LIFE: THE SCIENCE OF BIOLOGY
LIFE: THE SCIENCE OF BIOLOGY
11th Edition
ISBN: 9781319145125
Author: Sadava
Publisher: MAC HIGHER
bartleby

Videos

Question
Book Icon
Chapter 22, Problem 1Q
Summary Introduction

To review:

On the basis of the given data, we are required to show the patterns of the hydrocarbons which are consistent with reinforcement.

Given:

The graph given below shows the hydrocarbon concentration in the cuticle of allopatric and sympatric species of three species of Drosophila.

LIFE: THE SCIENCE OF BIOLOGY, Chapter 22, Problem 1Q

Introduction:

A study was conducted on the east coast of Australia, where two species of Drosophila, D. serrata and D. birchii, coexist and breed to produce hybrids. The hydrocarbon concentration in the allopatric and sympatric species was estimated to see the differences in them. The reinforcement mechanism was assumed to be the reason for such differences in the species.

Expert Solution & Answer
Check Mark

Explanation of Solution

Reinforcement theory for speciation was first proposed by Wallace, where he suggested that reproductive isolation between species take place as a result of natural selection. This process prevents the production of hybrids, which have low fitness that the nonhybrids.

After studying the data given, the hydrocarbon 2 show a pattern, which is consistent with reinforcement. For reinforcement to be consistent, one needs to check the difference between the sympatric population and the other species, which should be greater than the difference between the allopatric populations and other species.

In case a barrier in gene flow is established, the reproduction isolation will begin by genetic divergence. Due to this, there are differences accumulated in the lineages. This reduces the probability of individuals mating with each other successfully, whenever they come into contact.

In case this isolation fails when the species come into contact, then some hybridization is bound to occur. The selection of the species will favor the parents. Due to this, the selection will result in the reinforcement of the mechanisms that prevent hybridization.

Conclusion

Therefore, it can be concluded that hydrocarbon 2 shows the correct pattern of reinforcement.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
You are studying the effect of directional selection on body height in three populations (graphs a, b, and c below). (a) What is the selection differential? Show your calculation. (2 pts) (b) Which population has the highest narrow sense heritability for height? Explain your answer. (2 pts) (c) If you examined the offspring in the next generation in each population, which population would have the highest mean height? Why? (2 pts) (a) Midoffspring height (average height of offspring) Short Short Short Short (c) Short (b) Short Tall Short Tall Short Short Tall Midparent height (average height of Mean of population = 65 inches Mean of breading parents = 70 inches Mean of population = 65 inches Mean of breading parents = 70 inches Mean of population = 65 inches Mean of breading parents = 70 inches
P You are studying a population of 100 flowers that has two alleles at a locus for flower color, blue (B) and green (G). There are 15 individuals with the BB genotype, 70 individuals with the BG genotype, and 15 individuals with the GG genotype. (a) What are the allele frequencies of B and G in the starting population? Show your calculations. (2 pts) (b) Is this population in Hardy-Weinberg equilibrium? Show your calculations. (3 pts) 12pt v Paragraph BIU UA AV & VT2V f CO V
In a natural population of outbreeding plants, the variance of the total number of seeds per plant is 16. From the natural population, 20 plants are taken into the laboratory and developed into separate true-breeding lines by self- fertilization-with selection for high, low, or medium number of seeds-for 10 generations. The average variance in the tenth generation in each of the 20 sets is about equal and averages 5.8 across all the sets. Estimate the broad-sense heritability for seed number in this population. (4 pts) 12pt v Paragraph BIUA V V T² v B ① O words
Knowledge Booster
Background pattern image
Biology
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
Concepts of Biology
Biology
ISBN:9781938168116
Author:Samantha Fowler, Rebecca Roush, James Wise
Publisher:OpenStax College
Text book image
Case Studies In Health Information Management
Biology
ISBN:9781337676908
Author:SCHNERING
Publisher:Cengage
Text book image
Essentials Health Info Management Principles/Prac...
Health & Nutrition
ISBN:9780357191651
Author:Bowie
Publisher:Cengage
Text book image
Biology (MindTap Course List)
Biology
ISBN:9781337392938
Author:Eldra Solomon, Charles Martin, Diana W. Martin, Linda R. Berg
Publisher:Cengage Learning
Text book image
Principles Of Radiographic Imaging: An Art And A ...
Health & Nutrition
ISBN:9781337711067
Author:Richard R. Carlton, Arlene M. Adler, Vesna Balac
Publisher:Cengage Learning
Text book image
Basic Clinical Laboratory Techniques 6E
Biology
ISBN:9781133893943
Author:ESTRIDGE
Publisher:Cengage
Introduction to the NIOSH Manual of Analytical Methods Fifth edition; Author: Centers for Disease Control and Prevention (CDC);https://www.youtube.com/watch?v=B5rUrKLMoas;License: Standard Youtube License