(a) The wavelength and frequency of photon that have the energy 2.33 × 10 − 19 J ?

Question

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Answer 1

Question

Chapter 22, Problem 47QAP

To determine

(a)

The wavelength and frequency of photon that have the energy 2.33×10−19J ?

Expert Solution

Explanation of Solution

Calculation:

Wavelength
λ=hcEphoton=6.63×10−34×3×1082.33×10−19=8.57×10−7m=857nm

Frequency
f=Ephotonh=2.33×10−196.63×10−34=3.51×1014Hz

Conclusion:

Wavelength =857nm

Frequency =3.51×1014Hz

To determine

(b)

The wavelength and frequency of photon that have the energy 4.50×10−19J ?

Expert Solution

Explanation of Solution

Calculation:

Wavelength
λ=hcEphoton=6.63×10−34×3×1084.5×10−19=4.42×10−7m=442nm

Frequency
f=Ephotonh=4.50×10−196.63×10−34=6.79×1014Hz

Conclusion:

Wavelength =442nm

Frequency =6.79×1014Hz

To determine

(c)

The wavelength and frequency of photon that have the energy 3.20×10−19J ?

Expert Solution

Explanation of Solution

Calculation:

Wavelength
λ=hcEphoton=6.63×10−34×3×1083.20×10−19=6.22×10−7m=622nm

Frequency
f=Ephotonh=3.20×10−196.63×10−34=4.83×1014Hz

Conclusion:

Wavelength =622nm

Frequency =4.83×1014Hz

To determine

(d)

The wavelength and frequency of photon that have the energy 8.55×10−19J ?

Expert Solution

Explanation of Solution

Calculation:

Wavelength
λ=hcEphoton=6.63×10−34×3×1088.55×10−19=2.33×10−7m=233nm

Frequency
f=Ephotonh=8.55×10−196.63×10−34=1.29×1015Hz

Conclusion:

Wavelength =233nm

Frequency =1.29×1015Hz

To determine

(e)

The wavelength and frequency of photon that have the energy 63.3eV ?

Expert Solution

Explanation of Solution

Calculation:

Energy in joules,
Ephoton=63.3×1.60×10−19=1.01×10−17J

Wavelength
λ=hcEphoton=6.63×10−34×3×1081.01×10−17=1.96×10−8m=19.6nm

Frequency
f=Ephotonh=1.01×10−176.63×10−34=1.53×1016Hz

Conclusion:

Wavelength =19.6nm

Frequency =1.53×1016Hz

To determine

(f)

The wavelength and frequency of photon that have the energy 8.77eV ?

Expert Solution

Explanation of Solution

Calculation:

Energy in joules,
Ephoton=8.77×1.60×10−19=1.40×10−18J

Wavelength
λ=hcEphoton=6.63×10−34×3×1081.40×10−18=1.42×10−8m=14.2nm

Frequency
f=Ephotonh=1.40×10−186.63×10−34=2.12×1015Hz

Conclusion:

Wavelength =14.2nm

Frequency =2.12×1015Hz

To determine

(g)

The wavelength and frequency of photon that have the energy 1.98eV ?

Expert Solution

Explanation of Solution

Calculation:

Energy in joules,
Ephoton=1.98×1.60×10−19=3.17×10−19J

Wavelength
λ=hcEphoton=6.63×10−34×3×1083.17×10−19=6.28×10−7m=628nm

Frequency
f=Ephotonh=3.17×10−196.63×10−34=4.78×1014Hz

Conclusion:

Wavelength =628nm

Frequency =4.78×1014Hz

To determine

(h)

The wavelength and frequency of photon that have the energy 4.55eV ?

Expert Solution

Explanation of Solution

Calculation:

Energy in joules,
Ephoton=4.55×1.60×10−19=7.28×10−19J

Wavelength
λ=hcEphoton=6.63×10−34×3×1087.28×10−19=2.73×10−7m=273nm

Frequency
f=Ephotonh=7.28×10−196.63×10−34=1.10×1015Hz

Conclusion:

Wavelength =273nm

Frequency =1.10×1015Hz

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Answer 2

Question

Chapter 22, Problem 47QAP

To determine

(a)

The wavelength and frequency of photon that have the energy 2.33×10−19J ?

Expert Solution

Explanation of Solution

Calculation:

Wavelength
λ=hcEphoton=6.63×10−34×3×1082.33×10−19=8.57×10−7m=857nm

Frequency
f=Ephotonh=2.33×10−196.63×10−34=3.51×1014Hz

Conclusion:

Wavelength =857nm

Frequency =3.51×1014Hz

To determine

(b)

The wavelength and frequency of photon that have the energy 4.50×10−19J ?

Expert Solution

Explanation of Solution

Calculation:

Wavelength
λ=hcEphoton=6.63×10−34×3×1084.5×10−19=4.42×10−7m=442nm

Frequency
f=Ephotonh=4.50×10−196.63×10−34=6.79×1014Hz

Conclusion:

Wavelength =442nm

Frequency =6.79×1014Hz

To determine

(c)

The wavelength and frequency of photon that have the energy 3.20×10−19J ?

Expert Solution

Explanation of Solution

Calculation:

Wavelength
λ=hcEphoton=6.63×10−34×3×1083.20×10−19=6.22×10−7m=622nm

Frequency
f=Ephotonh=3.20×10−196.63×10−34=4.83×1014Hz

Conclusion:

Wavelength =622nm

Frequency =4.83×1014Hz

To determine

(d)

The wavelength and frequency of photon that have the energy 8.55×10−19J ?

Expert Solution

Explanation of Solution

Calculation:

Wavelength
λ=hcEphoton=6.63×10−34×3×1088.55×10−19=2.33×10−7m=233nm

Frequency
f=Ephotonh=8.55×10−196.63×10−34=1.29×1015Hz

Conclusion:

Wavelength =233nm

Frequency =1.29×1015Hz

To determine

(e)

The wavelength and frequency of photon that have the energy 63.3eV ?

Expert Solution

Explanation of Solution

Calculation:

Energy in joules,
Ephoton=63.3×1.60×10−19=1.01×10−17J

Wavelength
λ=hcEphoton=6.63×10−34×3×1081.01×10−17=1.96×10−8m=19.6nm

Frequency
f=Ephotonh=1.01×10−176.63×10−34=1.53×1016Hz

Conclusion:

Wavelength =19.6nm

Frequency =1.53×1016Hz

To determine

(f)

The wavelength and frequency of photon that have the energy 8.77eV ?

Expert Solution

Explanation of Solution

Calculation:

Energy in joules,
Ephoton=8.77×1.60×10−19=1.40×10−18J

Wavelength
λ=hcEphoton=6.63×10−34×3×1081.40×10−18=1.42×10−8m=14.2nm

Frequency
f=Ephotonh=1.40×10−186.63×10−34=2.12×1015Hz

Conclusion:

Wavelength =14.2nm

Frequency =2.12×1015Hz

To determine

(g)

The wavelength and frequency of photon that have the energy 1.98eV ?

Expert Solution

Explanation of Solution

Calculation:

Energy in joules,
Ephoton=1.98×1.60×10−19=3.17×10−19J

Wavelength
λ=hcEphoton=6.63×10−34×3×1083.17×10−19=6.28×10−7m=628nm

Frequency
f=Ephotonh=3.17×10−196.63×10−34=4.78×1014Hz

Conclusion:

Wavelength =628nm

Frequency =4.78×1014Hz

To determine

(h)

The wavelength and frequency of photon that have the energy 4.55eV ?

Expert Solution

Explanation of Solution

Calculation:

Energy in joules,
Ephoton=4.55×1.60×10−19=7.28×10−19J

Wavelength
λ=hcEphoton=6.63×10−34×3×1087.28×10−19=2.73×10−7m=273nm

Frequency
f=Ephotonh=7.28×10−196.63×10−34=1.10×1015Hz

Conclusion:

Wavelength =273nm

Frequency =1.10×1015Hz

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Answer 3

Question

Chapter 22, Problem 47QAP

To determine

(a)

The wavelength and frequency of photon that have the energy 2.33×10−19J ?

Expert Solution

Explanation of Solution

Calculation:

Wavelength
λ=hcEphoton=6.63×10−34×3×1082.33×10−19=8.57×10−7m=857nm

Frequency
f=Ephotonh=2.33×10−196.63×10−34=3.51×1014Hz

Conclusion:

Wavelength =857nm

Frequency =3.51×1014Hz

To determine

(b)

The wavelength and frequency of photon that have the energy 4.50×10−19J ?

Expert Solution

Explanation of Solution

Calculation:

Wavelength
λ=hcEphoton=6.63×10−34×3×1084.5×10−19=4.42×10−7m=442nm

Frequency
f=Ephotonh=4.50×10−196.63×10−34=6.79×1014Hz

Conclusion:

Wavelength =442nm

Frequency =6.79×1014Hz

To determine

(c)

The wavelength and frequency of photon that have the energy 3.20×10−19J ?

Expert Solution

Explanation of Solution

Calculation:

Wavelength
λ=hcEphoton=6.63×10−34×3×1083.20×10−19=6.22×10−7m=622nm

Frequency
f=Ephotonh=3.20×10−196.63×10−34=4.83×1014Hz

Conclusion:

Wavelength =622nm

Frequency =4.83×1014Hz

To determine

(d)

The wavelength and frequency of photon that have the energy 8.55×10−19J ?

Expert Solution

Explanation of Solution

Calculation:

Wavelength
λ=hcEphoton=6.63×10−34×3×1088.55×10−19=2.33×10−7m=233nm

Frequency
f=Ephotonh=8.55×10−196.63×10−34=1.29×1015Hz

Conclusion:

Wavelength =233nm

Frequency =1.29×1015Hz

To determine

(e)

The wavelength and frequency of photon that have the energy 63.3eV ?

Expert Solution

Explanation of Solution

Calculation:

Energy in joules,
Ephoton=63.3×1.60×10−19=1.01×10−17J

Wavelength
λ=hcEphoton=6.63×10−34×3×1081.01×10−17=1.96×10−8m=19.6nm

Frequency
f=Ephotonh=1.01×10−176.63×10−34=1.53×1016Hz

Conclusion:

Wavelength =19.6nm

Frequency =1.53×1016Hz

To determine

(f)

The wavelength and frequency of photon that have the energy 8.77eV ?

Expert Solution

Explanation of Solution

Calculation:

Energy in joules,
Ephoton=8.77×1.60×10−19=1.40×10−18J

Wavelength
λ=hcEphoton=6.63×10−34×3×1081.40×10−18=1.42×10−8m=14.2nm

Frequency
f=Ephotonh=1.40×10−186.63×10−34=2.12×1015Hz

Conclusion:

Wavelength =14.2nm

Frequency =2.12×1015Hz

To determine

(g)

The wavelength and frequency of photon that have the energy 1.98eV ?

Expert Solution

Explanation of Solution

Calculation:

Energy in joules,
Ephoton=1.98×1.60×10−19=3.17×10−19J

Wavelength
λ=hcEphoton=6.63×10−34×3×1083.17×10−19=6.28×10−7m=628nm

Frequency
f=Ephotonh=3.17×10−196.63×10−34=4.78×1014Hz

Conclusion:

Wavelength =628nm

Frequency =4.78×1014Hz

To determine

(h)

The wavelength and frequency of photon that have the energy 4.55eV ?

Expert Solution

Explanation of Solution

Calculation:

Energy in joules,
Ephoton=4.55×1.60×10−19=7.28×10−19J

Wavelength
λ=hcEphoton=6.63×10−34×3×1087.28×10−19=2.73×10−7m=273nm

Frequency
f=Ephotonh=7.28×10−196.63×10−34=1.10×1015Hz

Conclusion:

Wavelength =273nm

Frequency =1.10×1015Hz

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Answer 4

Question

Chapter 22, Problem 47QAP

To determine

(a)

The wavelength and frequency of photon that have the energy 2.33×10−19J ?

Expert Solution

Explanation of Solution

Calculation:

Wavelength
λ=hcEphoton=6.63×10−34×3×1082.33×10−19=8.57×10−7m=857nm

Frequency
f=Ephotonh=2.33×10−196.63×10−34=3.51×1014Hz

Conclusion:

Wavelength =857nm

Frequency =3.51×1014Hz

To determine

(b)

The wavelength and frequency of photon that have the energy 4.50×10−19J ?

Expert Solution

Explanation of Solution

Calculation:

Wavelength
λ=hcEphoton=6.63×10−34×3×1084.5×10−19=4.42×10−7m=442nm

Frequency
f=Ephotonh=4.50×10−196.63×10−34=6.79×1014Hz

Conclusion:

Wavelength =442nm

Frequency =6.79×1014Hz

To determine

(c)

The wavelength and frequency of photon that have the energy 3.20×10−19J ?

Expert Solution

Explanation of Solution

Calculation:

Wavelength
λ=hcEphoton=6.63×10−34×3×1083.20×10−19=6.22×10−7m=622nm

Frequency
f=Ephotonh=3.20×10−196.63×10−34=4.83×1014Hz

Conclusion:

Wavelength =622nm

Frequency =4.83×1014Hz

To determine

(d)

The wavelength and frequency of photon that have the energy 8.55×10−19J ?

Expert Solution

Explanation of Solution

Calculation:

Wavelength
λ=hcEphoton=6.63×10−34×3×1088.55×10−19=2.33×10−7m=233nm

Frequency
f=Ephotonh=8.55×10−196.63×10−34=1.29×1015Hz

Conclusion:

Wavelength =233nm

Frequency =1.29×1015Hz

To determine

(e)

The wavelength and frequency of photon that have the energy 63.3eV ?

Expert Solution

Explanation of Solution

Calculation:

Energy in joules,
Ephoton=63.3×1.60×10−19=1.01×10−17J

Wavelength
λ=hcEphoton=6.63×10−34×3×1081.01×10−17=1.96×10−8m=19.6nm

Frequency
f=Ephotonh=1.01×10−176.63×10−34=1.53×1016Hz

Conclusion:

Wavelength =19.6nm

Frequency =1.53×1016Hz

To determine

(f)

The wavelength and frequency of photon that have the energy 8.77eV ?

Expert Solution

Explanation of Solution

Calculation:

Energy in joules,
Ephoton=8.77×1.60×10−19=1.40×10−18J

Wavelength
λ=hcEphoton=6.63×10−34×3×1081.40×10−18=1.42×10−8m=14.2nm

Frequency
f=Ephotonh=1.40×10−186.63×10−34=2.12×1015Hz

Conclusion:

Wavelength =14.2nm

Frequency =2.12×1015Hz

To determine

(g)

The wavelength and frequency of photon that have the energy 1.98eV ?

Expert Solution

Explanation of Solution

Calculation:

Energy in joules,
Ephoton=1.98×1.60×10−19=3.17×10−19J

Wavelength
λ=hcEphoton=6.63×10−34×3×1083.17×10−19=6.28×10−7m=628nm

Frequency
f=Ephotonh=3.17×10−196.63×10−34=4.78×1014Hz

Conclusion:

Wavelength =628nm

Frequency =4.78×1014Hz

To determine

(h)

The wavelength and frequency of photon that have the energy 4.55eV ?

Expert Solution

Explanation of Solution

Calculation:

Energy in joules,
Ephoton=4.55×1.60×10−19=7.28×10−19J

Wavelength
λ=hcEphoton=6.63×10−34×3×1087.28×10−19=2.73×10−7m=273nm

Frequency
f=Ephotonh=7.28×10−196.63×10−34=1.10×1015Hz

Conclusion:

Wavelength =273nm

Frequency =1.10×1015Hz

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Answer 5

Chapter 22, Problem 47QAP

To determine

(a)

The wavelength and frequency of photon that have the energy 2.33×10−19J ?

Expert Solution

Explanation of Solution

Calculation:

Wavelength
λ=hcEphoton=6.63×10−34×3×1082.33×10−19=8.57×10−7m=857nm

Frequency
f=Ephotonh=2.33×10−196.63×10−34=3.51×1014Hz

Conclusion:

Wavelength =857nm

Frequency =3.51×1014Hz

To determine

(b)

The wavelength and frequency of photon that have the energy 4.50×10−19J ?

Expert Solution

Explanation of Solution

Calculation:

Wavelength
λ=hcEphoton=6.63×10−34×3×1084.5×10−19=4.42×10−7m=442nm

Frequency
f=Ephotonh=4.50×10−196.63×10−34=6.79×1014Hz

Conclusion:

Wavelength =442nm

Frequency =6.79×1014Hz

To determine

(c)

The wavelength and frequency of photon that have the energy 3.20×10−19J ?

Expert Solution

Explanation of Solution

Calculation:

Wavelength
λ=hcEphoton=6.63×10−34×3×1083.20×10−19=6.22×10−7m=622nm

Frequency
f=Ephotonh=3.20×10−196.63×10−34=4.83×1014Hz

Conclusion:

Wavelength =622nm

Frequency =4.83×1014Hz

To determine

(d)

The wavelength and frequency of photon that have the energy 8.55×10−19J ?

Expert Solution

Explanation of Solution

Calculation:

Wavelength
λ=hcEphoton=6.63×10−34×3×1088.55×10−19=2.33×10−7m=233nm

Frequency
f=Ephotonh=8.55×10−196.63×10−34=1.29×1015Hz

Conclusion:

Wavelength =233nm

Frequency =1.29×1015Hz

To determine

(e)

The wavelength and frequency of photon that have the energy 63.3eV ?

Expert Solution

Explanation of Solution

Calculation:

Energy in joules,
Ephoton=63.3×1.60×10−19=1.01×10−17J

Wavelength
λ=hcEphoton=6.63×10−34×3×1081.01×10−17=1.96×10−8m=19.6nm

Frequency
f=Ephotonh=1.01×10−176.63×10−34=1.53×1016Hz

Conclusion:

Wavelength =19.6nm

Frequency =1.53×1016Hz

To determine

(f)

The wavelength and frequency of photon that have the energy 8.77eV ?

Expert Solution

Explanation of Solution

Calculation:

Energy in joules,
Ephoton=8.77×1.60×10−19=1.40×10−18J

Wavelength
λ=hcEphoton=6.63×10−34×3×1081.40×10−18=1.42×10−8m=14.2nm

Frequency
f=Ephotonh=1.40×10−186.63×10−34=2.12×1015Hz

Conclusion:

Wavelength =14.2nm

Frequency =2.12×1015Hz

To determine

(g)

The wavelength and frequency of photon that have the energy 1.98eV ?

Expert Solution

Explanation of Solution

Calculation:

Energy in joules,
Ephoton=1.98×1.60×10−19=3.17×10−19J

Wavelength
λ=hcEphoton=6.63×10−34×3×1083.17×10−19=6.28×10−7m=628nm

Frequency
f=Ephotonh=3.17×10−196.63×10−34=4.78×1014Hz

Conclusion:

Wavelength =628nm

Frequency =4.78×1014Hz

To determine

(h)

The wavelength and frequency of photon that have the energy 4.55eV ?

Expert Solution

Explanation of Solution

Calculation:

Energy in joules,
Ephoton=4.55×1.60×10−19=7.28×10−19J

Wavelength
λ=hcEphoton=6.63×10−34×3×1087.28×10−19=2.73×10−7m=273nm

Frequency
f=Ephotonh=7.28×10−196.63×10−34=1.10×1015Hz

Conclusion:

Wavelength =273nm

Frequency =1.10×1015Hz

Answer 6

Chapter 22, Problem 47QAP

To determine

(a)

The wavelength and frequency of photon that have the energy 2.33×10−19J ?

Expert Solution

Explanation of Solution

Calculation:

Wavelength
λ=hcEphoton=6.63×10−34×3×1082.33×10−19=8.57×10−7m=857nm

Frequency
f=Ephotonh=2.33×10−196.63×10−34=3.51×1014Hz

Conclusion:

Wavelength =857nm

Frequency =3.51×1014Hz

Answer 7

Chapter 22, Problem 47QAP

To determine

(a)

The wavelength and frequency of photon that have the energy 2.33×10−19J ?

Answer 8

Expert Solution

Explanation of Solution

Calculation:

Wavelength
λ=hcEphoton=6.63×10−34×3×1082.33×10−19=8.57×10−7m=857nm

Frequency
f=Ephotonh=2.33×10−196.63×10−34=3.51×1014Hz

Conclusion:

Wavelength =857nm

Frequency =3.51×1014Hz

Answer 9

Expert Solution

Answer 10

Expert Solution

Answer 11

Expert Solution

Answer 12

To determine

(b)

The wavelength and frequency of photon that have the energy 4.50×10−19J ?

Expert Solution

Explanation of Solution

Calculation:

Wavelength
λ=hcEphoton=6.63×10−34×3×1084.5×10−19=4.42×10−7m=442nm

Frequency
f=Ephotonh=4.50×10−196.63×10−34=6.79×1014Hz

Conclusion:

Wavelength =442nm

Frequency =6.79×1014Hz

Answer 13

To determine

(b)

The wavelength and frequency of photon that have the energy 4.50×10−19J ?

Answer 14

Expert Solution

Explanation of Solution

Calculation:

Wavelength
λ=hcEphoton=6.63×10−34×3×1084.5×10−19=4.42×10−7m=442nm

Frequency
f=Ephotonh=4.50×10−196.63×10−34=6.79×1014Hz

Conclusion:

Wavelength =442nm

Frequency =6.79×1014Hz

Answer 15

Expert Solution

Answer 16

Expert Solution

Answer 17

Expert Solution

Answer 18

To determine

(c)

The wavelength and frequency of photon that have the energy 3.20×10−19J ?

Expert Solution

Explanation of Solution

Calculation:

Wavelength
λ=hcEphoton=6.63×10−34×3×1083.20×10−19=6.22×10−7m=622nm

Frequency
f=Ephotonh=3.20×10−196.63×10−34=4.83×1014Hz

Conclusion:

Wavelength =622nm

Frequency =4.83×1014Hz

Answer 19

To determine

(c)

The wavelength and frequency of photon that have the energy 3.20×10−19J ?

Answer 20

Expert Solution

Explanation of Solution

Calculation:

Wavelength
λ=hcEphoton=6.63×10−34×3×1083.20×10−19=6.22×10−7m=622nm

Frequency
f=Ephotonh=3.20×10−196.63×10−34=4.83×1014Hz

Conclusion:

Wavelength =622nm

Frequency =4.83×1014Hz

Answer 21

Expert Solution

Answer 22

Expert Solution

Answer 23

Expert Solution

Answer 24

To determine

(d)

The wavelength and frequency of photon that have the energy 8.55×10−19J ?

Expert Solution

Explanation of Solution

Calculation:

Wavelength
λ=hcEphoton=6.63×10−34×3×1088.55×10−19=2.33×10−7m=233nm

Frequency
f=Ephotonh=8.55×10−196.63×10−34=1.29×1015Hz

Conclusion:

Wavelength =233nm

Frequency =1.29×1015Hz

Answer 25

To determine

(d)

The wavelength and frequency of photon that have the energy 8.55×10−19J ?

Answer 26

Expert Solution

Explanation of Solution

Calculation:

Wavelength
λ=hcEphoton=6.63×10−34×3×1088.55×10−19=2.33×10−7m=233nm

Frequency
f=Ephotonh=8.55×10−196.63×10−34=1.29×1015Hz

Conclusion:

Wavelength =233nm

Frequency =1.29×1015Hz

Answer 27

Expert Solution

Answer 28

Expert Solution

Answer 29

Expert Solution

Answer 30

To determine

(e)

The wavelength and frequency of photon that have the energy 63.3eV ?

Expert Solution

Explanation of Solution

Calculation:

Energy in joules,
Ephoton=63.3×1.60×10−19=1.01×10−17J

Wavelength
λ=hcEphoton=6.63×10−34×3×1081.01×10−17=1.96×10−8m=19.6nm

Frequency
f=Ephotonh=1.01×10−176.63×10−34=1.53×1016Hz

Conclusion:

Wavelength =19.6nm

Frequency =1.53×1016Hz

Answer 31

To determine

(e)

The wavelength and frequency of photon that have the energy 63.3eV ?

Answer 32

Expert Solution

Explanation of Solution

Calculation:

Energy in joules,
Ephoton=63.3×1.60×10−19=1.01×10−17J

Wavelength
λ=hcEphoton=6.63×10−34×3×1081.01×10−17=1.96×10−8m=19.6nm

Frequency
f=Ephotonh=1.01×10−176.63×10−34=1.53×1016Hz

Conclusion:

Wavelength =19.6nm

Frequency =1.53×1016Hz

Answer 33

Expert Solution

Answer 34

Expert Solution

Answer 35

Expert Solution

Answer 36

To determine

(f)

The wavelength and frequency of photon that have the energy 8.77eV ?

Expert Solution

Explanation of Solution

Calculation:

Energy in joules,
Ephoton=8.77×1.60×10−19=1.40×10−18J

Wavelength
λ=hcEphoton=6.63×10−34×3×1081.40×10−18=1.42×10−8m=14.2nm

Frequency
f=Ephotonh=1.40×10−186.63×10−34=2.12×1015Hz

Conclusion:

Wavelength =14.2nm

Frequency =2.12×1015Hz

Answer 37

To determine

(f)

The wavelength and frequency of photon that have the energy 8.77eV ?

Answer 38

Expert Solution

Explanation of Solution

Calculation:

Energy in joules,
Ephoton=8.77×1.60×10−19=1.40×10−18J

Wavelength
λ=hcEphoton=6.63×10−34×3×1081.40×10−18=1.42×10−8m=14.2nm

Frequency
f=Ephotonh=1.40×10−186.63×10−34=2.12×1015Hz

Conclusion:

Wavelength =14.2nm

Frequency =2.12×1015Hz

Answer 39

Expert Solution

Answer 40

Expert Solution

Answer 41

Expert Solution

Answer 42

To determine

(g)

The wavelength and frequency of photon that have the energy 1.98eV ?

Expert Solution

Explanation of Solution

Calculation:

Energy in joules,
Ephoton=1.98×1.60×10−19=3.17×10−19J

Wavelength
λ=hcEphoton=6.63×10−34×3×1083.17×10−19=6.28×10−7m=628nm

Frequency
f=Ephotonh=3.17×10−196.63×10−34=4.78×1014Hz

Conclusion:

Wavelength =628nm

Frequency =4.78×1014Hz

Answer 43

To determine

(g)

The wavelength and frequency of photon that have the energy 1.98eV ?

Answer 44

Expert Solution

Explanation of Solution

Calculation:

Energy in joules,
Ephoton=1.98×1.60×10−19=3.17×10−19J

Wavelength
λ=hcEphoton=6.63×10−34×3×1083.17×10−19=6.28×10−7m=628nm

Frequency
f=Ephotonh=3.17×10−196.63×10−34=4.78×1014Hz

Conclusion:

Wavelength =628nm

Frequency =4.78×1014Hz

Answer 45

Expert Solution

Answer 46

Expert Solution

Answer 47

Expert Solution

Answer 48

To determine

(h)

The wavelength and frequency of photon that have the energy 4.55eV ?

Expert Solution

Explanation of Solution

Calculation:

Energy in joules,
Ephoton=4.55×1.60×10−19=7.28×10−19J

Wavelength
λ=hcEphoton=6.63×10−34×3×1087.28×10−19=2.73×10−7m=273nm

Frequency
f=Ephotonh=7.28×10−196.63×10−34=1.10×1015Hz

Conclusion:

Wavelength =273nm

Frequency =1.10×1015Hz

Answer 49

To determine

(h)

The wavelength and frequency of photon that have the energy 4.55eV ?

Answer 50

Expert Solution

Explanation of Solution

Calculation:

Energy in joules,
Ephoton=4.55×1.60×10−19=7.28×10−19J

Wavelength
λ=hcEphoton=6.63×10−34×3×1087.28×10−19=2.73×10−7m=273nm

Frequency
f=Ephotonh=7.28×10−196.63×10−34=1.10×1015Hz

Conclusion:

Wavelength =273nm

Frequency =1.10×1015Hz

Answer 51

Expert Solution

Answer 52

Expert Solution

Answer 53

Expert Solution

Answer 54

Ch. 22 - Prob. 1QAP Ch. 22 - Prob. 2QAP Ch. 22 - Prob. 3QAP Ch. 22 - Prob. 4QAP Ch. 22 - Prob. 5QAP Ch. 22 - Prob. 6QAP Ch. 22 - Prob. 7QAP Ch. 22 - Prob. 8QAP Ch. 22 - Prob. 9QAP Ch. 22 - Prob. 10QAP

(a) The wavelength and frequency of photon that have the energy 2.33 × 10 − 19 J ?

Concept explainers

(a)

The wavelength and frequency of photon that have the energy 2.33×10−19J ?

Explanation of Solution

(b)

The wavelength and frequency of photon that have the energy 4.50×10−19J ?

Explanation of Solution

(c)

The wavelength and frequency of photon that have the energy 3.20×10−19J ?

Explanation of Solution

(d)

The wavelength and frequency of photon that have the energy 8.55×10−19J ?

Explanation of Solution

(e)

The wavelength and frequency of photon that have the energy 63.3eV ?

Explanation of Solution

(f)

The wavelength and frequency of photon that have the energy 8.77eV ?

Explanation of Solution

(g)

The wavelength and frequency of photon that have the energy 1.98eV ?

Explanation of Solution

(h)

The wavelength and frequency of photon that have the energy 4.55eV ?

Explanation of Solution

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Chapter 22 Solutions

(a) The wavelength and frequency of photon that have the energy 2.33 × 10 − 19 J ?

Concept explainers

(a) The wavelength and frequency of photon that have the energy 2.33×10−19J ?

Explanation of Solution

(b) The wavelength and frequency of photon that have the energy 4.50×10−19J ?

Explanation of Solution

(c) The wavelength and frequency of photon that have the energy 3.20×10−19J ?

Explanation of Solution

(d) The wavelength and frequency of photon that have the energy 8.55×10−19J ?

Explanation of Solution

(e) The wavelength and frequency of photon that have the energy 63.3eV ?

Explanation of Solution

(f) The wavelength and frequency of photon that have the energy 8.77eV ?

Explanation of Solution

(g) The wavelength and frequency of photon that have the energy 1.98eV ?

Explanation of Solution

(h) The wavelength and frequency of photon that have the energy 4.55eV ?

Explanation of Solution

Want to see more full solutions like this?

Chapter 22 Solutions

(a)

The wavelength and frequency of photon that have the energy 2.33×10−19J ?

(b)

The wavelength and frequency of photon that have the energy 4.50×10−19J ?

(c)

The wavelength and frequency of photon that have the energy 3.20×10−19J ?

(d)

The wavelength and frequency of photon that have the energy 8.55×10−19J ?

(e)

The wavelength and frequency of photon that have the energy 63.3eV ?

(f)

The wavelength and frequency of photon that have the energy 8.77eV ?

(g)

The wavelength and frequency of photon that have the energy 1.98eV ?

(h)

The wavelength and frequency of photon that have the energy 4.55eV ?