The candidate molecule which proves to be a better potential drug if molecule A has a K d of 4.9 and molecule B has a K d of 0.3 for the receptor. Introduction: K d or the dissociation constant is a quantity which determines the degree around which the given molecule remains dissociated into ions in a solution. It is reciprocal of the equilibrium constant, which is a quantitative representation of the binding affinity of a protein to its ligand.

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Answer 1

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Chapter 2.3, Problem 14CC

Summary Introduction

To determine: The candidate molecule which proves to be a better potential drug if molecule A has a K_d of 4.9 and molecule B has a K_d of 0.3 for the receptor.

Introduction: K_d or the dissociation constant is a quantity which determines the degree around which the given molecule remains dissociated into ions in a solution. It is reciprocal of the equilibrium constant, which is a quantitative representation of the binding affinity of a protein to its ligand.

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Answer 2

Question

Chapter 2.3, Problem 14CC

Summary Introduction

To determine: The candidate molecule which proves to be a better potential drug if molecule A has a K_d of 4.9 and molecule B has a K_d of 0.3 for the receptor.

Introduction: K_d or the dissociation constant is a quantity which determines the degree around which the given molecule remains dissociated into ions in a solution. It is reciprocal of the equilibrium constant, which is a quantitative representation of the binding affinity of a protein to its ligand.

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Answer 3

Question

Chapter 2.3, Problem 14CC

Summary Introduction

To determine: The candidate molecule which proves to be a better potential drug if molecule A has a K_d of 4.9 and molecule B has a K_d of 0.3 for the receptor.

Introduction: K_d or the dissociation constant is a quantity which determines the degree around which the given molecule remains dissociated into ions in a solution. It is reciprocal of the equilibrium constant, which is a quantitative representation of the binding affinity of a protein to its ligand.

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Answer 4

Question

Chapter 2.3, Problem 14CC

Summary Introduction

To determine: The candidate molecule which proves to be a better potential drug if molecule A has a K_d of 4.9 and molecule B has a K_d of 0.3 for the receptor.

Introduction: K_d or the dissociation constant is a quantity which determines the degree around which the given molecule remains dissociated into ions in a solution. It is reciprocal of the equilibrium constant, which is a quantitative representation of the binding affinity of a protein to its ligand.

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Answer 5

Chapter 2.3, Problem 14CC

Summary Introduction

To determine: The candidate molecule which proves to be a better potential drug if molecule A has a K_d of 4.9 and molecule B has a K_d of 0.3 for the receptor.

Introduction: K_d or the dissociation constant is a quantity which determines the degree around which the given molecule remains dissociated into ions in a solution. It is reciprocal of the equilibrium constant, which is a quantitative representation of the binding affinity of a protein to its ligand.

Answer 6

Chapter 2.3, Problem 14CC

Summary Introduction

To determine: The candidate molecule which proves to be a better potential drug if molecule A has a K_d of 4.9 and molecule B has a K_d of 0.3 for the receptor.

Introduction: K_d or the dissociation constant is a quantity which determines the degree around which the given molecule remains dissociated into ions in a solution. It is reciprocal of the equilibrium constant, which is a quantitative representation of the binding affinity of a protein to its ligand.

Answer 7

Chapter 2.3, Problem 14CC

Summary Introduction

To determine: The candidate molecule which proves to be a better potential drug if molecule A has a K_d of 4.9 and molecule B has a K_d of 0.3 for the receptor.

Introduction: K_d or the dissociation constant is a quantity which determines the degree around which the given molecule remains dissociated into ions in a solution. It is reciprocal of the equilibrium constant, which is a quantitative representation of the binding affinity of a protein to its ligand.

Answer 8

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Answer 11

Ch. 2.1 - List three major essential elements found in the...Ch. 2.1 - What is the general formula of a carbohydrate?Ch. 2.1 - Prob. 3CC Ch. 2.1 - Prob. 4CC Ch. 2.1 - Prob. 5CC Ch. 2.1 - Prob. 6CC Ch. 2.2 - Which dissolve more easily in water, polar...Ch. 2.2 - Prob. 8CC Ch. 2.2 - Why does table salt (NaCl) dissolve in water?Ch. 2.2 - Prob. 10CC

Solution Summary: The author explains that molecule A has a K d of 4.9, whereas molecule B's Kd is 0.3, which is lower than the A value.

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