Given code: public static void mA(int n) { for ( int i = 0 ; i < n ; i ++) { System.out.println(Math. random()); } }

Question

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Answer 1

Question

Chapter 22.3, Problem 22.3.3CP

a)

Program Plan Intro

Given code:

public static void mA(int n)

{

for ( int i = 0 ; i < n ; i ++) {

System.out.println(Math. random());

}

}

b)

Program Plan Intro

Given code:

public static void mB (int n)

{

for ( int i = 0 ; i < n ; i ++ )

{

for ( int j = 0; j < i ; j ++)

System.out.print(Math. random());

}

}

c)

Program Plan Intro

Given code:

public static void mC(int[ ] m)

{

for (int i = 0; i < m.length; i++)

{

System .out.print(m [i]);

}

for (int i=m.length-1;i>=0;)

{

System.out.print(m[i]);

i--;

}

}

d)

Program Plan Intro

Given code:

public static void mD (int[ ] m)

{

for (int i= 0; i < m.length; i++)

{

for ( int j = 0 ; j < i ; j ++)

System.out. print( m[ i ] * m[ j ]);

}

}

Expert Solution & Answer

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Check out a sample textbook solution

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My daughter is a Girl Scout and it is time for our cookie sales. There are 15 neighbors nearby and she plans to visit every neighbor this evening. There is a 40% likelihood that someone will be home. If someone is home, there is an 85% likelihood that person will make a purchase. If a purchase is made, the revenue generated from the sale follows the Normal distribution with mean $18 and standard deviation $5. Using @RISK, simulate our door-to-door sales using at least 1000 iterations and report the expected revenue, the maximum revenue, and the average number of purchasers. What is the probability that the revenue will be greater than $120?

Q4 For the network of Fig. 1.41: a- Determine re b- Find Aymid =VolVi =Vo/Vi c- Calculate Zi. d- Find Ay smid e-Determine fL, JLC, and fLE f-Determine the low cutoff frequency. g- Sketch the asymptotes of the Bode plot defined by the cutoff frequencies of part (e). h-Sketch the low-frequency response for the amplifier using the results of part (f). Ans: 28.48 2, -72.91, 2.455 KS2, -54.68, 103.4 Hz. 38.05 Hz. 235.79 Hz. 235.79 Hz. 14V 15.6ΚΩ 68kQ 0.47µF Vo 0.82 ΚΩ V₁ B-120 3.3kQ 0.47µF 10kQ 1.2k0 =20µF Z₁ Fig. 1.41 Circuit for

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Answer 2

Question

Chapter 22.3, Problem 22.3.3CP

a)

Program Plan Intro

Given code:

public static void mA(int n)

{

for ( int i = 0 ; i < n ; i ++) {

System.out.println(Math. random());

}

}

b)

Program Plan Intro

Given code:

public static void mB (int n)

{

for ( int i = 0 ; i < n ; i ++ )

{

for ( int j = 0; j < i ; j ++)

System.out.print(Math. random());

}

}

c)

Program Plan Intro

Given code:

public static void mC(int[ ] m)

{

for (int i = 0; i < m.length; i++)

{

System .out.print(m [i]);

}

for (int i=m.length-1;i>=0;)

{

System.out.print(m[i]);

i--;

}

}

d)

Program Plan Intro

Given code:

public static void mD (int[ ] m)

{

for (int i= 0; i < m.length; i++)

{

for ( int j = 0 ; j < i ; j ++)

System.out. print( m[ i ] * m[ j ]);

}

}

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 3

Question

Chapter 22.3, Problem 22.3.3CP

a)

Program Plan Intro

Given code:

public static void mA(int n)

{

for ( int i = 0 ; i < n ; i ++) {

System.out.println(Math. random());

}

}

b)

Program Plan Intro

Given code:

public static void mB (int n)

{

for ( int i = 0 ; i < n ; i ++ )

{

for ( int j = 0; j < i ; j ++)

System.out.print(Math. random());

}

}

c)

Program Plan Intro

Given code:

public static void mC(int[ ] m)

{

for (int i = 0; i < m.length; i++)

{

System .out.print(m [i]);

}

for (int i=m.length-1;i>=0;)

{

System.out.print(m[i]);

i--;

}

}

d)

Program Plan Intro

Given code:

public static void mD (int[ ] m)

{

for (int i= 0; i < m.length; i++)

{

for ( int j = 0 ; j < i ; j ++)

System.out. print( m[ i ] * m[ j ]);

}

}

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 4

Question

Chapter 22.3, Problem 22.3.3CP

a)

Program Plan Intro

Given code:

public static void mA(int n)

{

for ( int i = 0 ; i < n ; i ++) {

System.out.println(Math. random());

}

}

b)

Program Plan Intro

Given code:

public static void mB (int n)

{

for ( int i = 0 ; i < n ; i ++ )

{

for ( int j = 0; j < i ; j ++)

System.out.print(Math. random());

}

}

c)

Program Plan Intro

Given code:

public static void mC(int[ ] m)

{

for (int i = 0; i < m.length; i++)

{

System .out.print(m [i]);

}

for (int i=m.length-1;i>=0;)

{

System.out.print(m[i]);

i--;

}

}

d)

Program Plan Intro

Given code:

public static void mD (int[ ] m)

{

for (int i= 0; i < m.length; i++)

{

for ( int j = 0 ; j < i ; j ++)

System.out. print( m[ i ] * m[ j ]);

}

}

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 5

Chapter 22.3, Problem 22.3.3CP

a)

Program Plan Intro

Given code:

public static void mA(int n)

{

for ( int i = 0 ; i < n ; i ++) {

System.out.println(Math. random());

}

}

b)

Program Plan Intro

Given code:

public static void mB (int n)

{

for ( int i = 0 ; i < n ; i ++ )

{

for ( int j = 0; j < i ; j ++)

System.out.print(Math. random());

}

}

c)

Program Plan Intro

Given code:

public static void mC(int[ ] m)

{

for (int i = 0; i < m.length; i++)

{

System .out.print(m [i]);

}

for (int i=m.length-1;i>=0;)

{

System.out.print(m[i]);

i--;

}

}

d)

Program Plan Intro

Given code:

public static void mD (int[ ] m)

{

for (int i= 0; i < m.length; i++)

{

for ( int j = 0 ; j < i ; j ++)

System.out. print( m[ i ] * m[ j ]);

}

}

Answer 6

Chapter 22.3, Problem 22.3.3CP

a)

Program Plan Intro

Given code:

public static void mA(int n)

{

for ( int i = 0 ; i < n ; i ++) {

System.out.println(Math. random());

}

}

Answer 7

Chapter 22.3, Problem 22.3.3CP

a)

Program Plan Intro

Given code:

public static void mA(int n)

{

for ( int i = 0 ; i < n ; i ++) {

System.out.println(Math. random());

}

}

Answer 8

b)

Program Plan Intro

Given code:

public static void mB (int n)

{

for ( int i = 0 ; i < n ; i ++ )

{

for ( int j = 0; j < i ; j ++)

System.out.print(Math. random());

}

}

Answer 9

b)

Program Plan Intro

Given code:

public static void mB (int n)

{

for ( int i = 0 ; i < n ; i ++ )

{

for ( int j = 0; j < i ; j ++)

System.out.print(Math. random());

}

}

Answer 10

c)

Program Plan Intro

Given code:

public static void mC(int[ ] m)

{

for (int i = 0; i < m.length; i++)

{

System .out.print(m [i]);

}

for (int i=m.length-1;i>=0;)

{

System.out.print(m[i]);

i--;

}

}

Answer 11

c)

Program Plan Intro

Given code:

public static void mC(int[ ] m)

{

for (int i = 0; i < m.length; i++)

{

System .out.print(m [i]);

}

for (int i=m.length-1;i>=0;)

{

System.out.print(m[i]);

i--;

}

}

Answer 12

d)

Program Plan Intro

Given code:

public static void mD (int[ ] m)

{

for (int i= 0; i < m.length; i++)

{

for ( int j = 0 ; j < i ; j ++)

System.out. print( m[ i ] * m[ j ]);

}

}

Answer 13

d)

Program Plan Intro

Given code:

public static void mD (int[ ] m)

{

for (int i= 0; i < m.length; i++)

{

for ( int j = 0 ; j < i ; j ++)

System.out. print( m[ i ] * m[ j ]);

}

}

Answer 14

Expert Solution & Answer

Answer 15

Expert Solution & Answer

Answer 16

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See solution

Answer 17

Ch. 22.2 - Prob. 22.2.1CP Ch. 22.2 - What is the order of each of the following...Ch. 22.3 - Count the number of iterations in the following...Ch. 22.3 - How many stars are displayed in the following code...Ch. 22.3 - Prob. 22.3.3CP Ch. 22.3 - Prob. 22.3.4CP Ch. 22.3 - Example 7 in Section 22.3 assumes n = 2k. Revise...Ch. 22.4 - Prob. 22.4.1CP Ch. 22.4 - Prob. 22.4.2CP Ch. 22.4 - Prob. 22.4.3CP

Given code: public static void mA(int n) { for ( int i = 0 ; i &lt; n ; i ++) { System.out.println(Math. random()); } }

Given code: public static void mA(int n) { for ( int i = 0 ; i < n ; i ++) { System.out.println(Math. random()); } }

Given code: public static void mB (int n) { for ( int i = 0 ; i < n ; i ++ ) { for ( int j = 0; j < i ; j ++) System.out.print(Math. random()); } }

Given code: public static void mC(int[ ] m) { for (int i = 0; i < m.length; i++) { System .out.print(m [i]); } for (int i=m.length-1;i>=0;) { System.out.print(m[i]); i--; } }

Given code: public static void mD (int[ ] m) { for (int i= 0; i < m.length; i++) { for ( int j = 0 ; j < i ; j ++) System.out. print( m[ i ] * m[ j ]); } }

Want to see the full answer?

Chapter 22 Solutions

Given code: public static void mA(int n) { for ( int i = 0 ; i < n ; i ++) { System.out.println(Math. random()); } }

Given code:

public static void mA(int n)

{

for ( int i = 0 ; i < n ; i ++) {

System.out.println(Math. random());

}

}

Given code:

public static void mB (int n)

{

for ( int i = 0 ; i < n ; i ++ )

{

for ( int j = 0; j < i ; j ++)

System.out.print(Math. random());

}

}

Given code:

public static void mC(int[ ] m)

{

for (int i = 0; i < m.length; i++)

{

System .out.print(m [i]);

}

for (int i=m.length-1;i>=0;)

{

System.out.print(m[i]);

i--;

}

}

Given code:

public static void mD (int[ ] m)

{

for (int i= 0; i < m.length; i++)

{

for ( int j = 0 ; j < i ; j ++)

System.out. print( m[ i ] * m[ j ]);

}

}