(a)
Interpretation:
The most likely site(s) of electrophilic
Concept introduction:
Electrophilic aromatic substitution reaction rate increases with increase in electron density around the ring. The electron donating groups activates whereas the electron withdrawing groups deactivates the aromatic ring. The electron donating groups increases the electron density at ortho-para position and thus they are ortho-para directing. The electron withdrawing groups decrease electron density at ortho/para and has comparatively greater electron density at meta position, thus they are meta directing.
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Answer to Problem 23.53P
The most likely site(s) electrophilic aromatic substitution in the given molecule is:
Explanation of Solution
The given molecule is:
In the given molecule, benzene has two methoxy substituents. These are activating groups, thus ortho-para directors. Each methoxy group activates their two ortho and one para positions. The activated sites are same for both groups, thus overall there are three activated sites. But the position between two methoxy groups is sterically hindered. Thus, the molecules have only two possible sites of electrophilic aromatic substitution which are indicated by an asterisk
The most likely site(s) of electrophilic aromatic substitution are determined by identifying positions activated by the substituents attached.
(b)
Interpretation:
The most likely site(s) of electrophilic aromatic substitution in the given molecule are to be indicated.
Concept introduction:
Electrophilic aromatic substitution reaction rate increases with increase in electron density around the ring. The electron donating groups activate whereas the electron withdrawing groups deactivate the aromatic ring. The electron donating groups increase the electron density at ortho-para position and thus they are ortho-para directing. The electron withdrawing groups decreases electron density at ortho/para and has comparatively greater electron density at meta position, thus they are meta directing.
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Answer to Problem 23.53P
The most likely site(s) of electrophilic aromatic substitution in the given molecule are:
Explanation of Solution
The given molecule is:
In the given molecule, benzene has one hydroxyl and one chloride substituent. Both these are activating groups, thus ortho-para directors. Each of the susbtituents activates their two ortho and one para positions. The activated sites are same for both groups thus overall there are three activated sites. But the position between these two substituents is sterically hindered. Thus, molecules have only two possible sites of electrophilic aromatic substitution which are indicated by an asterisk
The most likely site(s) of electrophilic aromatic substitution are determined by identifying positions activated by the substituents attached.
(c)
Interpretation:
The most likely site(s) of electrophilic aromatic substitution in the given molecule are to be indicated.
Concept introduction:
The electrophilic aromatic substitution reaction rate increases with increase in electron density around the ring. The electron donating groups activates whereas the electron withdrawing groups deactivates the aromatic ring. The electron donating groups increase the electron density at ortho-para position and thus they are ortho-para directing. The electron withdrawing groups decrease electron density at ortho/para and have comparatively greater electron density at meta position, thus they are meta directing.
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Answer to Problem 23.53P
The most likely site(s) of electrophilic aromatic substitution in the given molecule are:
Explanation of Solution
The given molecule is:
In the given molecule, benzene has one acetyl and one bromide substituent. Acetyl is carbonyl group which is deactivating thus it is meta director. The bromine atom is activating group thus it is ortho/para director. The acetyl group activates its two meta positions and bromine activates its one ortho and one para positions. The meta positions of acetyl group are same as the ortho/para position of bromine atom. Thus the molecules have only two possible sites of electrophilic aromatic substitution which are indicated by an asterisk
The most likely site(s) of electrophilic aromatic substitution are determined by identifying positions activated by the substituents attached.
(d)
Interpretation:
The most likely site(s) of electrophilic aromatic substitution in the given molecule are to be indicated.
Concept introduction:
The electrophilic aromatic substitution reaction rate increases with increase in electron density around the ring. The electron donating groups activates whereas the electron withdrawing groups deactivates the aromatic ring. The electron donating groups increases the electron density at ortho-para position and thus they are ortho-para directing. The electron withdrawing groups decreases electron density at ortho/para and has comparatively greater electron density at meta position, thus they are meta directing.
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Answer to Problem 23.53P
The most likely site(s) of electrophilic aromatic substitution in the given molecule are:
Explanation of Solution
The given molecule is:
In the given molecule, benzene has one acetyl and one bromide substituent. Acetyl is carbonyl group which is deactivating thus it is meta director. The bromine atom is activating group thus it is ortho/para director.
The acetyl group activates its one meta positions and bromine activates two ortho and one para positions. The activating sites of both groups are different, thus overall there are three activated sites. But the position between these two substituents is sterically hindered. Thus, molecules have only two possible sites of electrophilic aromatic substitution which are indicated by an asterisk
The most likely site(s) of electrophilic aromatic substitution are determined by identifying positions activated by the substituents attached.
(e)
Interpretation:
The most likely site(s) of electrophilic aromatic substitution in the given molecule are to be indicated.
Concept introduction:
The electrophilic aromatic substitution reaction rate increases with increase in electron density around the ring. The electron donating groups activates whereas the electron withdrawing groups deactivates the aromatic ring. The electron donating groups increases the electron density at ortho-para position and thus they are ortho-para directing. The electron withdrawing groups decreases electron density at ortho/para and has comparatively greater electron density at meta position, thus they are meta directing.
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Answer to Problem 23.53P
The most likely site(s) of electrophilic aromatic substitution in the given molecule are:
Explanation of Solution
The given molecule is:
In the given molecule, benzene has one nitro and one methyl substituent. Nitro group is deactivating thus it is meta director. The methyl group is activating group thus it is ortho/para director. The nitro group activates its two meta positions and methyl group activates its one ortho and one para positions. The meta positions of nitro group are same as the ortho/para positions of methyl groups. Thus, the molecules have only two possible sites of electrophilic aromatic substitution which are indicated by an asterisk
The most likely site(s) of electrophilic aromatic substitution are determined by identifying positions activated by the substituents attached.
(f)
Interpretation:
The most likely site(s) of electrophilic aromatic substitution in the given molecule are to be indicated.
Concept introduction:
The electrophilic aromatic substitution reaction rate increases with increase in electron density around the ring. The electron donating groups activates whereas the electron withdrawing groups deactivates the aromatic ring. The electron donating groups increases the electron density at ortho-para position and thus they are ortho-para directing. The electron withdrawing groups decreases electron density at ortho/para and has comparatively greater electron density at meta position, thus they are meta directing.
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Answer to Problem 23.53P
The most likely site(s) of electrophilic aromatic substitution in the given molecule are:
Explanation of Solution
The given molecule is:
In the given molecule, benzene has one methyl and one
The most likely site(s) of electrophilic aromatic substitution are determined by identifying positions activated by the substituents attached.
(g)
Interpretation:
The most likely site(s) of electrophilic aromatic substitution in the given molecule are to be indicated.
Concept introduction:
The electrophilic aromatic substitution reaction rate increases with increase in electron density around the ring. The electron donating groups activates whereas the electron withdrawing groups deactivates the aromatic ring. The electron donating groups increases the electron density at ortho-para position and thus they are ortho-para directing. The electron withdrawing groups decreases electron density at ortho/para and has comparatively greater electron density at meta position, thus they are meta directing.
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Answer to Problem 23.53P
The most likely site(s) of electrophilic aromatic substitution in the given molecule are:
Explanation of Solution
The given molecule is:
In the given molecule, benzene has one methyl and one amino substituent. They both are activating groups, thus they are ortho/para positions. Each of the susbtituents activates their two ortho and one para positions. The some activated sites are not same for both groups so, overall there are three activated sites. But the position between two groups is sterically hindered. Thus, molecules have only two possible sites of electrophilic aromatic substitution which are indicated by an asterisk
The most likely site(s) of electrophilic aromatic substitution are determined by identifying positions activated by the substituents attached.
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Chapter 23 Solutions
ORGANIC CHEMISTRY PRINCIPLES & MECHANISM
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- Please correct answer and don't used hand raitingarrow_forwardreciprocal lattices rotates along with the real space lattices of the crystal. true or false?arrow_forwardDeducing the reactants of a Diels-Alder reaction vn the molecule on the right-hand side of this organic reaction be made in good yield from no more than two reactants, in one step, by moderately heating the reactants? ? Δ O If your answer is yes, then draw the reactant or reactants in the drawing area below. You can draw the reactants in any arrangement you like. • If your answer is no, check the box under the drawing area instead. Click and drag to start drawing a structure. Product can't be made in one step. Explanation Checkarrow_forward
- Predict the major products of the following organic reaction: Δ ? Some important notes: • Draw the major product, or products, of the reaction in the drawing area below. • If there aren't any products, because no reaction will take place, check the box below the drawing area instead. • Be sure to use wedge and dash bonds when necessary, for example to distinguish between major products that are enantiomers. Explanation Check Click and drag to start drawing a structure. Larrow_forward> Can the molecule on the right-hand side of this organic reaction be made in good yield from no more than two reactants, in one step, by moderately heating the reactants? ? Δ • If your answer is yes, then draw the reactant or reactants in the drawing area below. You can draw the reactants in any arrangement you like. If your answer is no, check the box under the drawing area instead. Explanation Check Click and drag to start drawing a structure. Х © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accesarrow_forwardPredict the major products of the following organic reaction: O O + A ? Some important notes: • Draw the major product, or products, of the reaction in the drawing area below. • If there aren't any products, because no reaction will take place, check the box below the drawing area instead. • Be sure to use wedge and dash bonds when necessary, for example to distinguish between major products that are enantiomers. Explanation Check Click and drag to start drawing a structure. eserved. Terms of Use | Privacy Center >arrow_forward
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