EBK CHEMISTRY
EBK CHEMISTRY
4th Edition
ISBN: 8220102797864
Author: Burdge
Publisher: YUZU
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Chapter 22, Problem 43QP
Interpretation Introduction

Interpretation:

The formation constant for [Fe(H2O)5NCS]2+ for the given conditions is to be calculated.

Concept introduction:

The formation constant describes the formation of a complex ion that takes place from its central ion and attached ligands. Its symbol is Kf.

Expert Solution & Answer
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Answer to Problem 43QP

Solution: 1.4×102 M1 

Explanation of Solution

Given information:

Volume of Fe(NO3)3 is 1.0 mL.

Concentration of Fe(NO3)3 is 0.20 M.

Volume of KSCN is 1.0 mL.

Concentration of KSCN is 1.0×103 M.

Volume of HNO3 is 8.0 mL.

Concentration of [Fe(H2O)5NCS]2+ is 7.3×105 M.

The given chemical equation is as:

[Fe(H2O)6]3++SCNH2O+[Fe(H2O)5NCS]2+

According to the above equation, the expression for theformation constant (Kf) is as:

Kf=[Fe(H2O)5NCS]2+[Fe(H2O)6]3+[SCN]

According to the given information, the original volumes of both Fe(III) and SCN were 1.0 mL and the final volume is 10.0 mL. This difference represents the ten-fold dilution. So, the concentrations of Fe(III) and SCN will become:

Fe(III)=0.20 M10=0.020 MSCN=1.0×103 M10=1.0×104 M

Now, make an ICE table as:

                          [Fe(H2O)6]3++SCNH2O+[Fe(H2O)5NCS]2+Initial(M)              0.020              1.0×104       0           0Change(M)      7.3×105    7.3×105      x         7.3×105 Equilibrium(M)   0.020              2.7×105        x         7.3×105

From the ICE table, the expression of Kf will be as:

Kf=7.3×105 M(0.020M)(2.7×105M)1.4×102 M1 

Conclusion

Hence, the formation constant of [Fe(H2O)5NCS]2+ is 1.4×102 M1 .

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Chapter 22 Solutions

EBK CHEMISTRY

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