(a) Answer (a) The final answer of first expression 15 ( 20 + l ) Explanation Given information: The length of living room 20 ft The length of game room l ft Breadth of room 15 ft Calculation : First of all we find the length of room l = ( 20 + l ) f t and the breadth is b = 15 f t This is in the shape of rectangle now find the area of rectangle ABCD. Area of rectangle ABCD = l × b Area of rectangle ABCD = ( 20 + l ) 15 s q . f t . (b) To determine To calculate : Write a second expression for the total area by finding the area of each room separately and then adding the two areas. Answer (b) The total area is ( 300 + 15 l ) ft. Explanation Calculation : Now when we solve the separately to find the area then now the find area of both rectangle ABCD and EFGH First of all find the area of rectangle ABCD Hence, Area of rectangle ABCD = 20 × 15 = 300 f t Now, Area of rectangle EFGH = 15 × l = 15 l ft Now add the both area of find total area Total area of rectangle = area of rectangle ABCD + area of rectangle EFGH Total area = ( 300 + 15 l ) sq. ft (c) To determine To Show: The expression from parts (a) and (b) are equivalent. Explanation Calculation : (c) Both the expression in above two part are equivalent First ( 20 + l ) 15 = 20 ( 15 ) + l ( 15 ) ( 20 + l ) 15 = 300 + 15 l Hence both are equivalent

Holt Mcdougal Larson Pre-algebra: Student Edition 2012

1st Edition

ISBN: 9780547587776

Author: HOLT MCDOUGAL

Publisher: HOLT MCDOUGAL

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Question

Chapter 2.2, Problem 11E

(a)

To determine

To write: The expression for the total area of both rooms.

(a)

Expert Solution

Answer to Problem 11E

(a) The final answer of first expression 15(20+l)

Explanation of Solution

Given information:

The length of living room 20 ft

The length of game room l ft

Breadth of room 15 ft

Calculation:

First of all we find the length of room l=(20+l)ft and the breadth is b=15 ft

This is in the shape of rectangle now find the area of rectangle ABCD.

Holt Mcdougal Larson Pre-algebra: Student Edition 2012, Chapter 2.2, Problem 11E , additional homework tip 1

Area of rectangle ABCD = l×b

Area of rectangle ABCD = (20+l)15 sq. ft .

(b)

To determine

To calculate:

Write a second expression for the total area by finding the area of each room separately and then adding the two areas.

(b)

Expert Solution

Answer to Problem 11E

(b) The total area is (300+15 l) ft.

Explanation of Solution

Calculation:

Now when we solve the separately to find the area then now the find area of both rectangle ABCD and EFGH

Holt Mcdougal Larson Pre-algebra: Student Edition 2012, Chapter 2.2, Problem 11E , additional homework tip 2

First of all find the area of rectangle ABCD

Hence, Area of rectangle ABCD

=20×15

=300 ft

Now, Area of rectangle EFGH

=15×l

=15 l ft

Now add the both area of find total area

Total area of rectangle = area of rectangle ABCD + area of rectangle EFGH

Total area = (300+15 l) sq. ft

(c)

To determine

To Show: The expression from parts (a) and (b) are equivalent.

(c)

Expert Solution

Explanation of Solution

Calculation:

(c)

Both the expression in above two part are equivalent

First

(20+l)15=20(15)+l(15)

(20+l)15=300+15l

Hence both are equivalent

Chapter 2.2, Problem 10E

Chapter 2.2, Problem 12E

Chapter 2 Solutions

Holt Mcdougal Larson Pre-algebra: Student Edition 2012

Ch. 2.1 - Prob. 1PSQ Ch. 2.1 - Prob. 2PSQ Ch. 2.1 - Prob. 3PSQ Ch. 2.1 - Prob. 4PSQ Ch. 2.1 - Prob. 5PSQ Ch. 2.1 - Prob. 6PSQ Ch. 2.1 - Prob. 7PSQ Ch. 2.1 - Prob. 8PSQ Ch. 2.1 - Prob. 9PSQ Ch. 2.1 - Prob. 10PSQ

Ch. 2.1 - Prob. 11PSQ Ch. 2.1 - Prob. 1C Ch. 2.1 - Prob. 2C Ch. 2.1 - Prob. 3C Ch. 2.1 - Prob. 4C Ch. 2.1 - Prob. 5C Ch. 2.1 - Prob. 6C Ch. 2.1 - Prob. 7C Ch. 2.1 - Prob. 8C Ch. 2.1 - Prob. 9C Ch. 2.1 - Prob. 10C Ch. 2.1 - Prob. 1E Ch. 2.1 - Prob. 2E Ch. 2.1 - Prob. 3E Ch. 2.1 - Prob. 4E Ch. 2.1 - Prob. 5E Ch. 2.1 - Prob. 6E Ch. 2.1 - Prob. 7E Ch. 2.1 - Prob. 8E Ch. 2.1 - Prob. 9E Ch. 2.1 - Prob. 10E Ch. 2.1 - Prob. 11E Ch. 2.1 - Prob. 12E Ch. 2.1 - Prob. 13E Ch. 2.1 - Prob. 14E Ch. 2.1 - Prob. 15E Ch. 2.1 - Prob. 16E Ch. 2.1 - Prob. 17E Ch. 2.1 - Prob. 18E Ch. 2.1 - Prob. 19E Ch. 2.1 - Prob. 20E Ch. 2.1 - Prob. 21E Ch. 2.1 - Prob. 22E Ch. 2.1 - Prob. 23E Ch. 2.1 - Prob. 24E Ch. 2.1 - Prob. 25E Ch. 2.1 - Prob. 26E Ch. 2.1 - Prob. 27E Ch. 2.1 - Prob. 28E Ch. 2.1 - Prob. 29E Ch. 2.1 - Prob. 30E Ch. 2.1 - Prob. 31E Ch. 2.1 - Prob. 32E Ch. 2.1 - Prob. 33E Ch. 2.1 - Prob. 34E Ch. 2.1 - Prob. 35E Ch. 2.1 - Prob. 36E Ch. 2.1 - Prob. 37E Ch. 2.1 - Prob. 38E Ch. 2.1 - Prob. 39E Ch. 2.1 - Prob. 40E Ch. 2.1 - 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