ORGANIC CHEMISTRY-ETEXT REG ACCESS
ORGANIC CHEMISTRY-ETEXT REG ACCESS
12th Edition
ISBN: 9781119308362
Author: Solomons
Publisher: WILEY
bartleby

Concept explainers

Question
Book Icon
Chapter 22, Problem 35P
Interpretation Introduction

Interpretation:

The distinguishing tests for the pair of given compounds are to be determined.

Concept introduction:

舧 Chair conformations: It is the most stable conformation, which accurately shows the spatial arrangement of atoms.

舧 Equatorial bonds are parallel to the average plane of the ring, while axial bonds are perpendicular to the average plane of the ring.

舧 The conformation having bonds at the equatorial positions are more stable than those with bonds at the axial position.

舧 On flipping the cyclohexane ring, axial bonds become equatorial bonds and equatorial bonds becomes axial bond.

舧 Bulkier group acquires equatorial positions to form stable conformer due to steric factors.

舧 The most stable configuration of aldopyranoses is when the CH2OH group exists in equatorial conformation.

舧 Stereochemistry: The equatorial orientation refers to the spatial arrangement of CH2OH group at C-2 in the same plane, and the axial orientation refers to the spatial arrangement of CH2OH group at C-2 along the axis.

舧 The anomeric effect is lowest for sugars with equatorial orientation, which results in lower energetic state, and consequently this type of orientation confers higher stability.

舧 The anomeric effect is highest for sugars with axial orientation, which results in higher energetic state, and consequently this type of orientation confers lower stability.

舧 A carbohydrate is a biomolecule consisting of carbon (C), hydrogen (H) and oxygen (O) atoms, usually with a hydrogen-oxygen atom ratio of 2:1

HNO3 is an oxidizing agent.

舧 Carbohydrates are oxidized by HNO3 to give aldaric acid as a product.

舧 Aldaric acids are carbohydrates having two carboxylic acids. They are formed due to oxidation reaction of aldoses with dilute HNO3 and their general reaction can be represented as:

ORGANIC CHEMISTRY-ETEXT REG ACCESS     , Chapter 22, Problem 35P , additional homework tip  1

舧 Monosaccharides containing six carbon atoms and an aldehyde group are called aldohexoses.

舧 Alditols are compounds produced from aldoses or ketoses on reduction with certain reagents such as sodium borohydride (NaBH4) and hydrogen along with a catalyst.

ORGANIC CHEMISTRY-ETEXT REG ACCESS     , Chapter 22, Problem 35P , additional homework tip  2

舧 Compounds formed by the reaction of reducing sugars with excess of phenyl hydrazine are called osazones. Osazones are products of oxidation and are produced by all reducing sugars.

ORGANIC CHEMISTRY-ETEXT REG ACCESS     , Chapter 22, Problem 35P , additional homework tip  3

舧 Fischer projection is a way of representing the structural formulae of compounds through cross formulation of their open chain structures.

舧. Bromine water is an effective reagent that selectively oxidizes the CHO group to COOH moiety, and thereby, converts an aldose into aldonic acid.

ORGANIC CHEMISTRY-ETEXT REG ACCESS     , Chapter 22, Problem 35P , additional homework tip  4

Tollen’s ([Ag+(NH3)2OH])/Benedict’s (alkaline solution with cupric citrate complex ion) test is a qualitative test to distinguish aldehydes from ketones. These reagents are used to determine the presence of carboxyl groups; both aromatic and non-aromatic aldehydes and α hydroxy ketones. All reducing sugars (having hemiacetal group) give positive Tollen’s / Benedict’s test whereas non-reducing sugars (having acetal groups) do not. However, reactions with these reagents are not that easy because these tests require alkaline solutions, which can induce complex chemical alterations in the sugars.

舧 Compounds that have plane of symmetry tend to form meso compounds. A meso form arises when the two stereoisomers produce superimposable (achiral) images, and hence, compounds having meso are optically inactive. Chiral (or non-superimposable) molecules are optically active.

HIO4 is known as the periodic acid. It is used for oxidative cleavage of compounds having hydroxyl groups on adjacent atoms to produce respective aldehydes, ketones and acids.

Blurred answer
Students have asked these similar questions
Show mechanism..don't give Ai generated solution
Don't used Ai solution
Show work. Don't give Ai generated solution
Knowledge Booster
Background pattern image
Chemistry
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
General, Organic, and Biological Chemistry
Chemistry
ISBN:9781285853918
Author:H. Stephen Stoker
Publisher:Cengage Learning
Text book image
Organic And Biological Chemistry
Chemistry
ISBN:9781305081079
Author:STOKER, H. Stephen (howard Stephen)
Publisher:Cengage Learning,
Text book image
Organic Chemistry
Chemistry
ISBN:9781305080485
Author:John E. McMurry
Publisher:Cengage Learning
Text book image
Chemistry for Today: General, Organic, and Bioche...
Chemistry
ISBN:9781305960060
Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. Hansen
Publisher:Cengage Learning
Text book image
Organic Chemistry
Chemistry
ISBN:9781305580350
Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
Publisher:Cengage Learning