Chapter 23, Problem 63EAP

In Problems 63 through 66 you are given the equation(s) used to solve a problem. For each of these

a. Write a realistic problem for which this is the correct equation(s).

b. Finish the solution of the problem.

$63.(9.0\times {10}^{9}N{m}^2/C^2)\frac{(2.0\times {10}^{-9}C)s}{{(0.025m)}^3}=1150N/C$

$64.(9.0\times {10}^{9}N{m}^2/C^2)\frac{2(2.0\times {10}^{-7}C/m)}{r}=25,000N/C$

$65.\frac{\eta }{2{\in }_0}\left[1-\frac{z}{\sqrt{z^2+R^2}}\right]=\frac{1}{2}\frac{\eta }{2{\in }_0}$

$\mathrm{66.2.0}\times {10}^{12}m/s^2=\frac{(1.60\times {10}^{-19}C)E}{(1.67\times {10}^{-27}kg)}$

$E=\frac{Q}{(8.85\times {10}^{-12}{C}^2/N{m}^2){(0.020m)}^2}$