
Concept explainers
Interpretation:
The special stability of chelates has to be explained with an example.
Concept Introduction:
Entropy means “randomness or disorderliness”. Entropy is a
The term free energy refers to available energy in the system to do work. Lesser the energy of the system more will be the stability of the system. It is denoted by ‘G’ and change in free energy is represented as
Enthalpy of the system refers to heat content of the system and it is denoted by ‘H’. Change in enthalpy is denoted as
These three thermodynamic terms are related as,

Want to see the full answer?
Check out a sample textbook solution
Chapter 22 Solutions
Lab Manual Experiments in General Chemistry
- Calculate the pH of 0.015 M HCl.arrow_forwardCalculate the pH of 0.450 M KOH.arrow_forwardWhich does NOT describe a mole? A. a unit used to count particles directly, B. Avogadro’s number of molecules of a compound, C. the number of atoms in exactly 12 g of pure C-12, D. the SI unit for the amount of a substancearrow_forward
- 5 What would the complete ionic reaction be if aqueous solutions of potassium sulfate and barium acetate were mixed? ed of Select one: O a 2 K SO4 + Ba2 +2 C₂H3O21 K+SO4 + Ba2+ + 2 C2H3O21 K+SO42 + Ba2 +2 C2H3O2 BaSO4 +2 K+ + 2 C2H3O estion Ob. O c. Od. 2 K SO4 +Ba2 +2 C₂H₂O₂ BaSO4 + K+ + 2 C2H3O BaSO4 + K + 2 C2H301 →Ba² +SO42 +2 KC2H3O s pagearrow_forward(28 pts.) 7. Propose a synthesis for each of the following transformations. You must include the reagents and product(s) for each step to receive full credit. The number of steps is provided. (OC 4) 4 steps 4 steps OH b.arrow_forwardLTS Solid: AT=Te-Ti Trial 1 Trial 2 Trial 3 Average ΔΗ Mass water, g 24.096 23.976 23.975 Moles of solid, mol 0.01763 001767 0101781 Temp. change, °C 2.9°C 11700 2.0°C Heat of reaction, J -292.37J -170.473 -193.26J AH, kJ/mole 16.58K 9.647 kJ 10.85 kr 16.58K59.64701 KJ mol 12.35k Minimum AS, J/mol K 41.582 mol-k Remember: q = mCsAT (m = mass of water, Cs=4.184J/g°C) & qsin =-qrxn & Show your calculations for: AH in J and then in kJ/mole for Trial 1: qa (24.0969)(4.1845/g) (-2.9°C)=-292.37J qsin = qrxn = 292.35 292.37J AH in J = 292.375 0.2923kJ 0.01763m01 =1.65×107 AH in kJ/mol = = 16.58K 0.01763mol mol qrx Minimum AS in J/mol K (Hint: use the average initial temperature of the three trials, con Kelvin.) AS=AHIT (1.65×10(9.64×103) + (1.0 Jimaiarrow_forward
- Chemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage LearningChemistry for Engineering StudentsChemistryISBN:9781337398909Author:Lawrence S. Brown, Tom HolmePublisher:Cengage LearningChemistry & Chemical ReactivityChemistryISBN:9781337399074Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage Learning
- Chemistry & Chemical ReactivityChemistryISBN:9781133949640Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage LearningChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistry: An Atoms First ApproachChemistryISBN:9781305079243Author:Steven S. Zumdahl, Susan A. ZumdahlPublisher:Cengage Learning





