B = [ 60 , 000 65,000 100 , 000 110,000 200 , 000 230,000 ] 0 − 10 10 − 30 over 30 Age

Solution Summary: The author explains that the product of matrix A and matrix B is left[cc232,000& 260,500 86,000&

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To calculate: The product of matrix A and matrix B.

Where,

Age 0−10 10−30over 30¯A=WellSickCarrier[ 0.70 0.70 0.600.10 0.20 0.300.20 0.10 0.10 ]

Male FemaleB=[ 60,000 65,000100,000 110,000200,000 230,000 ]0−1010−30over 30 Age

The number of males who are sick in the city.

Where,

Age 0−10 10−30over 30¯A=WellSickCarrier[ 0.70 0.70 0.600.10 0.20 0.300.20 0.10 0.10 ] Male FemaleB=[ 60,000 65,000100,000 110,000200,000 230,000 ]0−1010−30over 30 Age

The number of female carriers in the city.

Where,

Age 0−10 10−30over 30¯A=WellSickCarrier[ 0.70 0.70 0.600.10 0.20 0.300.20 0.10 0.10 ] Male FemaleB=[ 60,000 65,000100,000 110,000200,000 230,000 ]0−1010−30over 30 Age

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Chapter 2 Solutions

The product of matrix A and matrix B . Where, Age 0 − 10 10 − 30 over 30 ¯ A = Well Sick Carrier [ 0.70 0.70 0.60 0.10 0.20 0.30 0.20 0.10 0.10 ] Male Female B = [ 60 , 000 65,000 100 , 000 110,000 200 , 000 230,000 ] 0 − 10 10 − 30 over 30 Age

Solution Summary: The author explains that the product of matrix A and matrix B is left[cc232,000& 260,500 86,000&

Concept explainers

Videos

To calculate: The product of matrix A and matrix B. Where, Age 0−10 10−30over 30¯A=WellSickCarrier[ 0.70 0.70 0.600.10 0.20 0.300.20 0.10 0.10 ] Male FemaleB=[ 60,000 65,000100,000 110,000200,000 230,000 ]0−1010−30over 30 Age

The number of males who are sick in the city. Where, Age 0−10 10−30over 30¯A=WellSickCarrier[ 0.70 0.70 0.600.10 0.20 0.300.20 0.10 0.10 ] Male FemaleB=[ 60,000 65,000100,000 110,000200,000 230,000 ]0−1010−30over 30 Age

The number of female carriers in the city. Where, Age 0−10 10−30over 30¯A=WellSickCarrier[ 0.70 0.70 0.600.10 0.20 0.300.20 0.10 0.10 ] Male FemaleB=[ 60,000 65,000100,000 110,000200,000 230,000 ]0−1010−30over 30 Age

Want to see the full answer?

Chapter 2 Solutions

To calculate: The product of matrix A and matrix B.

Where,

Age 0−10 10−30over 30¯A=WellSickCarrier[ 0.70 0.70 0.600.10 0.20 0.300.20 0.10 0.10 ]

Male FemaleB=[ 60,000 65,000100,000 110,000200,000 230,000 ]0−1010−30over 30 Age

The number of males who are sick in the city.

Where,

Age 0−10 10−30over 30¯A=WellSickCarrier[ 0.70 0.70 0.600.10 0.20 0.300.20 0.10 0.10 ] Male FemaleB=[ 60,000 65,000100,000 110,000200,000 230,000 ]0−1010−30over 30 Age

The number of female carriers in the city.

Where,

Age 0−10 10−30over 30¯A=WellSickCarrier[ 0.70 0.70 0.600.10 0.20 0.300.20 0.10 0.10 ] Male FemaleB=[ 60,000 65,000100,000 110,000200,000 230,000 ]0−1010−30over 30 Age