Explanation Equation used: “ Parabola: The general form of the equation of the parabola in xy -coordinate plane is, ( y − k ) 2 = 4 p ( x − h ) ( axis parallel to x -axis ) ( x − h ) 2 = 4 p ( y − k ) ( axis parallel to y -axis ) where ( h , k ) is the center.” Calculation: The given equation of the curve is, ( y − 2 ) 2 = 4 ( x + 1 ) It is observed from the given curve that, it is a parabola with the axis parallel to the x- axis. The equation of the curve in the x ′ y ′ - system is, y − 2 = y ′ and x + 1 = x ′ ∴ ( y ′ ) 2 = 4 x ′ Using the general equation of parabola, the vertex of the curve is obtained at the origin, that is at ( h , k ) = ( − 1 , 2 )

11th Edition

ISBN: 9780134437705

Author: Washington

Publisher: PEARSON

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Chapter 21.7, Problem 3E

To determine

The type of the curve with the given equation and then to identify it’s center and to sketch the curve.

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Chapter 21.7, Problem 2E

Chapter 21.7, Problem 4E

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Chapter 21 Solutions

Basic Technical Mathematics

Ch. 21.1 - Find the distance between (−2, 6) and (5, −3). Ch. 21.1 - Prob. 2PE Ch. 21.1 - Prob. 1E Ch. 21.1 - Prob. 2E Ch. 21.1 - Prob. 5E Ch. 21.1 - In Exercises 5–14, find the distance between the...Ch. 21.1 - Prob. 7E Ch. 21.1 - Prob. 8E Ch. 21.1 - Prob. 9E Ch. 21.1 - Prob. 10E

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