Quantitative Chemical Analysis 9e And Sapling Advanced Single Course For Analytical Chemistry (access Card)
Quantitative Chemical Analysis 9e And Sapling Advanced Single Course For Analytical Chemistry (access Card)
9th Edition
ISBN: 9781319090241
Author: Daniel C. Harris, Sapling Learning
Publisher: W. H. Freeman
Question
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Chapter 23, Problem 23.FE

(a)

Interpretation Introduction

Interpretation:

The retention factor of compound 2 has to be calculated.

Concept introduction:

Retention factor:

The retention factor (k) is given by

k=tr-tmtmWhere,k-retentionfactortr-timerequiredtoelutethepeaktm-timerequiredformobilephasetopassthroughthecolumn.

(a)

Expert Solution
Check Mark

Answer to Problem 23.FE

  • The retention factor of compound 2 is 5.511.

Explanation of Solution

Given information,

The value of relative retention (α) is 1.068 .

The value of retention factor for compound 1 (k1) is 5.16 .

Calculate the value of k2 by using the relationship between αandk

α=k2k1k2=αk1=(1.068)(5.16)=5.511

The retention factor of compound 2 is 5.511.

(b)

Interpretation Introduction

Interpretation:

The length (L) of the column has to be calculated.

Concept introduction:

Purnell equation:

The relationship between Handα is given by Purnell equation,

Resolution=N4(α-1)α(k21+k2)Where,N-numberoftheoreticalplatesα-relativeretentionofthetwopeaksk2-retentionfactorofthemoreretainedcomponent

(b)

Expert Solution
Check Mark

Answer to Problem 23.FE

  • The length of the column is 6.45m.

Explanation of Solution

Given information,

The value of α is 1.068 .

The value of k2 is 5.511 .

Height of the plate is 0.520mm.

Calculate the number (N) of plates on column by Purnell equation

Resolution=N4(α-1)α(k21+k2)1.5=N4(1.068-1)1.068(5.5111+5.511)N=4×1.5(0.8464)(0.0637)=60.0539=111.32N=12392=1.24×104plates

Calculate the length (L) of the column

H=LengthofthecolumnNumberofplatesoncolumn=LNL=H×N=0.520mm×1.24×104=6448mm=6.45m.

The length of the column is 6.45m.

(c)

Interpretation Introduction

Interpretation:

The values of trandw1/2 has to be calculated for the given peaks.

Concept introduction:

Plates of column:

The relationship between Nandw1/2

N=5.55tr2w1/22Where,N-numberofplatesoncolumntr-retentiontimew1/2-half-width

(c)

Expert Solution
Check Mark

Answer to Problem 23.FE

  • The value of tr for the compound 1 is 12.32min.
  • The value of tr for the compound 2 is 13.02min.
  • The value of w1/2 for the compound 1 is 0.261min.
  • The value of w1/2 for the compound 2 is 0.275min.

Explanation of Solution

Given information,

The value of α is 1.068 .

The value of k1 is 5.16 .

The value of k2 is 5.511 .

The value of N is 1.24×104 .

Calculate the value of tr for the compound 1 by using the relation between retention factor and retention time

k1=(t1-tm)tm=t1tm-1t1=tm(k1+1)=tm(6.16)=(2.00min)(6.16)=12.32min

The value of tr for the compound 1 is 12.32min.

Calculate the value of tr for the compound 2 by using the relation between retention factor and retention time

k2=(t2-tm)tm=t2tm-1t2=tm(k2+1)=tm(6.511)=(2.00min)(6.511)=13.02min

The value of tr for the compound 2 is 13.02min.

Calculate the value of w1/2 for the compound 1 by using the relationship between Nandw1/2

N=5.55tr2w1/22w1/2=5.55N×tr=5.551.24×104×(12.32min)=0.261min.

The value of w1/2 for the compound 1 is 0.261min.

Calculate the value of w1/2 for the compound 2 by using the relationship between Nandw1/2

N=5.55tr2w1/22w1/2=5.55N×tr=5.551.24×104×(13.02min)=0.275min.

The value of w1/2 for the compound 2 is 0.275min.

(d)

Interpretation Introduction

Interpretation:

The partition coefficient value for compound 1 has to be calculated.

Concept introduction:

Partition coefficient:

The relationship between retention factor and partition coefficient is given by

k=KVsVmWhere,k-retentionfactorK-partitioncoefficientVs-volumeofstationaryphaseVm-volumeofmobilephase

(d)

Expert Solution
Check Mark

Answer to Problem 23.FE

  • The partition coefficient value for compound 1 is 17.2.

Explanation of Solution

Given information,

The value of Vs/Vm is 0.30 .

The value of k1 is 5.16 .

Calculate the value of K1 for the compound 1 by using the relation between retention factor and partition coefficient

K1=k1VmVs=(5.16)(1/0.30)=17.2

The partition coefficient value for compound 1 is 17.2.

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