EBK PRACTICE OF STATISTICS IN THE LIFE
EBK PRACTICE OF STATISTICS IN THE LIFE
4th Edition
ISBN: 9781319067496
Author: BALDI
Publisher: VST
Question
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Chapter 22, Problem 22.11AYK

(a)

To determine

To find:

The study provides evidence that among men with a neurodegenerative disorder for the given data.

(a)

Expert Solution
Check Mark

Answer to Problem 22.11AYK

  χ2=39.35

Explanation of Solution

Given:

Participated in a contact sport =66men

None of the control men =132

Concept used:

Formula

  p=xn

Significance level

  α=1confidenceα=10.95

Calculation:

Parameter p= sample proportion

The best point of estimate of p is sample proportion

Since the sample size are large.

The condition for the two samples z test are met.

The population distribution is normal.

Draw the first table

CTEContact sportsNoContact sports Total

    Observed 21223
    Expected 7.6715.3323.00
    O-E13.3313.330.00
    (O-E)2E23.1911.5934.78

Draw the second table

No CTEContact sportsNoContact sports Total

    Observed 45130175
    Expected 58.33116.67175.00
    O-E13.3313.330.00
    (O-E)2E3.051.524.57

Draw the third table

TotalContact sportsNoContact sports Total

    Observed 66132198
    Expected 66.00132.00198.00
    O-E0.000.000.00
    (O-E)2E26.2413.1239.35

Test statistic

  X Is a random variable

The null hypothesis

  χ2={(OiEi)2Ei}χ2=39.35

(b)

To determine

To explain:

The chi-square test is nevertheless appropriate for the given data.

(b)

Expert Solution
Check Mark

Explanation of Solution

Given:

Participated in a contact sport =66men

None of the control men =132

Concept used:

Formula

  p=xn

Significance level

  α=1confidenceα=10.95

Calculation:

Parameter p= sample proportion

The best point of estimate of p is sample proportion

Since the sample size are large.

The condition for the two samples z test are met.

The population distribution is normal.

Draw the first table

CTEContact sportsNoContact sports Total

    Observed 21223
    Expected 7.6715.3323.00
    O-E13.3313.330.00
    (O-E)2E23.1911.5934.78

Draw the second table

No CTEContact sportsNoContact sports Total

    Observed 45130175
    Expected 58.33116.67175.00
    O-E13.3313.330.00
    (O-E)2E3.051.524.57

Draw the third table

TotalContact sportsNoContact sports Total

    Observed 66132198
    Expected 66.00132.00198.00
    O-E0.000.000.00
    (O-E)2E26.2413.1239.35

Test statistic

  X Is a random variable

The null hypothesis

  χ2={(OiEi)2Ei}χ2=39.35

Significance level

  α=1confidenceα=10.95α=0.05

Since p Value is greater than 0.05 significance level.

So the hypothesis is fail to reject null hypothesis H0

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