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Chemistry, Books a la Carte Edition and Modified Mastering Chemistry with Pearson eText & ValuePack Access Card (7th Edition)
7th Edition
ISBN: 9780134172514
Author: John E. McMurry
Publisher: PEARSON
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Question
Chapter 23, Problem 23.18P
a.
Interpretation Introduction
To determine: If the given fatty acid are in cis or trans configuration
Explanation:
Compound a is a trans isomer because here the similar groups i.e., the H atoms and the alkyl substituents are in the opposite orientation in the adjacent carbons of the compound.
b.
To determine: If the given fatty acid is in cis or trans configuration
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Explanation:
Compound b is a cis isomer because here the similar groups i.e., the H atoms and the alkyl substituents are in the same orientation in the adjacent carbons of the compound.
Conclusion:
Hence
a. Compound a is trans isomer.
b. Compound b is cis isomer
b.
Interpretation Introduction
To determine: If the given fatty acid is in cis or trans configuration
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Expert Solution & Answer
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Students have asked these similar questions
From the given compound, choose the proton that best fits each given description.
a
CH2
CH 2
Cl
b
с
CH2
F
Most shielded:
(Choose one)
Least shielded:
(Choose one)
Highest chemical shift:
(Choose one)
Lowest chemical shift:
(Choose one)
×
Consider this molecule:
How many H atoms are in this molecule?
How many different signals could be found in its 1H NMR spectrum?
Note: A multiplet is considered one signal.
For each of the given mass spectrum data, identify whether the compound contains chlorine, bromine, or neither.
Compound
m/z of M* peak
m/z of M
+ 2 peak
ratio of M+ : M
+ 2 peak
Which element is present?
A
122
no M
+ 2 peak
not applicable
(Choose one)
B
78
80
3:1
(Choose one)
C
227
229
1:1
(Choose one)
Chapter 23 Solutions
Chemistry, Books a la Carte Edition and Modified Mastering Chemistry with Pearson eText & ValuePack Access Card (7th Edition)
Ch. 23 - Prob. 23.1PCh. 23 - Prob. 23.2ACh. 23 - Prob. 23.3PCh. 23 - Prob. 23.4ACh. 23 - Prob. 23.5PCh. 23 - Prob. 23.6PCh. 23 - Prob. 23.7PCh. 23 - Prob. 23.8ACh. 23 - Prob. 23.9PCh. 23 - Prob. 23.10A
Ch. 23 - Prob. 23.11PCh. 23 - Prob. 23.12PCh. 23 - Prob. 23.13ACh. 23 - Prob. 23.14PCh. 23 - Prob. 23.15ACh. 23 - Prob. 23.16PCh. 23 - Prob. 23.17ACh. 23 - Prob. 23.18PCh. 23 - Prob. 23.19PCh. 23 - Prob. 23.20ACh. 23 - Prob. 23.21PCh. 23 - Prob. 23.22ACh. 23 - Prob. 23.23PCh. 23 - Prob. 23.24ACh. 23 - Prob. 23.25PCh. 23 - Prob. 23.26PCh. 23 - Prob. 23.27ACh. 23 - Prob. 23.28PCh. 23 - Prob. 23.29ACh. 23 - Prob. 23.30PCh. 23 - Prob. 23.31ACh. 23 - Prob. 23.32PCh. 23 - Prob. 23.33PCh. 23 - Prob. 23.34PCh. 23 - Prob. 23.35CPCh. 23 - Prob. 23.36CPCh. 23 - Prob. 23.37CPCh. 23 - Prob. 23.38CPCh. 23 - Prob. 23.39CPCh. 23 - Prob. 23.40CPCh. 23 - Prob. 23.41CPCh. 23 - Prob. 23.42SPCh. 23 - Prob. 23.43SPCh. 23 - Prob. 23.44SPCh. 23 - Prob. 23.45SPCh. 23 - Prob. 23.46SPCh. 23 - Prob. 23.47SPCh. 23 - Prob. 23.48SPCh. 23 - Prob. 23.49SPCh. 23 - Prob. 23.50SPCh. 23 - Prob. 23.51SPCh. 23 - Prob. 23.52SPCh. 23 - Prob. 23.53SPCh. 23 - Prob. 23.54SPCh. 23 - Prob. 23.55SPCh. 23 - Prob. 23.56SPCh. 23 - Prob. 23.57SPCh. 23 - Prob. 23.58SPCh. 23 - Prob. 23.59SPCh. 23 - Prob. 23.60SPCh. 23 - Prob. 23.61SPCh. 23 - Prob. 23.62SPCh. 23 - Prob. 23.63SPCh. 23 - Prob. 23.64SPCh. 23 - Prob. 23.65SPCh. 23 - Prob. 23.66SPCh. 23 - Prob. 23.67SPCh. 23 - Prob. 23.68SPCh. 23 - Prob. 23.69SPCh. 23 - Prob. 23.70SPCh. 23 - Prob. 23.71SPCh. 23 - Prob. 23.72SPCh. 23 - Prob. 23.73SPCh. 23 - Prob. 23.74SPCh. 23 - Prob. 23.75SPCh. 23 - Prob. 23.76SPCh. 23 - Prob. 23.77SPCh. 23 - Prob. 23.78SPCh. 23 - Prob. 23.79SPCh. 23 - Prob. 23.80SPCh. 23 - Prob. 23.81SPCh. 23 - Prob. 23.82SPCh. 23 - Prob. 23.83SPCh. 23 - Prob. 23.84SPCh. 23 - Prob. 23.85SPCh. 23 - Prob. 23.86SPCh. 23 - Prob. 23.87SPCh. 23 - Prob. 23.88SPCh. 23 - Prob. 23.89SPCh. 23 - Prob. 23.90SPCh. 23 - Prob. 23.91SPCh. 23 - Prob. 23.92SPCh. 23 - Draw the structure of a fatty acid with a lipid...Ch. 23 - Prob. 23.94SPCh. 23 - Prob. 23.95SPCh. 23 - Prob. 23.96SPCh. 23 - Prob. 23.97SPCh. 23 - Prob. 23.98SPCh. 23 - Prob. 23.99SPCh. 23 - Prob. 23.100SPCh. 23 - Prob. 23.101SPCh. 23 - Prob. 23.102SPCh. 23 - Prob. 23.103SPCh. 23 - Prob. 23.104SPCh. 23 - Prob. 23.105SPCh. 23 - Prob. 23.106SPCh. 23 - Prob. 23.107SPCh. 23 - Prob. 23.108SPCh. 23 - Prob. 23.109SPCh. 23 - Prob. 23.110SPCh. 23 - Prob. 23.111SPCh. 23 - Prob. 23.112SPCh. 23 - In the following molecules, indicate which atoms...Ch. 23 - Prob. 23.114SPCh. 23 - Prob. 23.115SPCh. 23 - Prob. 23.116SPCh. 23 - Prob. 23.117SPCh. 23 - Prob. 23.118SPCh. 23 - Prob. 23.119SPCh. 23 - Prob. 23.120SPCh. 23 - Prob. 23.121SPCh. 23 - Prob. 23.122SPCh. 23 - Prob. 23.123SPCh. 23 - Prob. 23.124SPCh. 23 - Prob. 23.125SPCh. 23 - Prob. 23.126SPCh. 23 - Prob. 23.127SPCh. 23 - Prob. 23.128SPCh. 23 - Prob. 23.129SPCh. 23 - Prob. 23.130SPCh. 23 - Prob. 23.131SPCh. 23 - Prob. 23.132SPCh. 23 - Prob. 23.133SPCh. 23 - Prob. 23.134SPCh. 23 - Prob. 23.135SPCh. 23 - Prob. 23.136CPCh. 23 - Prob. 23.137CPCh. 23 - Prob. 23.138CPCh. 23 - Prob. 23.139CPCh. 23 - Prob. 23.140CPCh. 23 - Prob. 23.141CPCh. 23 - Prob. 23.142CPCh. 23 - Prob. 23.143CPCh. 23 - Prob. 23.144CPCh. 23 - Prob. 23.145CPCh. 23 - Prob. 23.146CPCh. 23 - Prob. 23.147CPCh. 23 - Prob. 23.148CPCh. 23 - Prob. 23.149CPCh. 23 - Prob. 23.150CPCh. 23 - Prob. 23.151CPCh. 23 - Prob. 23.152MPCh. 23 - Prob. 23.153MPCh. 23 - Prob. 23.154MPCh. 23 - Prob. 23.155MP
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- Don't used hand raiting and don't used Ai solutionarrow_forward2' P17E.6 The oxidation of NO to NO 2 2 NO(g) + O2(g) → 2NO2(g), proceeds by the following mechanism: NO + NO → N₂O₂ k₁ N2O2 NO NO K = N2O2 + O2 → NO2 + NO₂ Ко Verify that application of the steady-state approximation to the intermediate N2O2 results in the rate law d[NO₂] _ 2kk₁[NO][O₂] = dt k+k₁₂[O₂]arrow_forwardPLEASE ANSWER BOTH i) and ii) !!!!arrow_forward
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