(a)
Interpretation: For a given set of nitrogen containing compounds, the structures have to be drawn using their general or IUPAC names.
Concept Introduction: If 
, 
and 
groups are attached to the parent carbon, they are called primary, secondary and tertiary
There are two ways followed to name the compound. First one is the method of giving general name in which name of the alkyl group followed by amine name is given. Second one is the method giving IUPAC name in which name of the alkane group followed by amine name is given.
The length of the chain which is having more number of carbon atoms is selected as the parent or main chain. Other chains are considered as substituents to the main chain. Position of the substituents should be included in the name. If one, two, three, four, five, six, etc carbons are activating as the main chain in IUPAC system, then the name of the compound comes as methane, ethane, propane, butane, pentane, hexane, etc. which are the name of
If any configuration is present in the compound, that should be assigned to it while writing the name. If the compound contains heavier groups on the same side, it gets (Z)-configuration. If they are on the opposite directions, (E)-configurations result.
If a carbon has four different groups attached to it, that carbon shows a chirality nature. If that chiral carbon rotates the plane polarized light into a clockwise direction, it gets (R)-isomer. If that carbon rotates the plane polarized light into a counter-clockwise direction, it gets (S)-isomer.
To find: Categorize the number of alkyl groups attached to nitrogen atom
(b)
Interpretation: For a given set of nitrogen containing compounds, the structures have to be drawn using their general or IUPAC names.
Concept Introduction: If , and groups are attached to the parent carbon, they are called primary, secondary and tertiary amines respectively.
There are two ways followed to name the compound. First one is the method of giving general name in which name of the alkyl group followed by amine name is given. Second one is the method giving IUPAC name in which name of the alkane group followed by amine name is given.
The length of the chain which is having more number of carbon atoms is selected as the parent or main chain. Other chains are considered as substituents to the main chain. Position of the substituents should be included in the name. If one, two, three, four, five, six, etc carbons are activating as the main chain in IUPAC system, then the name of the compound comes as methane, ethane, propane, butane, pentane, hexane, etc. which are the name of alkanes. If one, two, three, four, five, six, etc carbons are activating as the main chain in general name method, then the name of the compound comes as methyl, ethyl, propyl, butyl, pentyl, hexyl, etc. which are the name of alkyl groups. If substituent groups are attached to nitrogen atom as in the case of tertiary or secondary amines, the name is given as N-alkyl name of the substituent.
If any configuration is present in the compound, that should be assigned to it while writing the name. If the compound contains heavier groups on the same side, it gets (Z)-configuration. If they are on the opposite directions, (E)-configurations result.
If a carbon has four different groups attached to it, that carbon shows a chirality nature. If that chiral carbon rotates the plane polarized light into a clockwise direction, it gets (R)-isomer. If that carbon rotates the plane polarized light into a counter-clockwise direction, it gets (S)-isomer.
To find: Categorize the number of alkyl groups attached to nitrogen atom
In the given compound (b), three alkyl groups are attached to nitrogen atom. Therefore, it belongs to tertiary amine.
Decide the given name which is in general name method or IUPAC name method
There are three alkyl groups present in the given name. Here, the main chain is cyclopropylamine. Three-membered carbon ring structure is called cyclopropyl group. So, general name system is followed.
Locate the substituents and draw the corresponding structure for the given name
(c)
Interpretation: For a given set of nitrogen containing compounds, the structures have to be drawn using their general or IUPAC names.
Concept Introduction: If , and groups are attached to the parent carbon, they are called primary, secondary and tertiary amines respectively.
There are two ways followed to name the compound. First one is the method of giving general name in which name of the alkyl group followed by amine name is given. Second one is the method giving IUPAC name in which name of the alkane group followed by amine name is given.
The length of the chain which is having more number of carbon atoms is selected as the parent or main chain. Other chains are considered as substituents to the main chain. Position of the substituents should be included in the name. If one, two, three, four, five, six, etc carbons are activating as the main chain in IUPAC system, then the name of the compound comes as methane, ethane, propane, butane, pentane, hexane, etc. which are the name of alkanes. If one, two, three, four, five, six, etc carbons are activating as the main chain in general name method, then the name of the compound comes as methyl, ethyl, propyl, butyl, pentyl, hexyl, etc. which are the name of alkyl groups. If substituent groups are attached to nitrogen atom as in the case of tertiary or secondary amines, the name is given as N-alkyl name of the substituent.
If any configuration is present in the compound, that should be assigned to it while writing the name. If the compound contains heavier groups on the same side, it gets (Z)-configuration. If they are on the opposite directions, (E)-configurations result.
If a carbon has four different groups attached to it, that carbon shows a chirality nature. If that chiral carbon rotates the plane polarized light into a clockwise direction, it gets (R)-isomer. If that carbon rotates the plane polarized light into a counter-clockwise direction, it gets (S)-isomer.
To find: Categorize the number of alkyl groups attached to nitrogen atom
In the given compound (c), only one alkyl group, namely pentane is attached to nitrogen atom. Therefore, it belongs to primary amine.
Decide the given name which is in general name method or IUPAC name method
There is only one alkane group present in the given name. It is pentane attached to primary amine named as pentanamine which is the main chain of the given name. So, IUPAC name system is followed.
Locate the substituents and draw the corresponding structure for the given name
(d)
Interpretation: For a given set of nitrogen containing compounds, the structures have to be drawn using their general or IUPAC names.
Concept Introduction: If , and groups are attached to the parent carbon, they are called primary, secondary and tertiary amines respectively.
There are two ways followed to name the compound. First one is the method of giving general name in which name of the alkyl group followed by amine name is given. Second one is the method giving IUPAC name in which name of the alkane group followed by amine name is given.
The length of the chain which is having more number of carbon atoms is selected as the parent or main chain. Other chains are considered as substituents to the main chain. Position of the substituents should be included in the name. If one, two, three, four, five, six, etc carbons are activating as the main chain in IUPAC system, then the name of the compound comes as methane, ethane, propane, butane, pentane, hexane, etc. which are the name of alkanes. If one, two, three, four, five, six, etc carbons are activating as the main chain in general name method, then the name of the compound comes as methyl, ethyl, propyl, butyl, pentyl, hexyl, etc. which are the name of alkyl groups. If substituent groups are attached to nitrogen atom as in the case of tertiary or secondary amines, the name is given as N-alkyl name of the substituent.
If any configuration is present in the compound, that should be assigned to it while writing the name. If the compound contains heavier groups on the same side, it gets (Z)-configuration. If they are on the opposite directions, (E)-configurations result.
If a carbon has four different groups attached to it, that carbon shows a chirality nature. If that chiral carbon rotates the plane polarized light into a clockwise direction, it gets (R)-isomer. If that carbon rotates the plane polarized light into a counter-clockwise direction, it gets (S)-isomer.
To find: Categorize the number of alkyl groups attached to nitrogen atom
In the given compound (d), only one alkyl group is attached to nitrogen atom. Therefore, it belongs to primary amine.
Decide the given name which is in general name method or IUPAC name method
There is only one alkyl group present in the given name. It is benzyl group. So, simple general name system is followed. If phenyl group is attached to methylene group, it is called benzyl group.
Locate the substituents and draw the corresponding structure for the given name
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Chapter 22 Solutions
EBK ORGANIC CHEMISTRY-STUD.SOLNS.MAN+SG
- Would the following organic synthesis occur in one step? Add any missing products, required catalysts, inorganic reagents, and other important conditions. Please include a detailed explanation and drawings showing how the reaction may occur in one step.arrow_forwardBelow is the SN1 reaction of (S)-3-chlorocyclohexene and hydroxide (OH). Draw the missing curved arrows, lone pairs of electrons, and nonzero formal charges. In the third box, draw the two enantiomeric products that will be produced. 5th attempt Please draw all four bonds at chiral centers. Draw the two enantiomeric products that will be produced. Draw in any hydrogen at chiral centers. 1000 4th attempt Feedback Please draw all four bonds at chiral centers. 8. R5 HO: See Periodic Table See Hint H Cl Br Jid See Periodic Table See Hintarrow_forwardShow that a molecule with configuration π4 has a cylindrically symmetric electron distribution. Hint: Let the π orbitals be equal to xf and yf, where f is a function that depends only on the distance from the internuclear axis.arrow_forward
- (a) Verify that the lattice energies of the alkali metal iodides are inversely proportional to the distances between the ions in MI (M = alkali metal) by plotting the lattice energies given below against the internuclear distances dMI. Is the correlation good? Would a better fit be obtained by plotting the lattice energies as a function of (1 — d*/d)/d, as theoretically suggested, with d* = 34.5 pm? You must use a standard graphing program to plot the graph. It generates an equation for the line and calculates a correlation coefficient. (b) From the graph obtained in (a), estimate the lattice energy of silver iodide. (c) Compare the results of (b) with the experimental value of 886 kJ/mol. If they do not agree, explain the deviation.arrow_forwardCan I please get help with #3 & 4? Thanks you so much!arrow_forwardA solution consisting of 0.200 mol methylbenzene, C,H,CH,, in 500. g of nitrobenzene, CH,NO₂, freezes at 3.2°C. Pure nitrobenzene freezes at 6.0°C. The molal freezing point constant of nitrobenzene is _ °C/m. a) 2.8 b) 3.2 c) 5.6 d) 7.0 e) 14.0arrow_forward
- Below is the SN1 reaction of (S)-3-chlorocyclohexene and hydroxide ("OH). Draw the missing curved arrows, lone pairs of electrons, and nonzero formal charges. In the third box, draw the two enantiomeric products that will be produced. 2nd attempt Please draw all four bonds at chiral centers. 0 D Draw the missing curved arrow notation. Add lone pairs of electrons and nonzero formal charges. + 노 V 1st attempt Feedback Please draw all four bonds at chiral centers. See Periodic Table See Hint F P 41 H Br See Periodic Table See Hint H Larrow_forwardHow close are the Mulliken and Pauling electronegativity scales? (a) Now that the ionization energies and electron affinities have been defined, calculate the Mulliken and Pauling electronegativities for C, N, O and F. Compare them. (Make the necessary adjustments to the values, such as dividing the ionization energies and electron affinities by 230kj/mol) (b) Plot both sets of electronegativities against atomic number (use the same graph). (c) Which scale depends most consistently on position in the Periodic Table?arrow_forwardBelow is the SN2 reaction between 2-bromopropane and iodide (I). Draw the mechanism arrows in the first box to reflect electron movements. In both boxes, add lone pairs of electrons and nonzero formal charges. 4th attempt Feedback 3rd attempt Feedback 1 -Br H :Bri :Br: ili See Periodic Table See Hint ini See Periodic Table See Hintarrow_forward
- When 4-chloro-1-butanol is placed in sodium hydride, a cyclization reaction occurs. 3rd attempt 2 HO NaH CI D Draw the curved arrow notation to form the intermediate. 4 2 H₂ See Periodic Table See Hint =arrow_forwardSketch, qualitatively, the potential energy curves of the N-N bond of N2H4, N2 and N3- graph. Explain why the energy at the minimum of each curve is not the same.arrow_forward(a) Show that the lattice energies are inversely proportional to the distance between ions in MX (M = alkali metal, X = halide ions) by plotting the lattice energies of KF, KCl, and KI against the internuclear distances, dMX. The lattice energies of KF, KCl, and KI are 826, 717, and 645 kJ/mol, respectively. Does the correlation obtained correlate well? You will need to use a standard graphing program to construct the graph (such as a spreadsheet program). It will generate an equation for the line and calculate a correlation coefficient. (b) Estimate the lattice energy of KBr from your graph. (c) Find an experimental value for the lattice energy of KBr in the literature, and compare this value with the one calculated in (b). Do they agree?arrow_forward
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