The mechanism for the last step of Gabriel synthesis under strong basic condition has to be explained. Concept Introduction : The general formula for hexylamine is C 6 H 13 NH 2 . There are several methods available to prepare primary amines . Among them, Gabriel synthesis plays a very important role for preparing it. In this method, secondary and tertiary amines are not formed as side products. It involves in three steps. Step-1: Formation of potassium phthalimide (deprotonation) Potassium phthalimide in alkaline KOH acts as the reagent which has negatively charged phthalimide. It is formed by the reaction between phthalimide and potassium hydroxide. Step-2: Formation of R−N bond by S N 2 nucleophilic substitution The negative charged nitrogen atom in phthalimide can easily attract the positive side of R−X. In primary alkyl halides (R−X), R and X get positive and negative charges, respectively when they ionize. As a result, a bond between nitrogen of phthalimide and carbon of R is formed. This is S N 2 nucleophilic substitution reaction. Halogen atom is going away as halide anion. Step-3: Formation of primary amine by hydrolysis The resultant product further goes for hydrolysis using hydrazine as the reagent. This reaction also follows nucleophilic substitution reaction. Finally, primary amine is formed with a side product of hydrazine derivative.

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Definition Definition Class of organic compounds that contain a carboxyl group ( - COOH ) and has a general formula R - COOH or R - CO 2 H , where R refers to the alkyl, alkenyl, aryl, or other groups. They can undergo different chemical reactions, such as acid-base reactions, esterification, and oxidation. These are essential components of living organisms, playing important roles in metabolic processes, signaling, and as pharmaceuticals.

Chapter 22, Problem 55PP

Interpretation Introduction

Interpretation: The mechanism for the last step of Gabriel synthesis under strong basic condition has to be explained.

Concept Introduction: The general formula for hexylamine is C₆H₁₃NH₂. There are several methods available to prepare primary amines. Among them, Gabriel synthesis plays a very important role for preparing it. In this method, secondary and tertiary amines are not formed as side products. It involves in three steps.

Step-1: Formation of potassium phthalimide (deprotonation)

Potassium phthalimide in alkaline KOH acts as the reagent which has negatively charged phthalimide. It is formed by the reaction between phthalimide and potassium hydroxide.

Step-2: Formation of R−N bond by S_N2 nucleophilic substitution

The negative charged nitrogen atom in phthalimide can easily attract the positive side of R−X. In primary alkyl halides (R−X), R and X get positive and negative charges, respectively when they ionize. As a result, a bond between nitrogen of phthalimide and carbon of R is formed. This is S_N2 nucleophilic substitution reaction. Halogen atom is going away as halide anion.

Step-3: Formation of primary amine by hydrolysis

The resultant product further goes for hydrolysis using hydrazine as the reagent. This reaction also follows nucleophilic substitution reaction. Finally, primary amine is formed with a side product of hydrazine derivative.

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Answer 2

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Definition Definition Class of organic compounds that contain a carboxyl group ( - COOH ) and has a general formula R - COOH or R - CO 2 H , where R refers to the alkyl, alkenyl, aryl, or other groups. They can undergo different chemical reactions, such as acid-base reactions, esterification, and oxidation. These are essential components of living organisms, playing important roles in metabolic processes, signaling, and as pharmaceuticals.

Chapter 22, Problem 55PP

Interpretation Introduction

Interpretation: The mechanism for the last step of Gabriel synthesis under strong basic condition has to be explained.

Concept Introduction: The general formula for hexylamine is C₆H₁₃NH₂. There are several methods available to prepare primary amines. Among them, Gabriel synthesis plays a very important role for preparing it. In this method, secondary and tertiary amines are not formed as side products. It involves in three steps.

Step-1: Formation of potassium phthalimide (deprotonation)

Potassium phthalimide in alkaline KOH acts as the reagent which has negatively charged phthalimide. It is formed by the reaction between phthalimide and potassium hydroxide.

Step-2: Formation of R−N bond by S_N2 nucleophilic substitution

The negative charged nitrogen atom in phthalimide can easily attract the positive side of R−X. In primary alkyl halides (R−X), R and X get positive and negative charges, respectively when they ionize. As a result, a bond between nitrogen of phthalimide and carbon of R is formed. This is S_N2 nucleophilic substitution reaction. Halogen atom is going away as halide anion.

Step-3: Formation of primary amine by hydrolysis

The resultant product further goes for hydrolysis using hydrazine as the reagent. This reaction also follows nucleophilic substitution reaction. Finally, primary amine is formed with a side product of hydrazine derivative.

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Check out a sample textbook solution

See solution

Answer 3

Question

Definition Definition Class of organic compounds that contain a carboxyl group ( - COOH ) and has a general formula R - COOH or R - CO 2 H , where R refers to the alkyl, alkenyl, aryl, or other groups. They can undergo different chemical reactions, such as acid-base reactions, esterification, and oxidation. These are essential components of living organisms, playing important roles in metabolic processes, signaling, and as pharmaceuticals.

Chapter 22, Problem 55PP

Interpretation Introduction

Interpretation: The mechanism for the last step of Gabriel synthesis under strong basic condition has to be explained.

Concept Introduction: The general formula for hexylamine is C₆H₁₃NH₂. There are several methods available to prepare primary amines. Among them, Gabriel synthesis plays a very important role for preparing it. In this method, secondary and tertiary amines are not formed as side products. It involves in three steps.

Step-1: Formation of potassium phthalimide (deprotonation)

Potassium phthalimide in alkaline KOH acts as the reagent which has negatively charged phthalimide. It is formed by the reaction between phthalimide and potassium hydroxide.

Step-2: Formation of R−N bond by S_N2 nucleophilic substitution

The negative charged nitrogen atom in phthalimide can easily attract the positive side of R−X. In primary alkyl halides (R−X), R and X get positive and negative charges, respectively when they ionize. As a result, a bond between nitrogen of phthalimide and carbon of R is formed. This is S_N2 nucleophilic substitution reaction. Halogen atom is going away as halide anion.

Step-3: Formation of primary amine by hydrolysis

The resultant product further goes for hydrolysis using hydrazine as the reagent. This reaction also follows nucleophilic substitution reaction. Finally, primary amine is formed with a side product of hydrazine derivative.

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 4

Question

Definition Definition Class of organic compounds that contain a carboxyl group ( - COOH ) and has a general formula R - COOH or R - CO 2 H , where R refers to the alkyl, alkenyl, aryl, or other groups. They can undergo different chemical reactions, such as acid-base reactions, esterification, and oxidation. These are essential components of living organisms, playing important roles in metabolic processes, signaling, and as pharmaceuticals.

Chapter 22, Problem 55PP

Interpretation Introduction