
Concept explainers
(a)
The width of the image on the screen.
(a)

Answer to Problem 68P
The width of the image on the screen is
Explanation of Solution
Given that the focal length of the lens is
Write the thin lens formula.
Here,
Solve equation (I) for
Write the expression for the magnification of the image in terms of object distance and image distance.
Here,
Write the expression for magnification of image in terms of height of object and image.
Here,
Equate the right hand sides of equations (III) and (IV) and solve for
Conclusion:
Substitute
Substitute
Therefore, the width of the image on the screen is
(b)
The type of the lens which is used in the projector.
(b)

Answer to Problem 68P
The type of the lens which is used in the projector is converging lens.
Explanation of Solution
A converging lens will produce a virtual image when the object is located in front of the focal point. The focal length of the lens is positive quantity. It means that the focal point of the lens is on the other side of the lens from where the object is placed. A positive focal length means a lens is convex, capable of forming a real image.
Conclusion:
Therefore, the type of the lens which is used in the projector is
(c)
Whether the image on the screen upright or inverted compared with the film.
(c)

Answer to Problem 68P
The image on the screen is
Explanation of Solution
If the height of the image formed by the lens is
Conclusion:
Therefore, the image on the screen is
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Chapter 23 Solutions
Physics
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