
Concept explainers
(a)
Interpretation:
Preparation methods of metal chlorides have to be given.
Concept introduction:
Direct combination: In this method, metals directly reacts with molecular chlorine and produces metal chlorides.
To give: The preparation of metal chloride by direct combination method
(b)
Concept introduction:
Metals with acids: In this method, metals react with acids and produces metal chlorides.
To give: The preparation of metal chloride by the reaction of metals with acids
(c)
Concept introduction:
Acid-base neutralization: In this method, metal chlorides are prepared by the neutralization reaction of acids with bases (metal hydroxides).
To give: The preparation of metal chloride by acid – base neutralization reaction
(d)
Concept introduction:
Metal carbonate with hydrochloric acid: In this method, metal chlorides are prepared by the reaction of metal carbonates with acids.
To give: The preparation of metal chloride by the reaction of metal carbonate with hydrochloric acid
(e)
Concept introduction:
Precipitation reaction: In this method, insoluble solid (precipitate) formed by the reaction of cations with anions in solution phase.
To give: The preparation of metal chloride by precipitation reaction method

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Chapter 22 Solutions
Chemistry
- H-Br Energy 1) Draw the step-by-step mechanism by which 3-methylbut-1-ene is converted into 2-bromo-2-methylbutane. 2) Sketch a reaction coordinate diagram that shows how the internal energy (Y- axis) of the reacting species change from reactants to intermediate(s) to product. Brarrow_forward2. Draw the missing structure(s) in each of the following reactions. The missing structure(s) can be a starting material or the major reaction product(s). C5H10 H-CI CH2Cl2 CIarrow_forwardDraw the products of the stronger acid protonating the other reactant. དའི་སྐད”“ H3C OH H3C CH CH3 KEq Product acid Product basearrow_forward
- Draw the products of the stronger acid protonating the other reactant. H3C NH2 NH2 KEq H3C-CH₂ 1. Product acid Product basearrow_forwardWhat alkene or alkyne yields the following products after oxidative cleavage with ozone? Click the "draw structure" button to launch the drawing utility. draw structure ... andarrow_forwardDraw the products of the stronger acid protonating the other reactant. H3C-C=C-4 NH2 KEq CH H3C `CH3 Product acid Product basearrow_forward
- 2. Draw the missing structure(s) in each of the following reactions. The missing structure(s) can be a starting material or the major reaction product(s). C5H10 Br H-Br CH2Cl2 + enant.arrow_forwardDraw the products of the stronger acid protonating the other reactant. KEq H₂C-O-H H3C OH Product acid Product basearrow_forwardDraw the products of the stronger acid protonating the other reactant. OH KEq CH H3C H3C `CH3 Product acid Product basearrow_forward
- 2. Draw the missing structure(s) in each of the following reactions. The missing structure(s) can be a starting material or the major reaction product(s). Ph H-I CH2Cl2arrow_forward3 attempts left Check my work Draw the products formed in the following oxidative cleavage. [1] 03 [2] H₂O draw structure ... lower mass product draw structure ... higher mass productarrow_forward2. Draw the missing structure(s) in each of the following reactions. The missing structure(s) can be a starting material or the major reaction product(s). H-Br CH2Cl2arrow_forward
- Chemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage LearningChemistry for Engineering StudentsChemistryISBN:9781285199023Author:Lawrence S. Brown, Tom HolmePublisher:Cengage Learning

