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(a)
Interpretation:
Whether C2H6forms an addition or
Concept Introduction:
A polymer is a long chain molecule made of large number of monomer units. The monomer is repeating units of a polymer that are linked to each other to produce a molecule of polymer.
These monomer units are linked to each other either through the formation of peptide linkage or glycosidic linkage or by removal of any moiety such as a water molecule.
Polyvinyl chloride, Bakelite and polystyrene are some of the example of
(b)
Interpretation:
Whether C2H4forms an addition or condensation polymer needs to be determined.
Concept Introduction:
A polymer is a long chain molecule made of large number of monomer units. The monomer is repeating units of a polymer that are linked to each other to produce a molecule of polymer.
These monomer units are linked to each other either through the formation of peptide linkage or glycosidic linkage or by removal of any moiety such as a water molecule.
Polyvinyl chloride, Bakelite and polystyrene are some of the example of polymers.
(c)
Interpretation:
Whether OH-CH2- CH2-OH forms an addition or condensation polymer needs to be determined.
Concept Introduction:
A polymer is a long chain molecule made of large number of monomer units. The monomer is repeating units of a polymer that are linked to each other to produce a molecule of polymer.
These monomer units are linked to each other either through the formation of peptide linkage or glycosidic linkage or by removal of any moiety such as a water molecule.
Polyvinyl chloride, Bakelite and polystyrene are some of the example of polymers.
(d)
Interpretation:
Whether OH-CH2- CH3 forms an addition or condensation polymer needs to be determined.
Concept Introduction:
A polymer is a long chain molecule made of large number of monomer units. The monomer is repeating units of a polymer that are linked to each other to produce a molecule of polymer.
These monomer units are linked to each other either through the formation of peptide linkage or glycosidic linkage or by removal of any moiety such as a water molecule.
Polyvinyl chloride, Bakelite and polystyrene are some of the example of polymers.
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Chapter 23 Solutions
OWLv2 with Student Solutions Manual eBook for Masterton/Hurley's Chemistry: Principles and Reactions, 8th Edition, [Instant Access], 4 terms (24 months)
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- State the name and condensed formula of isooxazole obtained by reacting acetylacetone and hydroxylamine.arrow_forwardState the name and condensed formula of the isothiazole obtained by reacting acetylacetone and thiosemicarbazide.arrow_forwardProvide the semi-developed formula of isooxazole obtained by reacting acetylacetone and hydroxylamine.arrow_forward
- Given a 1,3-dicarbonyl compound (R1-CO-CH2-CO-R2), indicate the formula of the compound obtaineda) if I add hydroxylamine (NH2OH) to give an isooxazole.b) if I add thiosemicarbazide (NH2-CO-NH-NH2) to give an isothiazole.arrow_forwardAn orange laser has a wavelength of 610 nm. What is the energy of this light?arrow_forwardThe molar absorptivity of a protein in water at 280 nm can be estimated within ~5-10% from its content of the amino acids tyrosine and tryptophan and from the number of disulfide linkages (R-S-S-R) between cysteine residues: Ε280 nm (M-1 cm-1) ≈ 5500 nTrp + 1490 nTyr + 125 nS-S where nTrp is the number of tryptophans, nTyr is the number of tyrosines, and nS-S is the number of disulfide linkages. The protein human serum transferrin has 678 amino acids including 8 tryptophans, 26 tyrosines, and 19 disulfide linkages. The molecular mass of the most dominant for is 79550. Predict the molar absorptivity of transferrin. Predict the absorbance of a solution that’s 1.000 g/L transferrin in a 1.000-cm-pathlength cuvet. Estimate the g/L of a transferrin solution with an absorbance of 1.50 at 280 nm.arrow_forward
- In GC, what order will the following molecules elute from the column? CH3OCH3, CH3CH2OH, C3H8, C4H10arrow_forwardBeer’s Law is A = εbc, where A is absorbance, ε is the molar absorptivity (which is specific to the compound and wavelength in the measurement), and c is concentration. The absorbance of a 2.31 × 10-5 M solution of a compound is 0.822 at a wavelength of 266 nm in a 1.00-cm cell. Calculate the molar absorptivity at 266 nm.arrow_forwardHow to calculate % of unknown solution using line of best fit y=0.1227x + 0.0292 (y=2.244)arrow_forward
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