
Concept explainers
(a)
To find: The average rate of change in Lisa’s temperature from 8:00 A.M on Monday to 8:00 P.M on Monday.
(a)

Answer to Problem 11PPS
The average rate of change in Lisa’s temperature from 8:00 A.M on Monday to 8:00 P.M on Monday is
Explanation of Solution
Given:
The following table shows Lisa’s temperature during an illness over 3-day period.
Day | Monday | Tuesday | Wednesday | |||
Time | 8:00 A.M | 8:00 P.M | 8:00 A.M | 8:00 P.M | 8:00 A.M | 8:00 P.M |
Temp |
Calculation:
Find the rate of change as follows.
Therefore, the average rate of change is
(b)
To find: The average rate of change in Lisa’s temperature from 8:00 A.M on Tuesday to 8:00 P.M on Wednesday, whether the answer is reasonable and find the meaning of sign of rate of change.
(b)

Answer to Problem 11PPS
The average rate of change from 8:00 A.M on Tuesday to 8:00 P.M on Wednesday is
Explanation of Solution
Find the rate of change as follows.
Therefore, the average rate of change is
The average rate of change from 8:00 A.M on Tuesday to 8:00 P.M on Wednesday is
(c)
To find: The 12-hour period at which the average rate of change in Lisa’s temperature is greatest.
(c)

Answer to Problem 11PPS
The average rate of change in Lisa’s temperature was greatest during Monday 8:00 A.M to Monday 8:00 P.M.
Explanation of Solution
The average rate of change in Lisa’s temperature from 8:00 A.M on Monday to 8:00 P.M on Monday is
The average rate of change in Lisa’s temperature from 8:00 A.M on Monday to 8:00 P.M on Tuesday is
The average rate of change in Lisa’s temperature from 8:00 A.M on Tuesday to 8:00 P.M on Tuesday is
The average rate of change in Lisa’s temperature from 8:00 A.M on Tuesday to 8:00 P.M on Wednesday is
The average rate of change in Lisa’s temperature from 8:00 A.M on Wednesday to 8:00 P.M on Wednesday is
Therefore, the average rate of change in Lisa’s temperature was greatest during Monday 8:00 A.M to Monday 8:00 P.M.
Chapter 2 Solutions
Glencoe Algebra 2 Student Edition C2014
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