Chapter 22, Problem 22.12P

Interpretation Introduction

(a)

Interpretation: The products formed from the treatment of benzoyl chloride $\left({\text{C}}_{\text{6}}{\text{H}}_{\text{5}}\text{COCl}\right)$ with ${\text{H}}_{\text{2}}\text{O}$, pyridine are to be drawn.

Concept introduction: The nucleophilic acyl substitution of acid chlorides involves two steps; that is the addition of nucleophile to carbonyl group, followed by the elimination of leaving group to give nucleophilic substitution product.

Interpretation Introduction

(b)

Interpretation: The products formed from the treatment of benzoyl chloride $\left({\text{C}}_{\text{6}}{\text{H}}_{\text{5}}\text{COCl}\right)$ with ${\text{CH}}_{\text{3}}{\text{COO}}^{-}$ are to be drawn.

Concept introduction: The nucleophilic acyl substitution of acid chlorides involves two steps; that is the addition of nucleophile to carbonyl group, followed by the elimination of leaving group to give nucleophilic substitution product.

Interpretation Introduction

(c)

Interpretation: The products formed from the treatment of benzoyl chloride $\left({\text{C}}_{\text{6}}{\text{H}}_{\text{5}}\text{COCl}\right)$ with ${\text{NH}}_{\text{3}}$ (excess) are to be drawn.

Concept introduction: The nucleophilic acyl substitution of acid chlorides involves two steps; that is the addition of nucleophile to carbonyl group, followed by the elimination of leaving group to give nucleophilic substitution product.

Interpretation Introduction

(d)

Interpretation: The products formed from the treatment of benzoyl chloride $\left({\text{C}}_{\text{6}}{\text{H}}_{\text{5}}\text{COCl}\right)$ with ${\left({\text{CH}}_{\text{3}}\right)}_{\text{2}}\text{NH}$ (excess) are to be drawn.

Concept introduction: The nucleophilic acyl substitution of acid chlorides involves two steps; that is the addition of nucleophile to carbonyl group, followed by the elimination of leaving group to give nucleophilic substitution product.