Concept explainers
(a)
Calculate the range of the index of refraction of the material for visible light.
Answer to Problem 49QAP
Refractive index for visible light ranges from
Explanation of Solution
Given:
For a certain optical medium the
Concept Used:
The relationship between refractive index and the speed of light is given as follows:
Where
Calculation:
As per the given problem,
Speed of violet light,
Speed of red light,
Refractive index corresponding to violet light
Refractive index corresponding to red light
Conclusion:
Refractive index for visible light ranges from
(b)
A white light is incident on the medium from air, making an angle of 30.0° with the normal. Compare the angles of refraction for violet light and red light.
Answer to Problem 49QAP
Angle of refraction for violet light=
Angle of refraction for red light=
Explanation of Solution
Given:
For a certain optical medium the speed of light varies from a low value of
Formula used:
Snell's law or the law of refraction is expressed as
Where
Calculation:
As per the given problem, medium 1 is air and medium 2 is the optical medium.
Angle of incidence,
Refractive index of violet light,
Substituting the values of
Refractive index of red light,
Substituting the values of
Conclusion:
Angle of refraction for violet light=
Angle of refraction for red light=
(c)
Repeat the previous part when the incident angle is 60.0°.
Answer to Problem 49QAP
Explanation of Solution
Given:
For a certain optical medium the speed of light varies from a low value of
Formulaused:
Snell's law or the law of refraction is expressed as
Where
Calculation:
As per the given problem, medium 1 is air and medium 2 is the optical medium.
Angle of incidence,
Refractive index of violet light,
Substituting the values of
Refractive index of red light,
Substituting the values of
Conclusion:
Angle of refraction for violet light=
Angle of refraction for red light=
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Chapter 23 Solutions
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