Discrete Mathematics: Introduction to Mathematical Reasoning
1st Edition
ISBN: 9780495826170
Author: Susanna S. Epp
Publisher: Cengage Learning
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Chapter 2.2, Problem 45ES
To determine
To rewrite: The given statement in if-then form.
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Please calculate the shaded area
An investigator analyzed the leading digits from 797 checks issued by seven suspect companies. The frequencies were found to be 0, 19, 2, 50, 361, 309, 10, 22, and 24, and those digits correspond to the
leading digits of 1, 2, 3, 4, 5, 6, 7, 8, and 9, respectively. If the observed frequencies are substantially different from the frequencies expected with Benford's law shown below, the check amounts appear to result
from fraud. Use a 0.10 significance level to test for goodness-of-fit with Benford's law. Does it appear that the checks are the result of fraud?
Leading Digit
Actual Frequency
Benford's Law: Distribution of Leading Digits
1
2
3
4
5
6
7
8
9
0
19
2
50
361
309
10
22
24
30.1%
17.6%
12.5%
9.7%
7.9%
6.7%
5.8%
5.1%
4.6%
Determine the null and alternative hypotheses.
Ho The leading digits are from a population that conforms to Benford's law.
H₁: At least one leading digit has a frequency that does not conform to Benford's law.
Calculate the test statistic, x².
x²
=
(Round to three…
3. Solve the Heat Equation with Initial and Boundary Conditions
Turn to page 71 for the heat equation problem. Solve the partial differential equation using
Fourier series or another suitable method, given the initial and boundary conditions.
Link: [https://drive.google.com/file/d/1RQ2OZK-LSxpRyejKEMg1t2q15dbpVLCS/view?
usp=sharing]
Provide all derivations and intermediate steps.
Chapter 2 Solutions
Discrete Mathematics: Introduction to Mathematical Reasoning
Ch. 2.1 - Prob. 1ESCh. 2.1 - Prob. 2ESCh. 2.1 - Prob. 3ESCh. 2.1 - Prob. 4ESCh. 2.1 - Prob. 5ESCh. 2.1 - Prob. 6ESCh. 2.1 - Prob. 7ESCh. 2.1 - Prob. 8ESCh. 2.1 - Prob. 9ESCh. 2.1 - Prob. 10ES
Ch. 2.1 - Prob. 11ESCh. 2.1 - Prob. 12ESCh. 2.1 - Prob. 13ESCh. 2.1 - Prob. 14ESCh. 2.1 - Prob. 15ESCh. 2.1 - Prob. 16ESCh. 2.1 - Prob. 17ESCh. 2.1 - Prob. 18ESCh. 2.1 - Prob. 19ESCh. 2.1 - Prob. 20ESCh. 2.1 - Prob. 21ESCh. 2.1 - Prob. 22ESCh. 2.1 - Prob. 23ESCh. 2.1 - Prob. 24ESCh. 2.1 - Prob. 25ESCh. 2.1 - Prob. 26ESCh. 2.1 - Prob. 27ESCh. 2.1 - Prob. 28ESCh. 2.1 - Prob. 29ESCh. 2.1 - Prob. 30ESCh. 2.1 - Prob. 31ESCh. 2.1 - Prob. 32ESCh. 2.1 - Prob. 33ESCh. 2.1 - Prob. 34ESCh. 2.1 - Prob. 35ESCh. 2.1 - Prob. 36ESCh. 2.1 - Prob. 37ESCh. 2.1 - Prob. 38ESCh. 2.1 - Prob. 39ESCh. 2.1 - Prob. 40ESCh. 2.1 - Prob. 41ESCh. 2.1 - Prob. 42ESCh. 2.1 - Prob. 43ESCh. 2.1 - Prob. 44ESCh. 2.1 - Prob. 45ESCh. 2.1 - Prob. 46ESCh. 2.1 - Prob. 47ESCh. 2.2 - Prob. 1ESCh. 2.2 - Prob. 2ESCh. 2.2 - Prob. 3ESCh. 2.2 - Prob. 4ESCh. 2.2 - Prob. 5ESCh. 2.2 - Prob. 6ESCh. 2.2 - Prob. 7ESCh. 2.2 - Prob. 8ESCh. 2.2 - Prob. 9ESCh. 2.2 - Prob. 10ESCh. 2.2 - Prob. 11ESCh. 2.2 - Prob. 12ESCh. 2.2 - Prob. 13ESCh. 2.2 - Prob. 14ESCh. 2.2 - Prob. 15ESCh. 2.2 - Prob. 16ESCh. 2.2 - Prob. 17ESCh. 2.2 - Prob. 18ESCh. 2.2 - Prob. 19ESCh. 2.2 - Prob. 20ESCh. 2.2 - Prob. 21ESCh. 2.2 - Prob. 22ESCh. 2.2 - Prob. 23ESCh. 2.2 - Prob. 24ESCh. 2.2 - Prob. 25ESCh. 2.2 - Prob. 26ESCh. 2.2 - Prob. 27ESCh. 2.2 - Prob. 28ESCh. 2.2 - Prob. 29ESCh. 2.2 - Prob. 30ESCh. 2.2 - Prob. 31ESCh. 2.2 - Prob. 32ESCh. 2.2 - Prob. 33ESCh. 2.2 - Prob. 34ESCh. 2.2 - Prob. 35ESCh. 2.2 - Prob. 36ESCh. 2.2 - Prob. 37ESCh. 2.2 - Prob. 38ESCh. 2.2 - Prob. 39ESCh. 2.2 - Prob. 40ESCh. 2.2 - Prob. 41ESCh. 2.2 - Prob. 42ESCh. 2.2 - Prob. 43ESCh. 2.2 - Prob. 44ESCh. 2.2 - Prob. 45ESCh. 2.2 - Prob. 46ESCh. 2.3 - Prob. 1ESCh. 2.3 - Prob. 2ESCh. 2.3 - Prob. 3ESCh. 2.3 - Prob. 4ESCh. 2.3 - Prob. 5ESCh. 2.3 - Prob. 6ESCh. 2.3 - Prob. 7ESCh. 2.3 - Prob. 8ESCh. 2.3 - Prob. 9ESCh. 2.3 - Prob. 10ESCh. 2.3 - Prob. 11ESCh. 2.3 - Prob. 12ESCh. 2.3 - Prob. 13ESCh. 2.3 - Prob. 14ESCh. 2.3 - Prob. 15ESCh. 2.3 - Prob. 16ESCh. 2.3 - Prob. 17ESCh. 2.3 - Prob. 18ESCh. 2.3 - Prob. 19ESCh. 2.3 - Prob. 20ESCh. 2.3 - Prob. 21ESCh. 2.3 - Prob. 22ESCh. 2.3 - Prob. 23ESCh. 2.3 - Prob. 24ESCh. 2.3 - Prob. 25ESCh. 2.3 - Prob. 26ESCh. 2.3 - Prob. 27ESCh. 2.3 - Prob. 28ESCh. 2.3 - Prob. 29ESCh. 2.3 - Prob. 30ESCh. 2.3 - Prob. 31ESCh. 2.3 - Prob. 32ESCh. 2.3 - Prob. 33ESCh. 2.3 - Prob. 34ESCh. 2.3 - Prob. 35ESCh. 2.3 - Prob. 36ESCh. 2.3 - Prob. 37ESCh. 2.3 - Prob. 38ESCh. 2.3 - Prob. 39ESCh. 2.3 - Prob. 40ESCh. 2.3 - Prob. 41ESCh. 2.3 - Prob. 42ESCh. 2.3 - Prob. 43ESCh. 2.3 - Prob. 44ES
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- Name: Tay Jones Level Two Date: Algebra 3 Unit 3: Functions and Equations Practice Assessment Class: #7-OneNote 1. The function f(x) = x² is transformed in the following functions. List the vertex for each function, circle whether the function opens up or down, and why. All three parts must be correct to receive Level 2 points. You can receive points for a, b, and c. a) g(x) = -2(x+5)² Vertex: Opens Up Opens Down Why? ais negative -2 Vertex: b) g(x) = (x + 2)² - 3 c) g(x) = -4(x + 2)² + 2 Opens Up Opens Down Vertex: Opens Up Opens Down Why? 4 Ca is negative) Why? his positive 2. The graph of the function f(x) is shown below. Find the domain, range, and end behavior. Then list the values of x for which the function values are increasing and decreasing. f(x) Domain: End Behavior: As x → ∞o, f(x) -> -6 As x, f(x) -> Range: Where is it Increasing? (002] Where is it Decreasing? (1,00)arrow_forwardFor the distribution drawn here, identify the mean, median, and mode. Question content area bottom Part 1 A. Aequalsmode, Bequalsmedian, Cequalsmean B. Aequalsmode, Bequalsmean, Cequalsmedian C. Aequalsmedian, Bequalsmode, Cequalsmean D. Aequalsmean, Bequalsmode, Cequalsmedianarrow_forwardQ3: Define the linear functional J: H₁(2) R by ¡(v) = a(v, v) - L(v) Л Let u be the unique weak solution to a(u,v) = L(v) in H(2) and suppose that a(...) is a symmetric bilinear form on H(2) prove that 1- u is minimizer. 2- u is unique. 3- The minimizer J(u) can be rewritten under 1(u) = u Au-ub, algebraic form 1 2 Where A, b are repictively the stiffence matrix and the load vector Q4: A) Answer 1- show that the solution to -Au = f in A, u = 0 on a satisfies the stability Vullfll and show that ||V(u u)||||||2 - ||vu||2 2- Prove that Where lu-ul Chuz - !ull = a(u, u) = Vu. Vu dx + fu. uds B) Consider the bilinea forta Л a(u, v) = (Au, Av) (Vu, Vv + (Vu, v) + (u,v) Show that a(u, v) continues and V- elliptic on H(2)arrow_forward
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