Explanation Given Info : Let refractive index of liquid be n l i q u i d Refractive index of air n a i r = 1.0 Liquid depth ‘D’ = 8.0 cm Let the angle of the incident (critical angle) be ∠ i = ∠ c The distance from just above the spot to the strike point, d = 7.6 cm at a critical angle. Angle of refraction ∠ r = 90 0 Formula Used: Apply Snell’s Law n l i q u i d sin ∠ i = n a i r sin ∠ r n l i q u i d sin ∠ c = n a i r sin 90 0 Here, all alphabets are in their usual meanings. Calculation: Now, we shall calculate the critical angle tan ∠ c = d D tan ∠ c = 7 .6 cm 8 .0 cm o r , ∠ c = 43

7th Edition

ISBN: 2818440071355

Author: GIANCOLI

Publisher: PEARSON

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Chapter 23, Problem 38P

To determine

The refractive index of the liquid.

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Chapter 23, Problem 37P

Chapter 23, Problem 39P

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Chapter 23 Solutions

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