
Concept explainers
(a)
To find: The number of visits it would take for the total cost to be the same for a member and a nonmember, if they both use the water park at each visit.
(a)

Answer to Problem 51PPS
The number of visits it would take for the total cost to be the same for a member and a nonmember, if they both use the water park at each visit is
Explanation of Solution
Given information:
An Amusement park details:
Line 1: Yearly membership charge
Line 2: And additional charge for use Water Park
Line 3: Nonmember pays
Calculation:
The equation to find the number of visits it would take for the total cost to be the same for a member and a nonmember if they both use the water park at each visit is to be written and solved.
Consider the number of visits to the park be
The cost for
The cost for
Acc. To equation,
Therefore, the required equation to find the number of visits it would take for the total cost to be the same for member and a nonmember if they both use the water park at each visit is
Now solving the equation:
Therefore, the number of visits it would take for the total cost to be the same for a member and a nonmember, if they both use the water park at each visit is
(b)
To find: Design a table for the costs of members and nonmembers after
(b)

Answer to Problem 51PPS
The table for the costs of members and nonmembers after
visits to the park is :
Visits | Cost for Members | Cost for nonmembers |
3 | 290 | 90 |
6 | 305 | 180 |
9 | 320 | 270 |
12 | 225 | 360 |
15 | 350 | 450 |
Explanation of Solution
Given information:
An Amusement park details:
Line 1: Yearly membership charge
Line 2: And additional charge for use Water Park
Line 3: Nonmember pays
Calculation:
The table for the cost of members and nonmembers after
For 3 visits,
And,
For
And,
For
And,
For
And,
For
And,
Now, the table for the cost of members and nonmembers after
visits to the park is as follows:
Visits | Cost for Members | Cost for nonmembers |
3 | 290 | 90 |
6 | 305 | 180 |
9 | 320 | 270 |
12 | 225 | 360 |
15 | 350 | 450 |
Chapter 2 Solutions
Algebra 1
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