Explanation Given info: The magnitude of the magnetic field is 0.42 T , the current flowing in the loop is 8.8 A and the side of the square loop is 0.38 m . Explanation: For the top and the bottom side of the loop magnetic field is parallel to the direction of current that is θ = 90 ° and for the left and the right side of the loop magnetic field is perpendicular to the direction of the current that is θ = 90 ° . Formula to calculate the magnetic force on the side of loop, F = B i l sin θ Here, B is the magnitude of the magnetic field. i is the current flowing through loop. l is the side of the loop or the length of the conductor. θ is the angle between the direction of current and magnetic field. For top side of the loop: Formula to calculate the magnetic force on top side of loop, F T = B i l sin θ (1) Substitute 0.42 T for B , 8.8 A for i , 0.38 m for l and 0 ° for θ in equation (1). F T = ( 0.42 T ) ( 8.8 A ) ( 0.38 m ) sin0 ° = 0 N Thus, the magnetic force on the top side of the loop is 0 N . For bottom side of the loop: Formula to calculate the magnetic force on the bottom side of loop, F B = B i l sin θ (1) Substitute 0.42 T for B , 8.8 A for i , 0.38 m for l and 0 ° for θ in equation (1). F B = ( 0.42 T ) ( 8

5th Edition

ISBN: 8220103026918

Author: Walker

Publisher: PEARSON

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Magnetic Force

A magnetic force arises when a charged particle or a current-carrying conductor is placed in a magnetic field. It is created because of the movement of the charged particles.

Question

Chapter 22, Problem 69GP

To determine

The magnitude of the magnetic force exerted on the each side of the loop.

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Chapter 22, Problem 68GP

Chapter 22, Problem 70GP

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The magnitude of the magnetic force exerted on the each side of the loop.

Solution Summary: The author explains the magnetic force exerted on the top and bottom sides of the loop.

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The magnitude of the magnetic force exerted on the each side of the loop.

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Chapter 22 Solutions