Refer to the Integrative Example on page 1082. Assume that the disproportionation of [ S 2 O 3 2 − ] is no longer spontaneous when the partial pressure of S O z ( g ) above a solution with [ S 2 O 3 2 − ] = 1 M has dropped 1 × 10 − 6 a t m . Show that this condition is reached while the solution is still acidic.
Refer to the Integrative Example on page 1082. Assume that the disproportionation of [ S 2 O 3 2 − ] is no longer spontaneous when the partial pressure of S O z ( g ) above a solution with [ S 2 O 3 2 − ] = 1 M has dropped 1 × 10 − 6 a t m . Show that this condition is reached while the solution is still acidic.
Solution Summary: The author explains the term electrode potential, which refers to the potential difference between the electrolyte and the electrode in an electrochemical cell.
Refer to the Integrative Example on page 1082. Assume that the disproportionation of
[
S
2
O
3
2
−
]
is no longer spontaneous when the partial pressure of
S
O
z
(
g
)
above a solution with
[
S
2
O
3
2
−
]
=
1
M
has dropped
1
×
10
−
6
a
t
m
. Show that this condition is reached while the solution is still acidic.
3. Consider the compounds below and determine if they are aromatic, antiaromatic, or
non-aromatic. In case of aromatic or anti-aromatic, please indicate number of I
electrons in the respective systems. (Hint: 1. Not all lone pair electrons were explicitly
drawn and you should be able to tell that the bonding electrons and lone pair electrons
should reside in which hybridized atomic orbital 2. You should consider ring strain-
flexibility and steric repulsion that facilitates adoption of aromaticity or avoidance of anti-
aromaticity)
H H
N
N:
NH2
N
Aromaticity
(Circle)
Aromatic Aromatic Aromatic Aromatic Aromatic
Antiaromatic Antiaromatic Antiaromatic Antiaromatic Antiaromatic
nonaromatic nonaromatic nonaromatic nonaromatic nonaromatic
aromatic TT
electrons
Me
H
Me
Aromaticity
(Circle)
Aromatic Aromatic Aromatic
Aromatic Aromatic
Antiaromatic Antiaromatic Antiaromatic Antiaromatic Antiaromatic
nonaromatic nonaromatic nonaromatic nonaromatic nonaromatic
aromatic πT
electrons
H
HH…
A chemistry graduate student is studying the rate of this reaction:
2 HI (g) →H2(g) +12(g)
She fills a reaction vessel with HI and measures its concentration as the reaction proceeds:
time
(minutes)
[IH]
0
0.800M
1.0
0.301 M
2.0
0.185 M
3.0
0.134M
4.0
0.105 M
Use this data to answer the following questions.
Write the rate law for this reaction.
rate
= 0
Calculate the value of the rate constant k.
k =
Round your answer to 2 significant digits. Also be
sure your answer has the correct unit symbol.
Chapter 22 Solutions
Selected Solutions Manual For General Chemistry: Principles And Modern Applications
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Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell