The given compound of amine is to be prepared via reductive amination and preparation of the starting material via retrosynthetic analysis of the final product. Concept Introduction : Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines . Aldehyde or ketone group is reacted with primary amine in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce secondary amines. Aldehyde or ketone group is reacted with secondary amine in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce tertiary amines. There are two ways to get the starting compounds in either left or right side cleavage of all C−N bonds. After the cleavage, retrosynthetic analysis of the starting materials is done. If both aldehyde/ketone and amine starting materials are decided, reductive amination is followed in both the ways by placing the suitable reagents. The starting materials for reductive amination are carbonyl compound and alkyl amine. The carbonyl compound can be prepared in a number of ways such as radical bromination of alkane , treatment of brominated product with strong base, ozonolysis of alkene .

Question

Want to see the full answer?

Answer 1

Question

Definition Definition Organic compounds that have a carbonyl group, C=O, as their functional group. The carbonyl group in aldehydes is placed at the end of the molecular structure, which means the C=O is attached to one hydrogen atom and an alkyl group or a benzene ring. Just like all the other homologous series in organic chemistry, the naming of aldehydes uses the suffix “-al”. The general molecular formula is C n H 2n O.

Chapter 22, Problem 90IP

Interpretation Introduction

Interpretation: The given compound of amine is to be prepared via reductive amination and preparation of the starting material via retrosynthetic analysis of the final product.

Concept Introduction: Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Aldehyde or ketone group is reacted with primary amine in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce secondary amines.

Aldehyde or ketone group is reacted with secondary amine in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce tertiary amines.

There are two ways to get the starting compounds in either left or right side cleavage of all C−N bonds. After the cleavage, retrosynthetic analysis of the starting materials is done. If both aldehyde/ketone and amine starting materials are decided, reductive amination is followed in both the ways by placing the suitable reagents.

The starting materials for reductive amination are carbonyl compound and alkyl amine. The carbonyl compound can be prepared in a number of ways such as radical bromination of alkane, treatment of brominated product with strong base, ozonolysis of alkene.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

You are trying to decide if there is a single reagent you can add that will make the following synthesis possible without any other major side products: xi 1. ☑ 2. H₂O хе i Draw the missing reagent X you think will make this synthesis work in the drawing area below. If there is no reagent that will make your desired product in good yield or without complications, just check the box under the drawing area and leave it blank. Click and drag to start drawing a structure. There is no reagent that will make this synthesis work without complications. : ☐ S ☐

Predict the major products of this organic reaction: H OH 1. LiAlH4 2. H₂O ? Note: be sure you use dash and wedge bonds when necessary, for example to distinguish between major products with different stereochemistry. Click and drag to start drawing a structure. G C टे

For each reaction below, decide if the first stable organic product that forms in solution will create a new C-C bond, and check the appropriate box. Next, for each reaction to which you answered "Yes" to in the table, draw this product in the drawing area below. Note for advanced students: for this problem, don't worry if you think this product will continue to react under the current conditions - just focus on the first stable product you expect to form in solution. NH2 CI MgCl ? Will the first product that forms in this reaction create a new CC bond? Yes No MgBr ? Will the first product that forms in this reaction create a new CC bond? Yes No G टे

Answer 2

Question

Definition Definition Organic compounds that have a carbonyl group, C=O, as their functional group. The carbonyl group in aldehydes is placed at the end of the molecular structure, which means the C=O is attached to one hydrogen atom and an alkyl group or a benzene ring. Just like all the other homologous series in organic chemistry, the naming of aldehydes uses the suffix “-al”. The general molecular formula is C n H 2n O.

Chapter 22, Problem 90IP

Interpretation Introduction

Interpretation: The given compound of amine is to be prepared via reductive amination and preparation of the starting material via retrosynthetic analysis of the final product.

Concept Introduction: Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Aldehyde or ketone group is reacted with primary amine in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce secondary amines.

Aldehyde or ketone group is reacted with secondary amine in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce tertiary amines.

There are two ways to get the starting compounds in either left or right side cleavage of all C−N bonds. After the cleavage, retrosynthetic analysis of the starting materials is done. If both aldehyde/ketone and amine starting materials are decided, reductive amination is followed in both the ways by placing the suitable reagents.

The starting materials for reductive amination are carbonyl compound and alkyl amine. The carbonyl compound can be prepared in a number of ways such as radical bromination of alkane, treatment of brominated product with strong base, ozonolysis of alkene.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 3

Question

Definition Definition Organic compounds that have a carbonyl group, C=O, as their functional group. The carbonyl group in aldehydes is placed at the end of the molecular structure, which means the C=O is attached to one hydrogen atom and an alkyl group or a benzene ring. Just like all the other homologous series in organic chemistry, the naming of aldehydes uses the suffix “-al”. The general molecular formula is C n H 2n O.

Chapter 22, Problem 90IP

Interpretation Introduction

Interpretation: The given compound of amine is to be prepared via reductive amination and preparation of the starting material via retrosynthetic analysis of the final product.

Concept Introduction: Sodium cyanoborohydride is a strong reducing agent than sodium borohydride. It reduces the carbonyl group into amine group in a rapid way. So, it is called as reductive amination reactions. Aldehyde or ketone group is reacted with ammonia in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce primary amines.

Aldehyde or ketone group is reacted with primary amine in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce secondary amines.

Aldehyde or ketone group is reacted with secondary amine in the presence of sodium cyanoborohydride as a reducing agent and a proton source in the reaction medium to produce tertiary amines.

There are two ways to get the starting compounds in either left or right side cleavage of all C−N bonds. After the cleavage, retrosynthetic analysis of the starting materials is done. If both aldehyde/ketone and amine starting materials are decided, reductive amination is followed in both the ways by placing the suitable reagents.

The starting materials for reductive amination are carbonyl compound and alkyl amine. The carbonyl compound can be prepared in a number of ways such as radical bromination of alkane, treatment of brominated product with strong base, ozonolysis of alkene.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 4

Question

Definition Definition Organic compounds that have a carbonyl group, C=O, as their functional group. The carbonyl group in aldehydes is placed at the end of the molecular structure, which means the C=O is attached to one hydrogen atom and an alkyl group or a benzene ring. Just like all the other homologous series in organic chemistry, the naming of aldehydes uses the suffix “-al”. The general molecular formula is C n H 2n O.

Chapter 22, Problem 90IP

Interpretation Introduction