Explanation Given data: The given lower temperature ( T L ) is 20 ° C . Resistance of the thermistor at lower temperature ( R L ) is 10.0 k Ω . The given higher temperature ( T H ) is 30 ° C . Potential difference applied to the thermistor ( Δ V ) is 1.2 V. The change in the current from lower temperature to the higher temperature is given as 30 μ A . Therefore, write the expression as follows. I H − I L = 30 μ A (1) Here, I L is the current at lower temperature, and I H is the current at higher temperature. Formula used: Refer to the equation (22.8) in the textbook and write the expression for current in the thermistor circuit as follows. I = Δ V R (2) Here, Δ V is the potential difference applied to the thermistor circuit, and R is the resistance of the thermistor. Explanation: Modify the expression in equation (2) for the current at the lower temperature as follows. I L = Δ V R L (3) Modify the expression in equation (2) for the current at the higher temperature as follows. I H = Δ V R H (4) From equations (3), and (4), substitute ( Δ V R L ) for I L , and ( Δ V R H ) for I H in equation (1), Δ V R H − Δ V R L = 30 μ A Rearrange the expression to find the resistance of the thermistor at the higher temperature as follows

MODIFIED MASTERING COLLEGE PHYSICS 18WK.

4th Edition

ISBN: 9780136782216

Author: Knight

Publisher: PEARSON

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Chapter 22, Problem 22P

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To find: The thermistor’s resistance at 30°C.

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Chapter 22, Problem 21P

Chapter 22, Problem 23P

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Chapter 22 Solutions

MODIFIED MASTERING COLLEGE PHYSICS 18WK.

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The thermistor’s resistance at 30 ° C .

To find: The thermistor’s resistance at 30°C.

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Chapter 22 Solutions